How to pass parameters to a partial view in ASP.NET MVC?
asp.net Mvcasp.net Mvc-3Model View-ControllerControllerasp.net Mvc-Partialviewasp.net Mvc Problem Overview
Suppose that I have this partial view:
Your name is <strong>@firstName @lastName</strong>
which is accessible through a child only action like:
[ChildActionOnly]
public ActionResult FullName(string firstName, string lastName)
{
}
And I want to use this partial view inside another view with:
@Html.RenderPartial("FullName")
In other words, I want to be able to pass firstName ans lastName from view to partial view. How should I do that?
asp.net Mvc Solutions
Solution 1 - asp.net Mvc
Here is another way to do it if you want to use ViewData:
@Html.Partial("~/PathToYourView.cshtml", null, new ViewDataDictionary { { "VariableName", "some value" } })
And to retrieve the passed in values:
@{
string valuePassedIn = this.ViewData.ContainsKey("VariableName") ? this.ViewData["VariableName"].ToString() : string.Empty;
}
Solution 2 - asp.net Mvc
Use this overload (RenderPartialExtensions.RenderPartial
on MSDN):
public static void RenderPartial(
this HtmlHelper htmlHelper,
string partialViewName,
Object model
)
so:
@{Html.RenderPartial(
"FullName",
new { firstName = model.FirstName, lastName = model.LastName});
}
Solution 3 - asp.net Mvc
You need to create a view model. Something like this should do...
public class FullNameViewModel
{
public string FirstName { get; set; }
public string LastName { get; set; }
public FullNameViewModel() { }
public FullNameViewModel(string firstName, string lastName)
{
this.FirstName = firstName;
this.LastName = lastName;
}
}
then from your action result pass the model
return View("FullName", new FullNameViewModel("John", "Doe"));
and you will be able to access @Model.FirstName
and @Model.LastName
accordingly.
Solution 4 - asp.net Mvc
make sure you add {} around Html.RenderPartial, as:
@{Html.RenderPartial("FullName", new { firstName = model.FirstName, lastName = model.LastName});}
not
@Html.RenderPartial("FullName", new { firstName = model.FirstName, lastName = model.LastName});
Solution 5 - asp.net Mvc
Following is working for me on dotnet 1.0.1:
./ourView.cshtml
@Html.Partial(
"_ourPartial.cshtml",
new ViewDataDictionary(this.ViewData) {
{
"hi", "hello"
}
}
);
./_ourPartial.cshtml
<h1>@this.ViewData["hi"]</h1>
Solution 6 - asp.net Mvc
Just:
@Html.Partial("PartialName", Model);
Solution 7 - asp.net Mvc
@{
Html.RenderPartial("_partialViewName", null, new ViewDataDictionary { { "Key", "Value" } });
}
in the place you want to show your partial,
@{
string valuePassedIn = this.ViewData.ContainsKey("Key") ? this.ViewData["Key"].ToString() : string.Empty;
}
in the partialview rendered,
To use the valuePassedIn --> @valuePassedIn