How to match a substring in a string, ignoring case

PythonPerl

Python Problem Overview


I'm looking for ignore case string comparison in Python.

I tried with:

if line.find('mandy') >= 0:

but no success for ignore case. I need to find a set of words in a given text file. I am reading the file line by line. The word on a line can be mandy, Mandy, MANDY, etc. (I don't want to use toupper/tolower, etc.).

I'm looking for the Python equivalent of the Perl code below.

if ($line=~/^Mandy Pande:/i)

Python Solutions


Solution 1 - Python

If you don't want to use str.lower(), you can use a regular expression:

import re

if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
    # Is True

Solution 2 - Python

There's another post here. Try looking at this.

BTW, you're looking for the .lower() method:

string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
    print "Equals!"
else:
    print "Different!"

Solution 3 - Python

Try:

if haystackstr.lower().find(needlestr.lower()) != -1:
  # True

Solution 4 - Python

a = "MandY"
alow = a.lower()
if "mandy" in alow:
    print "true"

work around

Solution 5 - Python

One can use the in operator after applying str.casefold to both strings.

str.casefold is the recommended method for use in case-insensitive comparison.

Return a casefolded copy of the string. Casefolded strings may be used for caseless matching.

Casefolding is similar to lowercasing but more aggressive because it is intended to remove all case distinctions in a string. For example, the German lowercase letter 'ß' is equivalent to "ss". Since it is already lowercase, lower() would do nothing to 'ß'; casefold() converts it to "ss".

The casefolding algorithm is described in section 3.13 of the Unicode Standard.

New in version 3.3.

For case-insensitive substring search:

needle = "TEST"
haystack = "testing"
if needle.casefold() in haystack.casefold():
	print('Found needle in haystack')

For case-insensitive string comparison:

a = "test"
b = "TEST"
if a.casefold() == b.casefold():
    print('a and b are equal, ignoring case')

Solution 6 - Python

you can also use: s.lower() in str.lower()

Solution 7 - Python

You can use in operator in conjunction with lower method of strings.

if "mandy" in line.lower():

Solution 8 - Python

import re
if re.search('(?i)Mandy Pande:', line):
    ...

Solution 9 - Python

See this.

In [14]: re.match("mandy", "MaNdY", re.IGNORECASE)
Out[14]: <_sre.SRE_Match object at 0x23a08b8>

Solution 10 - Python

If it is a pandas series, you can mention case=False in the str.contains

data['Column_name'].str.contains('abcd', case=False) 

OR if it is just two string comparisons try the other method below

You can use casefold() method. The casefold() method ignores cases when comparing.

firstString = "Hi EVERYONE"
secondString = "Hi everyone"

if firstString.casefold() == secondString.casefold():
    print('The strings are equal.')
else:
    print('The strings are not equal.')

Output:

The strings are equal.

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionMandar PandeView Question on Stackoverflow
Solution 1 - PythoneumiroView Answer on Stackoverflow
Solution 2 - PythonSamuele MattiuzzoView Answer on Stackoverflow
Solution 3 - PythonnorbertoisaacView Answer on Stackoverflow
Solution 4 - PythonRiccardo B.View Answer on Stackoverflow
Solution 5 - PythonUnmitigatedView Answer on Stackoverflow
Solution 6 - PythonpabloverdView Answer on Stackoverflow
Solution 7 - PythonVHSView Answer on Stackoverflow
Solution 8 - Pythona'rView Answer on Stackoverflow
Solution 9 - PythonFredrik PihlView Answer on Stackoverflow
Solution 10 - PythonmpriyaView Answer on Stackoverflow