Try redirecting the output to [Out-Null][1]. Like so,

`$key = &amp; &#39;gpg&#39; --decrypt &quot;secret.gpg&quot; --quiet --no-verbose | out-null`


  [1]: http://technet.microsoft.com/en-us/library/hh849716.aspx &quot;Technet&quot;

Try redirecting the output like this:

    $key = &amp; &#39;gpg&#39; --decrypt &quot;secret.gpg&quot; --quiet --no-verbose &gt;$null 2&gt;&amp;1

It is a duplicate of [this question][1], with an answer that contains a time measurement of the different methods.

Conclusion: Use `[void]` or `&gt; $null`.


  [1]: https://stackoverflow.com/questions/5260125/whats-the-better-cleaner-way-to-ignore-output-in-powershell

I&#39;m trying to make a layout like this:

&lt;img src=&quot;http://i.stack.imgur.com/cEDjE.png&quot; width=&quot;300&quot;/&gt;

The problem is that I don&#39;t want the `ListViews` to be scrollable. **I want them to be as high as they need to and make the whole screen be scrollable.** If I set the height of the `ListView` to `wrap_content`, that doesn&#39;t work. The only way to make it work is to set a specific height - but I don&#39;t know how many items will be in the `ListView`.

**I know that I should not put `ListView` inside `ScrollView`** - but I don&#39;t want the `ListView` to be scrollable, just to show all items.

Maybe there is a better way to make it work?


 

Non-scrollable ListView inside ScrollView

I have read so many suggestions about, not putting your customization aka commands in &quot;.profile&quot; file. Rather, create a .bash_profile for yourself and add your alias and etc.

But,when I open the new terminal, if there is only .bash_profile, OS X is not exporting/sourcing the commands mentioned in it. I have to manually source the .bash_profile.

If I create .profile file, on opening a new terminal, all my commands in .profile are executed  and will be available readily.

Could you please help me in understanding, how does it works? Also, when to use .bashrc/.profile/.bash_profile files.

Thanks!

How to make OS X to read .bash_profile not .profile file

I have a call to GPG in the following way in a PowerShell script: 

    $key = &amp; &#39;gpg&#39; --decrypt &quot;secret.gpg&quot; --quiet --no-verbose &gt; $null

I don&#39;t want any output from GPG to be seen on the main console when I&#39;m running the script. 

Due to my noobness in PowerShell, I don&#39;t know how to do this. I searched 
Stack&amp;nbsp;Overflow and googled for a way to do it, found a lot of ways to do it, but non of it worked.

The &quot;&gt; $null&quot; for example has no effect. I found the `--quiet --no-verbose` options for GPG to put less output in the console, still it&#39;s not completely quiet, and I&#39;m sure there is a way in PowerShell too.


Suppress console output in PowerShell

I have a call to GPG in the following way in a PowerShell script:
<pre><code class="hljs language-ini">$key = &#x26; 'gpg' --decrypt "secret.gpg" --quiet --no-verbose > $null
</code></pre>
I don't want any output from GPG to be seen on the main console when I'm running the script.
Due to my noobness in PowerShell, I don't know how to do this. I searched
Stack Overflow and googled for a way to do it, found a lot of ways to do it, but non of it worked.
The "> $null" for example has no effect. I found the <code>--quiet --no-verbose</code> options for GPG to put less output in the console, still it's not completely quiet, and I'm sure there is a way in PowerShell too.

How can I change the following code to look at all the .log files in the directory and not just the one file?

I need to loop through all the files and delete all lines that do not contain &quot;step4&quot; or &quot;step9&quot;. Currently this will create a new file, but I&#39;m not sure how to use the `for each` loop here (newbie).

The actual files are named like this: **2013 09 03 00_01_29.log**. I&#39;d like the output files to either overwrite them, or to have the SAME name, appended with &quot;out&quot;.

    $In = &quot;C:\Users\gerhardl\Documents\My Received Files\Test_In.log&quot;
    $Out = &quot;C:\Users\gerhardl\Documents\My Received Files\Test_Out.log&quot;
    $Files = &quot;C:\Users\gerhardl\Documents\My Received Files\&quot;

    Get-Content $In | Where-Object {$_ -match &#39;step4&#39; -or $_ -match &#39;step9&#39;} | `
    Set-Content $Out


Loop through files in a directory using PowerShell

Consider the following snippet:

    &quot;12-18&quot; -Contains &quot;-&quot;

You’d think this evaluates to `true`, but it doesn&#39;t. This will evaluate to `false` instead. I’m not sure why this happens, but it does.

To avoid this, you can use this instead:

    &quot;12-18&quot;.Contains(&quot;-&quot;)

Now the expression will evaluate to true.

Why does the first code snippet behave like that? Is there something special about `-` that doesn&#39;t play nicely with `-Contains`? [The documentation][1] doesn&#39;t mention anything about it.

  [1]: http://technet.microsoft.com/en-us/library/hh847759.aspx


PowerShell and the -contains operator

I&#39;m writing a powershell script that needs to make a web request and inspect the status code of the response.

I have tried writing this:

    $client = new-object system.net.webclient
    
    $response = $client.DownloadData($url)

as well as this:

    $response = Invoke-WebRequest $url

but whenever the web page has a status code that&#39;s not a success status code, PowerShell goes ahead and throws an exception instead of giving me the actual response object.

How can I get the status code of the page even when it fails to load?

Powershell web request without throwing exception on 4xx/5xx

I&#39;m running a PowerShell script against many servers, and it is logging output to a text file.

I&#39;d like to capture the server the script is currently running on. So far I have:

    $file = &quot;\\server\share\file.txt&quot;
    $computername = $env:computername

    $computername | Add-Content -Path $file

This last line adds question marks in the output file. Oops.

How do I output a variable to a text file in PowerShell?


Output (&quot;echo&quot;) a variable to a text file

I&#39;m trying to create a child XML element for this xml:

    &lt;?xml version=&quot;1.0&quot; encoding=&quot;utf-8&quot;?&gt;
    &lt;configuration&gt;
    &lt;/configuration&gt;

I use this PowerShell script:


    [xml] $doc = Get-Content($filePath)
    $child = $doc.CreateElement(&quot;newElement&quot;)
    $doc.configuration.AppendChild($child)

I have an error:
**Method invocation failed because [System.String] doesn&#39;t contain a method named
 &#39;AppendChild&#39;.**

How to add a child element for XML in PowerShell

I&#39;m pretty new to CMake, and read a few tutorials on how to use it, and wrote some complicated 50 lines of CMake script in order to make a program for 3 different compilers. This probably concludes all my knowledge in CMake.

Now my problem is that I have some source code, whose folder I don&#39;t want to touch/mess with when I make the program. I want that all CMake and `make` output files and folders to go into `../Compile/`, so I changed a few variables in my CMake script for that, and it worked for sometime when I did something like this on my laptop:

    Compile$ cmake ../src
    Compile$ make

Where with that I had a clean output in the folder I&#39;m in right now, which is exactly what I&#39;m looking for.

Now I moved to another computer, and recompiled CMake 2.8.11.2, and I&#39;m almost back to square one! It always compiles the thing into the `src` folder where my `CMakeLists.txt` is located.

The part where I choose the directory in my CMake script is this:

    set(dir ${CMAKE_CURRENT_SOURCE_DIR}/../Compile/)
    set(EXECUTABLE_OUTPUT_PATH ${dir} CACHE PATH &quot;Build directory&quot; FORCE)
    set(LIBRARY_OUTPUT_PATH ${dir} CACHE PATH &quot;Build directory&quot; FORCE)
    set(CMAKE_RUNTIME_OUTPUT_DIRECTORY ${dir})
    set(CMAKE_BUILD_FILES_DIRECTORY ${dir})
    set(CMAKE_BUILD_DIRECTORY ${dir})
    set(CMAKE_BINARY_DIR  ${dir})
    SET(EXECUTABLE_OUTPUT_PATH ${dir})
    SET(LIBRARY_OUTPUT_PATH ${dir}lib)
    SET(CMAKE_CACHEFILE_DIR ${dir})
    

And now it always ends with:

    -- Build files have been written to: /.../src

Am I missing something?

CMake output/build directory

If I have an array of strings e.g.

    a = [&#39;a&#39;, &#39;b&#39;, &#39;c&#39;, &#39;d&#39;]

and I want to output the elements, to a file (e.g. .txt) one per line. So far I have:

    File.new(&quot;test.txt&quot;, &quot;w+&quot;)
    File.open(&quot;test.txt&quot;, &quot;w+&quot;) do |i|
	    i.write(a)
    end

This gives me the array on one line of the test.txt file.
How can I iterate over the array, adding each value to a new line of the file?

Add each array element to the lines of a file in ruby

I have the followed imports:

    import org.slf4j.Logger;
    import org.slf4j.LoggerFactory;

and the following instantiation:

    private static Logger logger = LoggerFactory.getLogger(Test.class);

and the following in my Main method:

    logger.info(&quot;SOME MESSAGE: &quot;);

However, I&#39;m not able to find the output anywhere. All I see is that in my console there is:

    21:21:24.235 [main] INFO  some_folder.Test - SOME MESSAGE: 

How do I locate the log file?

Note that the following are on my  build path:

`slf4j-api-1.7.5.jar`

`slf4j-log4j12-1.6.4.jar`

I read the answer to similar questions but nobody actually says how to fix the problem.


Where does the slf4j log file get saved?

    Program A()
    {
    	x, y, z: integer;
    
    	procedure B()
    	{
    		y: integer;
    		y=0;
    		x=z+1;
    		z=y+2;
    	}
    
    	procedure C()
    	{
    		z: integer;
    
    		procedure D()
    		{
    			x: integer;
    			x = z + 1;
    			y = x + 1;
    			call B();
    		}
    
    		z = 5;
    		call D();
    	}
    
    	x = 10;
    	y = 11;
    	z = 12;
    	call C();
    	print x, y, z;
    }

From my understanding, the result of this program when run using **static scoping** is: x=13, y=7, and z=2.

However, when it is run using **dynamic scoping**, the result is: x=10, y=7, and z=12.

These results are the ones that our professor gave us. However, I cannot understand for the life of me how he has reached these results. Could someone possibly walk through the pseudocode and explain their values in the two different types of scopes?

Static (Lexical) Scoping vs Dynamic Scoping (Pseudocode)

Our (PHP) framework sometimes renders hidden inputs with value `YTowOnt9`. I can&#39;t find that string anywhere in the (huge) codebase, and can&#39;t figure out where it came from. I decided to Google for that particular string, and the [result][1] surprised me. Over half a million - kind of random - hits. I haven&#39;t found any page describing the value itself. It has 0 hits on Stack&amp;nbsp;Overflow. 

Is `YTowOnt9` some kind of magic string?

  [1]: https://www.google.com/?q=%22YTowOnt9%22#q=%22YTowOnt9%22


What is &#39;YTowOnt9&#39;?

I am writing scripts in Python2.6 with use of [pyVmomi](https://github.com/vmware/pyvmomi) and while using one of the connection methods:

    service_instance = connect.SmartConnect(host=args.ip,
                                            user=args.user,
                                            pwd=args.password)

I get the following warning:

    /usr/lib/python2.6/site-packages/requests/packages/urllib3/connectionpool.py:734: InsecureRequestWarning: Unverified HTTPS request is being made. Adding certificate verification is strongly advised. See: https://urllib3.readthedocs.org/en/latest/security.html
      InsecureRequestWarning)


What&#39;s interesting is that I do not have urllib3 installed with pip (but it&#39;s there in */usr/lib/python2.6/site-packages/requests/packages/urllib3/*).

I have tried as suggested [here](https://urllib3.readthedocs.org/en/latest/security.html)

    import urllib3
    ...
    urllib3.disable_warnings()

but that didn&#39;t change anything.



Suppress InsecureRequestWarning: Unverified HTTPS request is being made in Python2.6

I am defining some functions to be used as callbacks and not all of them use all their parameters.

How can I mark unused parameters so that the compiler won&#39;t give me warnings about them?

Mark unused parameters in Kotlin

I have a function for statistic issues:

    import numpy as np
    from scipy.special import gamma as Gamma

    def Foo(xdata):
        ...
        return x1 * (
                     ( #R is a numpy vector
                      ( ((R - x2)/beta) ** (x3 -1) ) * 
                      ( np.exp( - ((R - x2) / x4) ) ) /
                      ( x4 * Gamma(x3))
                     ).real
                    )

Sometimes I get from the shell the following warning:

    RuntimeWarning: divide by zero encountered in...

I use the numpy `isinf` function to correct the results of the function in other files, so I do not need this warning. 

Is there a way to ignore the message?
In other words, I do not want the shell to print this message.

I do not want to disable all python warnings, just this one.

Ignore divide by 0 warning in NumPy

An often used statement like `(void)x;` allows to suppress warnings about unused variable `x`. But if I try compiling the following, I get some results I don&#39;t quite understand:

    int main()
    {
        int x;
        (short)x;
        (void)x;
        (int)x;
    }

Compiling this with g++, I get the following warnings:

    $ g++ test.cpp -Wall -Wextra -o test
    test.cpp: In function ‘int main()’:
    test.cpp:4:13: warning: statement has no effect [-Wunused-value]
         (short)x;
                 ^
    test.cpp:6:11: warning: statement has no effect [-Wunused-value]
         (int)x;
               ^

So I conclude that casting to `void` is very different from casting to any other types, be the target type the same as `decltype(x)` or something different. My guess at possible explanations is:

* It is just a convention that `(void)x;` but not the other casts will suppress warnings. All the statements equally don&#39;t have any effect.
* This difference is somehow related to the fact that `void x;` isn&#39;t a valid statement while `short x;` is.

Which of these if any is more correct? If none, then how can the difference in compiler warnings be explained?

What does casting to `void` really do?

I&#39;m getting the user&#39;s location through 

    Location location = LocationServices.FusedLocationApi.getLastLocation(
                mGoogleApiClient);

This line of code is inside a method and before calling this method I do check for Android run time permissions. Only if the permission is available from the user then I call this method. Code is working perfectly.

The problem is that Android Studio still shows an error on this line not recognising that I&#39;ve already checked before calling this function.

    Call requires permission which may be rejected by user: code should explicitly check to see if permission is available (with `checkPermission`) or explicitly handle a potential `SecurityException`
Now how do I remove this warning? I&#39;ve already checked for permissions and don&#39;t want  to check again just to remove this warning. I&#39;ve tried adding @SuppressWarnings() but don&#39;t know the exact String to pass into this.             **@SuppressWarnings({&quot;all&quot;})** works but it is obviously not recommended.

How do I remove this warning? 

**EDIT 1 :** This is my exact code -

    private void checkPermissions() {
        if (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_FINE_LOCATION)
                == PackageManager.PERMISSION_GRANTED)
            getLocation();  //Method called if I have permission
    }

    private void getLocation() {
        //Android studio shows warning at this line.
        Location location = LocationServices.FusedLocationApi.getLastLocation(
                mGoogleApiClient);
    }

But if I put the permission check inside getLocation() method then the warning disappears. **@SuppressWarnings({&quot;MissingPermission&quot;})** did not work.

**EDIT 2:** I&#39;ve discovered that the only way to suppress the warning are - 

Adding this comment on top of that particular piece of code - 

    //noinspection ResourceType

or adding this - 

    @SuppressWarnings({&quot;ResourceType&quot;})

Content Type	Original Author	Original Content on Stackoverflow
Question	Dominik Antal	View Question on Stackoverflow
Solution 1 - Powershell	vonPryz	View Answer on Stackoverflow
Solution 2 - Powershell	Dave Sexton	View Answer on Stackoverflow
Solution 3 - Powershell	Dirk	View Answer on Stackoverflow

Suppress console output in PowerShell

Powershell Problem Overview

Powershell Solutions

Solution 1 - Powershell

Solution 2 - Powershell

Solution 3 - Powershell

How to make OS X to read .bash_profile not .profile file

Non-scrollable ListView inside ScrollView

Attributions