Should I instantiate instance variables on declaration or in the constructor?

JavaConstructorInstance Variables

Java Problem Overview


Is there any advantage for either approach?

Example 1:

class A {
    B b = new B();
}

Example 2:

class A {
    B b;

    A() {
         b = new B();
    }
}

Java Solutions


Solution 1 - Java

  • There is no difference - the instance variable initialization is actually put in the constructor(s) by the compiler.

  • The first variant is more readable.

  • You can't have exception handling with the first variant.

  • There is additionally the initialization block, which is as well put in the constructor(s) by the compiler:

      {
          a = new A();
      }
    

Check http://java.sun.com/docs/books/tutorial/java/javaOO/initial.html">Sun's explanation and advice

From http://docstore.mik.ua/orelly/java-ent/jnut/ch03_02.htm">this tutorial: > Field declarations, however, are not part of any method, so they cannot be executed as statements are. Instead, the Java compiler generates instance-field initialization code automatically and puts it in the constructor or constructors for the class. The initialization code is inserted into a constructor in the order it appears in the source code, which means that a field initializer can use the initial values of fields declared before it.

Additionally, you might want to lazily initialize your field. In cases when initializing a field is an expensive operation, you may initialize it as soon as it is needed:

ExpensiveObject o;

public ExpensiveObject getExpensiveObject() {
    if (o == null) {
        o = new ExpensiveObject();
    }
    return o;
}

And ultimately (as pointed out by Bill), for the sake of dependency management, it is better to avoid using the new operator anywhere within your class. Instead, using http://en.wikipedia.org/wiki/Dependency_injection">Dependency Injection is preferable - i.e. letting someone else (another class/framework) instantiate and inject the dependencies in your class.

Solution 2 - Java

Another option would be to use Dependency Injection.

class A{
   B b;

   A(B b) {
      this.b = b;
   }
}

This removes the responsibility of creating the B object from the constructor of A. This will make your code more testable and easier to maintain in the long run. The idea is to reduce the coupling between the two classes A and B. A benefit that this gives you is that you can now pass any object that extends B (or implements B if it is an interface) to A's constructor and it will work. One disadvantage is that you give up encapsulation of the B object, so it is exposed to the caller of the A constructor. You'll have to consider if the benefits are worth this trade-off, but in many cases they are.

Solution 3 - Java

I got burned in an interesting way today:

class MyClass extends FooClass {
    String a = null;

    public MyClass() {
        super();     // Superclass calls init();
    }

    @Override
    protected void init() {
        super.init();
        if (something)
            a = getStringYadaYada();
    }
}

See the mistake? It turns out that the a = null initializer gets called after the superclass constructor is called. Since the superclass constructor calls init(), the initialization of a is followed by the a = null initialization.

Solution 4 - Java

my personal "rule" (hardly ever broken) is to:

  • declare all variables at the start of a block
  • make all variables final unless they cannot be
  • declare one variable per line
  • never initialize a variable where declared
  • only initialize something in a constructor when it needs data from the constructor to do the initialization

So I would have code like:

public class X
{
    public static final int USED_AS_A_CASE_LABEL = 1; // only exception - the compiler makes me
    private static final int A;
    private final int b;
    private int c;
  
    static 
    { 
        A = 42; 
    }

    {
        b = 7;
    }

    public X(final int val)
    {
        c = val;
    }

    public void foo(final boolean f)
    {
        final int d;
        final int e;

        d = 7;

        // I will eat my own eyes before using ?: - personal taste.
        if(f)
        {
            e = 1;
        }
        else
        {
            e = 2;
        }
    }
}

This way I am always 100% certain where to look for variables declarations (at the start of a block), and their assignments (as soon as it makes sense after the declaration). This winds up potentially being more efficient as well since you never initialize a variable with a value that is not used (for example declare and init vars and then throw an exception before half of those vars needed to have a value). You also do not wind up doing pointless initialization (like int i = 0; and then later on, before "i" is used, do i = 5;.

I value consistency very much, so following this "rule" is something I do all the time, and it makes it much easier to work with the code since you don't have to hunt around to find things.

Your mileage may vary.

Solution 5 - Java

Example 2 is less flexible. If you add another constructor, you need to remember to instantiate the field in that constructor as well. Just instantiate the field directly, or introduce lazy loading somewhere in a getter.

If instantiation requires more than just a simple new, use an initializer block. This will be run regardless of the constructor used. E.g.

public class A {
    private Properties properties;

    {
        try {
            properties = new Properties();
            properties.load(Thread.currentThread().getContextClassLoader().getResourceAsStream("file.properties"));
        } catch (IOException e) {
            throw new ConfigurationException("Failed to load properties file.", e); // It's a subclass of RuntimeException.
        }
    }

    // ...

}

Solution 6 - Java

I take it is almost just a matter of taste, as long as initialization is simple and doesn't need any logic.

The constructor approach is a bit more fragile if you don't use an initializer block, because if you later on add a second constructor and forget to initialize b there, you'll get a null b only when using that last constructor.

See http://java.sun.com/docs/books/tutorial/java/javaOO/initial.html for more details about initialization in Java (and for explanations on initalizer blocks and other not well known initialization features).

Solution 7 - Java

Using either dependency injection or lazy initialization is always preferable, as already explained thoroughly in other answers.

When you don't want or can't use those patterns, and for primitive data types, there are three compelling reasons that I can think of why it's preferable to initialize the class attributes outside the constructor:

  1. avoided repetition = if you have more than one constructor, or when you will need to add more, you won't have to repeat the initialization over and over in all the constructors bodies;
  2. improved readability = you can easily tell with a glance which variables will have to be initialized from outside the class;
  3. reduced lines of code = for every initialization done at the declaration there will be a line less in the constructor.

Solution 8 - Java

I've not seen the following in the replies:

A possible advantage of having the initialisation at the time of declaration might be with nowadays IDE's where you can very easily jump to the declaration of a variable (mostly Ctrl-<hover_over_the_variable>-<left_mouse_click>) from anywhere in your code. You then immediately see the value of that variable. Otherwise, you have to "search" for the place where the initialisation is done (mostly: constructor).

This advantage is of course secondary to all other logical reasonings, but for some people that "feature" might be more important.

Solution 9 - Java

Both of the methods are acceptable. Note that in the latter case b=new B() may not get initialized if there is another constructor present. Think of initializer code outside constructor as a common constructor and the code is executed.

Solution 10 - Java

I think Example 2 is preferable. I think the best practice is to declare outside the constructor and initialize in the constructor.

Solution 11 - Java

The second is an example of lazy initialization. First one is more simple initialization, they are essentially same.

Solution 12 - Java

There is one more subtle reason to initialize outside the constructor that no one has mentioned before (very specific I must say). If you are using UML tools to generate class diagrams from the code (reverse engineering), most of the tools I believe will note the initialization of Example 1 and will transfer it to a diagram (if you prefer it to show the initial values, like I do). They will not take these initial values from Example 2. Again, this is a very specific reason - if you are working with UML tools, but once I learned that, I am trying to take all my default values outside of constructor unless, as was mentioned before, there is an issue of possible exception throwing or complicated logic.

Solution 13 - Java

The second option is preferable as allows to use different logic in ctors for class instantiation and use ctors chaining. E.g.

class A {
    int b;

    // secondary ctor
    A(String b) {
         this(Integer.valueOf(b));
    }

    // primary ctor
    A(int b) {
         this.b = b;
    }
}

So the second options is more flexible.

Solution 14 - Java

It's quite different actually:

The declaration happens before construction. So say if one has initialized the variable (b in this case) at both the places, the constructor's initialization will replace the one done at the class level.

So declare variables at the class level, initialize them in the constructor.

Solution 15 - Java

    class MyClass extends FooClass {
    String a = null;

    public MyClass() {
        super();     // Superclass calls init();
    }

    @Override
    protected void init() {
        super.init();
        if (something)
            a = getStringYadaYada();
    }
}

Regarding the above,

String a = null;

null init could be avoided since anyway it's the default. However, if you were to need another default value, then, because of the uncontrolled initialization order, I would fix as follow:

class MyClass extends FooClass 
{
    String a;
    {
        if( a==null ) a="my custom default value";
    }
    ...

  

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