Create a dedicated folder for every zip files in a directory and extract zip files
LinuxShellSedAwkUnzipLinux Problem Overview
If I choose a zip file and right click "extract here" a folder with the zip filename is created and the entire content of the zip file is extracted into it.
However, I would like to convert several zip files via shell. But when I do
unzip filename.zip
the folder "filename"
is not created but all the files are extracted into the current directory.
I have looked at the parameters but there is no such parameter. I also tried
for zipfile in \*.zip; do mkdir $zipfile; unzip $zipfile -d $zipfile/; done
but the .zip
extension of the 2. $zipfile and 4. $zipfile have to be removed with sed.
If I do
for zipfile in \*.zip; do mkdir sed 's/\.zip//i' $zipfile; unzip $zipfile -d sed 's/\.zip//i' $zipfile/; done
it is not working.
How do I replace the .zip
extension of $zipfile
properly?
Is there an easier way than a shell script?
Linux Solutions
Solution 1 - Linux
unzip file.zip -d xxx
will extract files to directory xxx, and xxx will be created if it is not there. You can check the man page for details.
The awk line below should do the job:
ls *.zip|awk -F'.zip' '{print "unzip "$0" -d "$1}'|sh
See the test below,
note that I removed |sh
at the end, since my zips are fake archives; I just want to show the generated command line here.
kent$ ls -l
total 0
-rw-r--r-- 1 kent kent 0 Nov 12 23:10 001.zip
-rw-r--r-- 1 kent kent 0 Nov 12 23:10 002.zip
-rw-r--r-- 1 kent kent 0 Nov 12 23:10 003.zip
-rw-r--r-- 1 kent kent 0 Nov 12 23:10 004.zip
-rw-r--r-- 1 kent kent 0 Nov 12 23:10 005.zip
-rw-r--r-- 1 kent kent 0 Nov 12 23:10 006.zip
-rw-r--r-- 1 kent kent 0 Nov 12 23:10 007.zip
kent$ ls *.zip|awk -F'.zip' '{print "unzip "$0" -d "$1}'
unzip 001.zip -d 001
unzip 002.zip -d 002
unzip 003.zip -d 003
unzip 004.zip -d 004
unzip 005.zip -d 005
unzip 006.zip -d 006
unzip 007.zip -d 007
Solution 2 - Linux
"extract here" is merely a feature of whatever unzip
wrapper you are using. unzip
will only extract what actually is in the archive. There is probably no simpler way than a shell script. But sed
, awk
etc. are not needed for this if you have a POSIX-compliant shell:
for f in *.zip; do unzip -d "${f%*.zip}" "$f"; done
(You MUST NOT escape the *
or pathname expansion will not take place.) Be aware that if the ZIP archive contains a directory, such as with Eclipse archives (which always contain eclipse/
), you would end up with ./eclipse*/eclipse/eclipse.ini
in any case. Add echo
before unzip
for a dry run.
Solution 3 - Linux
p7zip
, the command line version of 7zip does the job
7z x '*.zip' -o'*'
On Debian and Ubuntu, you have to install p7zip-full
.
Solution 4 - Linux
Add the folder name and slash after the switch, example:
unzip -d newfolder/ zipfile.zip
zip will create the folder 'newfolder' and extract the archive into it.
Note that the trailing slash is not required but I guess it's just from old habit (I use Debian and Ubuntu).
Solution 5 - Linux
aunpack
from atool will do this by default for all sorts of archives.
Solution 6 - Linux
In Termux bash I ended up with this, tested for spaces and dots in filenames. It only removes the last file extension and dot for the folder name. This assumes the zip file has a .zip extension otherwise it won't work. Went nuts trying to \ escape the quotes or use single quotes before realizing they just needed to be there as plain quote marks. Drop an echo in front of the zip command, or add a -l to audit the command. For some reason the position of the -d seems important for this implementation.
for f in *.zip; do unzip "$f" \-d "./${f%.*}/"; done; echo -end-
Solution 7 - Linux
- Open the terminal and locate the 00* files
cat filename.zip.00* > filename.zip
wait until the process ends, it depends on the file size.
- The file joining process finished, now you can run the output file
unzip filename.zip