Convert string to JSON array
JavaAndroidJsonJava Problem Overview
I have the following string of a JSON from a web service and am trying to convert this to a JSONarray
{
"locations": [
{
"lat": "23.053",
"long": "72.629",
"location": "ABC",
"address": "DEF",
"city": "Ahmedabad",
"state": "Gujrat",
"phonenumber": "1234567"
},
{
"lat": "23.053",
"long": "72.629",
"location": "ABC",
"address": "DEF",
"city": "Ahmedabad",
"state": "Gujrat",
"phonenumber": "1234567"
},
{
"lat": "23.053",
"long": "72.629",
"location": "ABC",
"address": "DEF",
"city": "Ahmedabad",
"state": "Gujrat",
"phonenumber": "1234567"
},
{
"lat": "23.053",
"long": "72.629",
"location": "ABC",
"address": "DEF",
"city": "Ahmedabad",
"state": "Gujrat",
"phonenumber": "1234567"
},
{
"lat": "23.053",
"long": "72.629",
"location": "ABC",
"address": "DEF",
"city": "Ahmedabad",
"state": "Gujrat",
"phonenumber": "1234567"
}
]
}
I validated this String online, it seems to be correct. Now I am using the following code in android development to utilise
JSONArray jsonArray = new JSONArray(readlocationFeed);
This throws exception a type mismatch Exception.
Java Solutions
Solution 1 - Java
Here you get JSONObject so change this line:
JSONArray jsonArray = new JSONArray(readlocationFeed);
with following:
JSONObject jsnobject = new JSONObject(readlocationFeed);
and after
JSONArray jsonArray = jsnobject.getJSONArray("locations");
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject explrObject = jsonArray.getJSONObject(i);
}
Solution 2 - Java
Input String
[ { "userName": "sandeep", "age": 30 }, { "userName": "vivan", "age": 5 }]
Simple Way to Convert String to JSON
public class Test
{
public static void main(String[] args) throws JSONException
{
String data = "[{\"userName\": \"sandeep\",\"age\":30},{\"userName\": \"vivan\",\"age\":5}] ";
JSONArray jsonArr = new JSONArray(data);
for (int i = 0; i < jsonArr.length(); i++)
{
JSONObject jsonObj = jsonArr.getJSONObject(i);
System.out.println(jsonObj);
}
}
}
Output
{"userName":"sandeep","age":30}
{"userName":"vivan","age":5}
Solution 3 - Java
Using json lib:-
String data="[{"A":"a","B":"b","C":"c","D":"d","E":"e","F":"f","G":"g"}]";
Object object=null;
JSONArray arrayObj=null;
JSONParser jsonParser=new JSONParser();
object=jsonParser.parse(data);
arrayObj=(JSONArray) object;
System.out.println("Json object :: "+arrayObj);
Using GSON lib:-
Gson gson = new Gson();
String data="[{\"A\":\"a\",\"B\":\"b\",\"C\":\"c\",\"D\":\"d\",\"E\":\"e\",\"F\":\"f\",\"G\":\"g\"}]";
JsonParser jsonParser = new JsonParser();
JsonArray jsonArray = (JsonArray) jsonParser.parse(data);
Solution 4 - Java
you will need to convert given string to JSONObject instead of JSONArray because current String contain JsonObject as root element instead of JsonArray :
JSONObject jsonObject = new JSONObject(readlocationFeed);
Solution 5 - Java
String b = "[" + readlocationFeed + "]";
JSONArray jsonArray1 = new JSONArray(b);
jsonarray_length1 = jsonArray1.length();
for (int i = 0; i < jsonarray_length1; i++) {
}
or convert it in JSONOBJECT
JSONObject jsonobj = new JSONObject(readlocationFeed);
JSONArray jsonArray = jsonobj.getJSONArray("locations");
Solution 6 - Java
Try this piece of code:
try {
Log.e("log_tag", "Error in convert String" + result.toString());
JSONObject json_data = new JSONObject(result);
String status = json_data.getString("Status");
{
String data = json_data.getString("locations");
JSONArray json_data1 = new JSONArray(data);
for (int i = 0; i < json_data1.length(); i++) {
json_data = json_data1.getJSONObject(i);
String lat = json_data.getString("lat");
String lng = json_data.getString("long");
}
}
}
Solution 7 - Java
if the response is like this
"GetDataResult": "[{\"UserID\":1,\"DeviceID\":\"d1254\",\"MobileNO\":\"056688\",\"Pak1\":true,\"pak2\":true,\"pak3\":false,\"pak4\":true,\"pak5\":true,\"pak6\":false,\"pak7\":false,\"pak8\":true,\"pak9\":false,\"pak10\":true,\"pak11\":false,\"pak12\":false}]"
you can parse like this
JSONObject jobj=new JSONObject(response);
String c = jobj.getString("GetDataResult");
JSONArray jArray = new JSONArray(c);
deviceId=jArray.getJSONObject(0).getString("DeviceID");
here the JsonArray size is 1.Otherwise you should use for loop for getting values.
Solution 8 - Java
You can do the following:
JSONArray jsonArray = jsnobject.getJSONArray("locations");
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject explrObject = jsonArray.getJSONObject(i);
}
Solution 9 - Java
It's a very simple way to convert:
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import com.google.gson.Gson;
import com.google.gson.JsonArray;
import com.google.gson.JsonElement;
import com.google.gson.JsonParser;
class Usuario {
private String username;
private String email;
private Integer credits;
private String twitter_username;
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public Integer getCredits() {
return credits;
}
public void setCredits(Integer credits) {
this.credits = credits;
}
public String getTwitter_username() {
return twitter_username;
}
public void setTwitter_username(String twitter_username) {
this.twitter_username = twitter_username;
}
@Override
public String toString() {
return "UserName: " + this.getUsername() + " Email: " + this.getEmail();
}
}
/*
* put string into file jsonFileArr.json
* [{"username":"Hello","email":"[email protected]","credits"
* :"100","twitter_username":""},
* {"username":"Goodbye","email":"[email protected]"
* ,"credits":"0","twitter_username":""},
* {"username":"mlsilva","email":"[email protected]"
* ,"credits":"524","twitter_username":""},
* {"username":"fsouza","email":"[email protected]"
* ,"credits":"1052","twitter_username":""}]
*/
public class TestaGsonLista {
public static void main(String[] args) {
Gson gson = new Gson();
try {
BufferedReader br = new BufferedReader(new FileReader(
"C:\\Temp\\jsonFileArr.json"));
JsonArray jsonArray = new JsonParser().parse(br).getAsJsonArray();
for (int i = 0; i < jsonArray.size(); i++) {
JsonElement str = jsonArray.get(i);
Usuario obj = gson.fromJson(str, Usuario.class);
System.out.println(obj);
System.out.println(str);
System.out.println("-------");
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
Solution 10 - Java
If having following JSON from web service, Json Array as a response :
[3]
0: {
id: 2
name: "a561137"
password: "test"
firstName: "abhishek"
lastName: "ringsia"
organization: "bbb"
}-
1: {
id: 3
name: "a561023"
password: "hello"
firstName: "hello"
lastName: "hello"
organization: "hello"
}-
2: {
id: 4
name: "a541234"
password: "hello"
firstName: "hello"
lastName: "hello"
organization: "hello"
}
have To Accept it first as a Json Array ,then while reading its Object have to use Object Mapper.readValue ,because Json Object Still in String .
List<User> list = new ArrayList<User>();
JSONArray jsonArr = new JSONArray(response);
for (int i = 0; i < jsonArr.length(); i++) {
JSONObject jsonObj = jsonArr.getJSONObject(i);
ObjectMapper mapper = new ObjectMapper();
User usr = mapper.readValue(jsonObj.toString(), User.class);
list.add(usr);
}
mapper.read is correct function ,if u use mapper.convert(param,param) . It will give u error .