using css modules how do I define more than one style name

JavascriptCssReactjs

Javascript Problem Overview


I am trying to use multiple classes for an element using css modules. How do I do this?

function Footer( props) {
    const { route } = props;
    return (
        <div className={styles.footer}>
            <div className={styles.description, styles.yellow}>
              <p>this site was created by me</p>
            </div>
            <div className={styles.description}>
              <p>copyright nz</p>
            </div>
        </div>
    );
}

Javascript Solutions


Solution 1 - Javascript

You can add multiple classes using css modules as follows:

className={`${styles.description} ${styles.yellow}`}

e.g.

function Footer( props) {
    return (
        <div className={styles.footer}>
            <div className={`${styles.description} ${styles.yellow}`}>
              <p>this site was created by me</p>
            </div>
        </div>
    );
}

Using react-css-modules you can use normal class name syntax:

<div styleName='description yellow'>

and you specify allowMultiple: true for multiple classes

Solution 2 - Javascript

You can use an array that will be joined with a space. i.e

<div className={[styles.App, styles.bold, styles['d-flex-c']].join(' ')}>

I prefer this to using template literals like @steven iseki suggested because it is easier to add and remove classes without having to wrap them in ${} every single time.

But if you're for some reason adding a lot of classes to a lot of elements you can write a higher order function to make it easier

import React from 'react';
import styles from './Person.module.css';

console.log(styles);
// sample console output =>
// {
//   App: 'App_App__3TjUG',
//   'd-flex-c': 'App_d-flex-c__xpDp1',
// }


// func below returns a function that takes a list of classes as an argument
// and turns it in an array with the spread operator and reduces it into a spaced string

const classLister = styleObject => (...classList) =>
  classList.reduce((list, myClass) => {
    let output = list;
    if (styleObject[myClass]) {
      if (list) output += ' '; // appends a space if list is not empty
      output += styleObject[myClass]; 
      //Above: append 'myClass' from styleObject to the list if it is defined
    }
    return output;
 }, '');

const classes = classLister(styles); 
// this creates a function called classes that takes class names as an argument
// and returns a spaced string of matching classes found in 'styles'

Usage

<div className={classes('App', 'bold', 'd-flex-c')}>

Looks very neat and readable.

When rendered to the DOM it becomes

<div class="App_App__3TjUG App_d-flex-c__xpDp1">
/* Note: the class 'bold' is automatically left out because
   in this example it is not defined in styles.module.css 
   as you can be observe in console.log(styles) */

As expected

And it can be used with conditionals by putting the conditionally generated classes in an array that is used as an argument for classes via ... spread operator

In fact while answering this I decided to publish an npm module because why not.

Get it with

npm install css-module-class-lister

Solution 3 - Javascript

I highly recommend using the classnames package. It's incredibly lightweight (600 bytes minified) and has no dependencies:

import classnames from 'classnames';

Function footer(props) {
  ...
  <div className={classnames(styles.description, styles.yellow)}>
}

It even has the added benefit of being able to conditionally add class names (for example, to append a dark theme class), without having to concatenate strings which can accidentally add an undefined or false class:

  <div className={classnames(styles.description, {styles.darkTheme: props.darkTheme })}>

Solution 4 - Javascript

You should add square brackets to make the classNames an array, and to remove ',' add join().

function Footer( props) {
    const { route } = props;
    return (
        <div className={styles.footer}>
            <div className={ [styles.description, styles.yellow].join(' ') }>
              <p>this site was created by me</p>
            </div>
            <div className={styles.description}>
              <p>copyright nz</p>
            </div>
        </div>
    );
}

Solution 5 - Javascript

As an addition to Yuan-Hao Chiang's answer, the following function makes it even easier to work with:

const classes = (classNames: Array<string> | string): string => classnames((Array.isArray(classNames) ? classNames : classNames.split(' ')).map(x => styles[x]));

What this does is take either an array or a string (which is then split into an array of strings), and returns a final class name (scoped to the current module since it uses the imported styles object of course).

You use it like this:

<div className={classes(['description', 'dark-theme', 'many', 'more', 'class-names'])}>

Or if you prefer, specify a single string (handy in case of using many classes when e.g. using TailwindCSS):

<div className={classes('description dark-theme many more class-names')}>

Solution 6 - Javascript

If you're using the classnames package and you want to apply a style conditionally, you need to use a dynamic property key with brackets, like this:

<div className={classNames(styles.formControl, { [styles.hidden]: hidden })}>
</div>

Solution 7 - Javascript

The best solution for my case is the function bellow. 'Cause with the aruments destructuring I can return the classes with spaces.

export function clx(...classes) {
  return classes.join(" ");
}
// className={clx('border', styles.form, styles.h1, 'classe-4')}
// class="border form_CDE h1_AB"

Solution 8 - Javascript

for combine class names in front of className property, you can use "clsx", using this package is easy

import clsx from 'clsx';
// Strings
clsx('foo', 'bar', 'baz'); // 'foo bar baz'

// Objects
clsx({ foo:true, bar:false, baz:true });// 'foo baz'

you can find the package from this address: https://github.com/lukeed/clsx

Solution 9 - Javascript

Install classnames package to join classNames together

npm install classnames --save

Solution:

import cx from 'classnames';

Function footer(props) {
 ...
 <div className={cx(styles.description, styles.yellow)}>
}

Solution 10 - Javascript

Simply do

<div className={style.smallFont + " " + style.yellowColor}>

string concatination

Solution 11 - Javascript

This can get out of hand quickly:

 className={`${styles.description} ${styles.yellow}`}

I like creating a function that sets the class and call that:

const setClass = (classes: string[]) => {
    return classes.map((className) => styles[className]).join(" ");
  };
<article className={setClass(["student", "student-expand-view-layout"])}>

Solution 12 - Javascript

you can use string concatenation with space(' ') ->

<div className={classes.centerFlexY + ' ' + classes.searchTabs} />

Solution 13 - Javascript

Why you don't define an additional class with the multiple styles? like

div .descyellow{
  background_color: yellow;
  style...
}

and then

<div class="descyellow">

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionNavelaView Question on Stackoverflow
Solution 1 - JavascriptsvnmView Answer on Stackoverflow
Solution 2 - JavascriptDudeonyxView Answer on Stackoverflow
Solution 3 - JavascriptYuan-Hao ChiangView Answer on Stackoverflow
Solution 4 - JavascriptOlcayView Answer on Stackoverflow
Solution 5 - JavascriptSipke SchoorstraView Answer on Stackoverflow
Solution 6 - JavascriptYamo93View Answer on Stackoverflow
Solution 7 - JavascriptAlex Alan NunesView Answer on Stackoverflow
Solution 8 - Javascriptf.jafariView Answer on Stackoverflow
Solution 9 - JavascriptYassine EjjoudView Answer on Stackoverflow
Solution 10 - JavascriptAbrahamView Answer on Stackoverflow
Solution 11 - JavascriptRoyer AdamesView Answer on Stackoverflow
Solution 12 - JavascriptDev AyushView Answer on Stackoverflow
Solution 13 - JavascriptRiesenfaultierView Answer on Stackoverflow