Is it not possible to define multiple constructors in Python?

PythonConstructor

Python Problem Overview


> Possible Duplicate:
> What is a clean, pythonic way to have multiple constructors in Python?

Is it not possible to define multiple constructors in Python, with different signatures? If not, what's the general way of getting around it?

For example, let's say you wanted to define a class City.

I'd like to be able to say someCity = City() or someCity = City("Berlin"), where the first just gives a default name value, and the second defines it.

Python Solutions


Solution 1 - Python

Unlike Java, you cannot define multiple constructors. However, you can define a default value if one is not passed.

def __init__(self, city="Berlin"):
  self.city = city

Solution 2 - Python

If your signatures differ only in the number of arguments, using default arguments is the right way to do it. If you want to be able to pass in different kinds of argument, I would try to avoid the isinstance-based approach mentioned in another answer, and instead use keyword arguments.

If using just keyword arguments becomes unwieldy, you can combine it with classmethods (the bzrlib code likes this approach). This is just a silly example, but I hope you get the idea:

class C(object):

    def __init__(self, fd):
        # Assume fd is a file-like object.
        self.fd = fd

    @classmethod
    def fromfilename(cls, name):
        return cls(open(name, 'rb'))

# Now you can do:
c = C(fd)
# or:
c = C.fromfilename('a filename')

Notice all those classmethods still go through the same __init__, but using classmethods can be much more convenient than having to remember what combinations of keyword arguments to __init__ work.

isinstance is best avoided because Python's duck typing makes it hard to figure out what kind of object was actually passed in. For example: if you want to take either a filename or a file-like object you cannot use isinstance(arg, file), because there are many file-like objects that do not subclass file (like the ones returned from urllib, or StringIO, or...). It's usually a better idea to just have the caller tell you explicitly what kind of object was meant, by using different keyword arguments.

Solution 3 - Python

For the example you gave, use default values:

class City:
    def __init__(self, name="Default City Name"):
        ...
    ...

In general, you have two options:

  1. Do if-elif blocks based on the type:

    def init(self, name): if isinstance(name, str): ... elif isinstance(name, City): ... ...

  2. Use duck typing --- that is, assume the user of your class is intelligent enough to use it correctly. This is typically the preferred option.

Solution 4 - Python

The easiest way is through keyword arguments:

class City():
  def __init__(self, city=None):
    pass

someCity = City(city="Berlin")

This is pretty basic stuff. Maybe look at the Python documentation?

Solution 5 - Python

The answer by Jack M. is correct. Do it this way:

>>> class City:
...     def __init__(self, city=None):
...         self.city = city
...     def __repr__(self):
...         if self.city:  return self.city
...         return ''
...
>>> c = City('Berlin')
>>> print c
Berlin
>>> c = City()
>>> print c

>>>

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionChrisView Question on Stackoverflow
Solution 1 - PythonAndrew SledgeView Answer on Stackoverflow
Solution 2 - PythonmzzView Answer on Stackoverflow
Solution 3 - PythonpavpanchekhaView Answer on Stackoverflow
Solution 4 - PythonJack M.View Answer on Stackoverflow
Solution 5 - Pythontelliott99View Answer on Stackoverflow