Get JSON object from URL
PhpJsonPhp Problem Overview
I have a URL that returns a JSON object like this:
{
"expires_in":5180976,
"access_token":"AQXzQgKTpTSjs-qiBh30aMgm3_Kb53oIf-VA733BpAogVE5jpz3jujU65WJ1XXSvVm1xr2LslGLLCWTNV5Kd_8J1YUx26axkt1E-vsOdvUAgMFH1VJwtclAXdaxRxk5UtmCWeISB6rx6NtvDt7yohnaarpBJjHWMsWYtpNn6nD87n0syud0"
}
I want to get JSON object from the URL and then the access_token value.
So how can I retrieve it through PHP?
Php Solutions
Solution 1 - Php
$json = file_get_contents('url_here');
$obj = json_decode($json);
echo $obj->access_token;
For this to work, file_get_contents requires that allow_url_fopen is enabled. This can be done at runtime by including:
ini_set("allow_url_fopen", 1);
You can also use curl to get the url. To use curl, you can use the example found here:
$ch = curl_init();
// IMPORTANT: the below line is a security risk, read https://paragonie.com/blog/2017/10/certainty-automated-cacert-pem-management-for-php-software
// in most cases, you should set it to true
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'url_here');
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
echo $obj->access_token;
Solution 2 - Php
$url = 'http://.../.../yoururl/...';
$obj = json_decode(file_get_contents($url), true);
echo $obj['access_token'];
Php also can use properties with dashes:
garex@ustimenko ~/src/ekapusta/deploy $ psysh
Psy Shell v0.4.4 (PHP 5.5.3-1ubuntu2.6 — cli) by Justin Hileman
>>> $q = new stdClass;
=> <stdClass #000000005f2b81c80000000076756fef> {}
>>> $q->{'qwert-y'} = 123
=> 123
>>> var_dump($q);
class stdClass#174 (1) {
public $qwert-y =>
int(123)
}
=> null
Solution 3 - Php
You could use PHP's json_decode function:
$url = "http://urlToYourJsonFile.com";
$json = file_get_contents($url);
$json_data = json_decode($json, true);
echo "My token: ". $json_data["access_token"];
Solution 4 - Php
You need to read about json_decode function http://php.net/manual/en/function.json-decode.php
Here you go
$json = '{"expires_in":5180976,"access_token":"AQXzQgKTpTSjs-qiBh30aMgm3_Kb53oIf-VA733BpAogVE5jpz3jujU65WJ1XXSvVm1xr2LslGLLCWTNV5Kd_8J1YUx26axkt1E-vsOdvUAgMFH1VJwtclAXdaxRxk5UtmCWeISB6rx6NtvDt7yohnaarpBJjHWMsWYtpNn6nD87n0syud0"}';
//OR $json = file_get_contents('http://someurl.dev/...');
$obj = json_decode($json);
var_dump($obj-> access_token);
//OR
$arr = json_decode($json, true);
var_dump($arr['access_token']);
Solution 5 - Php
// Get the string from the URL
$json = file_get_contents('https://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452');
// Decode the JSON string into an object
$obj = json_decode($json);
// In the case of this input, do key and array lookups to get the values
var_dump($obj->results[0]->formatted_address);
Solution 6 - Php
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'url_here');
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
echo $obj->access_token;
Solution 7 - Php
file_get_contents() is not fetching the data from url,then i tried curl and it's working fine.
Solution 8 - Php
Our solution, adding some validations to response so we are sure we have a well formed json object in $json variable
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, $url);
$result = curl_exec($ch);
curl_close($ch);
if (! $result) {
return false;
}
$json = json_decode(utf8_encode($result));
if (empty($json) || json_last_error() !== JSON_ERROR_NONE) {
return false;
}
Solution 9 - Php
my solution only works for the next cases: if you are mistaking a multidimensaional array into a single one
$json = file_get_contents('url_json'); //get the json
$objhigher=json_decode($json); //converts to an object
$objlower = $objhigher[0]; // if the json response its multidimensional this lowers it
echo "<pre>"; //box for code
print_r($objlower); //prints the object with all key and values
echo $objlower->access_token; //prints the variable
i know that the answer was has already been answered but for those who came here looking for something i hope this can help you
Solution 10 - Php
When you are using curl sometimes give you 403 (access forbidden)
Solved by adding this line to emulate browser.
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.0.3705; .NET CLR 1.1.4322)');
Hope this help someone.
Solution 11 - Php
$curl_handle=curl_init();
curl_setopt($curl_handle, CURLOPT_URL,'https://www.xxxSite/get_quote/ajaxGetQuoteJSON.jsp?symbol=IRCTC&series=EQ');
//Set the GET method by giving 0 value and for POST set as 1
//curl_setopt($curl_handle, CURLOPT_POST, 0);
curl_setopt($curl_handle, CURLOPT_CUSTOMREQUEST, "GET");
curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1);
$query = curl_exec($curl_handle);
$data = json_decode($query, true);
curl_close($curl_handle);
//print complete object, just echo the variable not work so you need to use print_r to show the result
echo print_r( $data);
//at first layer
echo $data["tradedDate"];
//Inside the second layer
echo $data["data"][0]["companyName"];
Some time you might get 405, set the method type correctly.