Using the field of an object as a generic Dictionary key

.NetGenericsDictionary

.Net Problem Overview


If I want to use objects as the keys for a Dictionary, what methods will I need to override to make them compare in a specific way?

Say I have a a class which has properties:

class Foo {
    public string Name { get; set; }
    public int FooID { get; set; }

    // elided
} 

And I want to create a:

Dictionary<Foo, List<Stuff>>

I want Foo objects with the same FooID to be considered the same group. Which methods will I need to override in the Foo class?

To summarize: I want to categorize Stuff objects into lists, grouped by Foo objects. Stuff objects will have a FooID to link them to their category.

.Net Solutions


Solution 1 - .Net

By default, the two important methods are GetHashCode() and Equals(). It is important that if two things are equal (Equals() returns true), that they have the same hash-code. For example, you might "return FooID;" as the GetHashCode() if you want that as the match. You can also implement IEquatable<Foo>, but that is optional:

class Foo : IEquatable<Foo> {
    public string Name { get; set;}
    public int FooID {get; set;}

    public override int GetHashCode() {
        return FooID;
    }
    public override bool Equals(object obj) {
        return Equals(obj as Foo);
    }
    public bool Equals(Foo obj) {
        return obj != null && obj.FooID == this.FooID;
    }
}

Finally, another alternative is to provide an IEqualityComparer<T> to do the same.

Solution 2 - .Net

As you want the FooID to be the identifier for the group, you should use that as key in the dictionary instead of the Foo object:

Dictionary<int, List<Stuff>>

If you would use the Foo object as key, you would just implement the GetHashCode and Equals method to only consider the FooID property. The Name property would just be dead weight as far as the Dictionary was concerned, so you would just use Foo as a wrapper for an int.

Therefore it's better to use the FooID value directly, and then you don't have to implement anything as the Dictionary already supports using an int as a key.

Edit:
If you want to use the Foo class as key anyway, the IEqualityComparer<Foo> is easy to implement:

public class FooEqualityComparer : IEqualityComparer<Foo> {
   public int GetHashCode(Foo foo) { return foo.FooID.GetHashCode(); }
   public bool Equals(Foo foo1, Foo foo2) { return foo1.FooID == foo2.FooID; }
}

Usage:

Dictionary<Foo, List<Stuff>> dict = new Dictionary<Foo, List<Stuff>>(new FooEqualityComparer());

Solution 3 - .Net

For Foo you will need to override object.GetHashCode() and object.Equals()

The dictionary will call GetHashCode() to calculate a hash bucket for each value and Equals to compare whether two Foo's are identical.

Make sure to calculate good hash codes (avoid many equal Foo objects having the same hashcode), but make sure two equals Foos have the same hash code. You might want to start with the Equals-Method and then (in GetHashCode()) xor the hash code of every member you compare in Equals.

public class Foo { 
     public string A;
     public string B;

     override bool Equals(object other) {
          var otherFoo = other as Foo;
          if (otherFoo == null)
             return false;
          return A==otherFoo.A && B ==otherFoo.B;
     }

     override int GetHashCode() {
          return 17 * A.GetHashCode() + B.GetHashCode();
     }
}

Solution 4 - .Net

What about Hashtable class!

Hashtable oMyDic = new Hashtable();
Object oAnyKeyObject = null;
Object oAnyValueObject = null;
oMyDic.Add(oAnyKeyObject, oAnyValueObject);
foreach (DictionaryEntry de in oMyDic)
{
   // Do your job
}

In above way, you can use any object (your class object) as a generic Dictionary key :)

Solution 5 - .Net

I had the same problem. I can now use any object I've tried as a key due to overriding Equals and GetHashCode.

Here is a class that I built with methods to use inside of the overrides of Equals(object obj) and GetHashCode(). I decided to use generics and a hashing algorithm that should be able to cover most objects. Please let me know if you see anything here that doesn't work for some types of object and you have a way to improve it.

public class Equality<T>
{
    public int GetHashCode(T classInstance)
    {
        List<FieldInfo> fields = GetFields();

        unchecked
        {
            int hash = 17;

            foreach (FieldInfo field in fields)
            {
                hash = hash * 397 + field.GetValue(classInstance).GetHashCode();
            }
            return hash;
        }
    }

    public bool Equals(T classInstance, object obj)
    {
        if (ReferenceEquals(null, obj))
        {
            return false;
        }
        if (ReferenceEquals(this, obj))
        {
            return true;
        }
        if (classInstance.GetType() != obj.GetType())
        {
            return false;
        }

        return Equals(classInstance, (T)obj);
    }

    private bool Equals(T classInstance, T otherInstance)
    {
        List<FieldInfo> fields = GetFields();

        foreach (var field in fields)
        {
            if (!field.GetValue(classInstance).Equals(field.GetValue(otherInstance)))
            {
                return false;
            }
        }

        return true;
    }

    private List<FieldInfo> GetFields()
    {
        Type myType = typeof(T);

        List<FieldInfo> fields = myType.GetTypeInfo().DeclaredFields.ToList();
        return fields;
    }
}

Here is how it's used in a class:

public override bool Equals(object obj)
    {
        return new Equality<ClassName>().Equals(this, obj);
    }

    public override int GetHashCode()
    {
        unchecked
        {
            return new Equality<ClassName>().GetHashCode(this);
        }
    }

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionDanaView Question on Stackoverflow
Solution 1 - .NetMarc GravellView Answer on Stackoverflow
Solution 2 - .NetGuffaView Answer on Stackoverflow
Solution 3 - .Netfroh42View Answer on Stackoverflow
Solution 4 - .NetBehzad EbrahimiView Answer on Stackoverflow
Solution 5 - .NetKeith BannerView Answer on Stackoverflow