How to printf "unsigned long" in C?
CPrintfLong IntegerUnsignedFormat SpecifiersC Problem Overview
I can never understand how to print unsigned long datatype in C.
Suppose unsigned_foo is an unsigned long, then I try:
printf("%lu\n", unsigned_foo)printf("%du\n", unsigned_foo)printf("%ud\n", unsigned_foo)printf("%ll\n", unsigned_foo)printf("%ld\n", unsigned_foo)printf("%dl\n", unsigned_foo)
And all of them print some kind of -123123123 number instead of unsigned long that I have.
C Solutions
Solution 1 - C
%lu is the correct format for unsigned long. Sounds like there are other issues at play here, such as memory corruption or an uninitialized variable. Perhaps show us a larger picture?
Solution 2 - C
For int %d
For long int %ld
For long long int %lld
For unsigned long long int %llu
Solution 3 - C
%lufor unsigned long%llufor unsigned long long
Solution 4 - C
Out of all the combinations you tried, %ld and %lu are the only ones which are valid printf format specifiers at all. %lu (long unsigned decimal), %lx or %lX (long hex with lowercase or uppercase letters), and %lo (long octal) are the only valid format specifiers for a variable of type unsigned long (of course you can add field width, precision, etc modifiers between the % and the l).
Solution 5 - C
The format is %lu.
Please check about the various other datatypes and their usage in printf here
Solution 6 - C
int main()
{
unsigned long long d;
scanf("%llu",&d);
printf("%llu",d);
getch();
}
This will be helpful . . .
Solution 7 - C
The correct specifier for unsigned long is %lu.
If you are not getting the exact value you are expecting then there may be some problems in your code.
Please copy your code here. Then maybe someone can tell you better what the problem is.