What does the %*s format specifier mean?
CPrintfFormat SpecifiersC Problem Overview
In some code that I have to maintain, I have seen a format specifier %*s
. Can anybody tell me what this is and why it is used?
An example of its usage is like:
fprintf(outFile, "\n%*s", indent, "");
C Solutions
Solution 1 - C
[It's used to specify, in a dynamic way, what the width of the field is][1]:
> * The width is not specified in the format string, but as an additional > integer value argument preceding the > argument that has to be formatted.
so "indent" specifies how much space to allocate for the string that follows it in the parameter list.
So,
printf("%*s", 5, "");
is the same as
printf("%5s", "");
It's a nice way to put some spaces in your file, avoiding a loop. [1]: http://www.cplusplus.com/reference/clibrary/cstdio/printf/
Solution 2 - C
Don't use "%*s" on a buffer which is not NULL terminated (packed) thinking that it will print only "length" field.
Solution 3 - C
The format specifier %4s outputs a String in a field width of 4—that is, printf displays the value with at least 4 character positions.
If the value to be output is less
than 4 character positions wide, the value is right justified
in the field by default.
If the value is greater
than 4 character positions wide, the field width expands
to accommodate the appropriate number of characters.
To left justify the value, use a negative integer to specify the field width.
References: Java™ How To Program (Early Objects), Tenth Edition
Solution 4 - C
When used in printf and fprintf:
printf("%*s", 4, myValue); is equivalent to printf("%4s", myValue);
It displays the variable with minimum width, rest right-justified spaces. To left-justify the value, use a negative integer.
When used in scanf and sscanf:
/* sscanf example */
#include <stdio.h>
int main ()
{
char sentence []="Rudolph is 12 years old";
char str [20];
int i;
sscanf (sentence,"%s %*s %d",str,&i);
printf ("%s -> %d\n",str,i);
return 0;
}
Output:
Rudolph -> 12
It is used to ignore a string.
Solution 5 - C
* Causes fprintf to pad the output until it is n characters wide, where n is an integer value stored in the a function argument just preceding that represented by the modified type.
printf("%*d", 5, 10) //will result in "10" being printed with a width of 5.
Solution 6 - C
http://www.cplusplus.com/reference/clibrary/cstdio/printf/
> The width is not specified in the format string, but as an additional integer value argument preceding the argument that has to be formatted.
e.g: printf("%*s", 4, myValue);
is equivelant to printf("%4s", myValue);
.