Case insensitive access for generic dictionary

C#GenericsDictionary

C# Problem Overview


I have an application that use managed dlls. One of those dlls return a generic dictionary:

Dictionary<string, int> MyDictionary;  

The dictionary contains keys with upper and lower case.

On another side I am getting a list of potential keys (string) however I cannot guarantee the case. I am trying to get the value in the dictionary using the keys. But of course the following will fail since I have a case mismatch:

bool Success = MyDictionary.TryGetValue( MyIndex, out TheValue );  

I was hoping the TryGetValue would have an ignore case flag like mentioned in the http://msdn.microsoft.com/en-us/library/bb348919%28v=vs.90%29.aspx">MSDN doc, but it seems this is not valid for generic dictionaries.

Is there a way to get the value of that dictionary ignoring the key case? Is there a better workaround than creating a new copy of the dictionary with the proper StringComparer.OrdinalIgnoreCase parameter?

C# Solutions


Solution 1 - C#

There's no way to specify a StringComparer at the point where you try to get a value. If you think about it, "foo".GetHashCode() and "FOO".GetHashCode() are totally different so there's no reasonable way you could implement a case-insensitive get on a case-sensitive hash map.

You can, however, create a case-insensitive dictionary in the first place using:-

var comparer = StringComparer.OrdinalIgnoreCase;
var caseInsensitiveDictionary = new Dictionary<string, int>(comparer);

Or create a new case-insensitive dictionary with the contents of an existing case-sensitive dictionary (if you're sure there are no case collisions):-

var oldDictionary = ...;
var comparer = StringComparer.OrdinalIgnoreCase;
var newDictionary = new Dictionary<string, int>(oldDictionary, comparer);

This new dictionary then uses the GetHashCode() implementation on StringComparer.OrdinalIgnoreCase so comparer.GetHashCode("foo") and comparer.GetHashcode("FOO") give you the same value.

Alternately, if there are only a few elements in the dictionary, and/or you only need to lookup once or twice, you can treat the original dictionary as an IEnumerable<KeyValuePair<TKey, TValue>> and just iterate over it:-

var myKey = ...;
var myDictionary = ...;
var comparer = StringComparer.OrdinalIgnoreCase;
var value = myDictionary.FirstOrDefault(x => String.Equals(x.Key, myKey, comparer)).Value;

Or if you prefer, without the LINQ:-

var myKey = ...;
var myDictionary = ...;
var comparer = StringComparer.OrdinalIgnoreCase;
int? value;
foreach (var element in myDictionary)
{
  if (String.Equals(element.Key, myKey, comparer))
  {
    value = element.Value;
    break;
  }
}

This saves you the cost of creating a new data structure, but in return the cost of a lookup is O(n) instead of O(1).

Solution 2 - C#

For you LINQers out there that never use a regular dictionary constructor

myCollection.ToDictionary(x => x.PartNumber, x => x.PartDescription, StringComparer.OrdinalIgnoreCase)

Solution 3 - C#

There is much simpler way:

using System;
using System.Collections.Generic;
....
var caseInsensitiveDictionary = new Dictionary<string, string>(StringComparer.OrdinalIgnoreCase);

Solution 4 - C#

Its not very elegant but in case you cant change the creation of dictionary, and all you need is a dirty hack, how about this:

var item = MyDictionary.Where(x => x.Key.ToLower() == MyIndex.ToLower()).FirstOrDefault();
    if (item != null)
    {
        TheValue = item.Value;
    }

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionTocTocView Question on Stackoverflow
Solution 1 - C#Iain GallowayView Answer on Stackoverflow
Solution 2 - C#DerpyView Answer on Stackoverflow
Solution 3 - C#MajorView Answer on Stackoverflow
Solution 4 - C#ShohamView Answer on Stackoverflow