Ajax Upload image

PhpJqueryHtmlAjax

Php Problem Overview


Q.1 I would like to convert this form to ajax but it seems like my ajax code lacks something. On submit doesn't do anything at all.

Q2. I also want the function to fire on change when the file has been selected not to wait for a submit.

Here is JS.

$('#imageUploadForm').on('submit',(function(e) {
    e.preventDefault()
    $.ajax({
        type:'POST',
        url: $(this).attr('action'),
        data:$(this).serialize(),
        cache:false
    });
}));

and the HTMl with php.

<form name="photo" id="imageUploadForm" enctype="multipart/form-data" action="<?php echo $_SERVER["PHP_SELF"];?>" method="post">
    <input type="file" style="widows:0; height:0" id="ImageBrowse" hidden="hidden" name="image" size="30"/>
    <input type="submit" name="upload" value="Upload" />
    <img width="100" style="border:#000; z-index:1;position: relative; border-width:2px; float:left" height="100px" src="<?php echo $upload_path.$large_image_name.$_SESSION['user_file_ext'];?>" id="thumbnail"/>
</form>
  
  

Php Solutions


Solution 1 - Php

first in your ajax call include success & error function and then check if it gives you error or what?

your code should be like this

$(document).ready(function (e) {
    $('#imageUploadForm').on('submit',(function(e) {
        e.preventDefault();
        var formData = new FormData(this);

        $.ajax({
            type:'POST',
            url: $(this).attr('action'),
            data:formData,
            cache:false,
            contentType: false,
        	processData: false,
            success:function(data){
                console.log("success");
                console.log(data);
            },
            error: function(data){
                console.log("error");
                console.log(data);
            }
        });
    }));

    $("#ImageBrowse").on("change", function() {
        $("#imageUploadForm").submit();
    });
});

Solution 2 - Php

HTML Code

<div class="rCol"> 
     <div id ="prv" style="height:auto; width:auto; float:left; margin-bottom: 28px; margin-left: 200px;"></div>
       </div>
    <div class="rCol" style="clear:both;">
   
    <label > Upload Photo : </label> 
    <input type="file" id="file" name='file' onChange=" return submitForm();">
    <input type="hidden" id="filecount" value='0'>

Here is Ajax Code:

function submitForm() {

    var fcnt = $('#filecount').val();
    var fname = $('#filename').val();
    var imgclean = $('#file');
    if(fcnt<=5)
    {
    data = new FormData();
    data.append('file', $('#file')[0].files[0]);
   
    var imgname  =  $('input[type=file]').val();
     var size  =  $('#file')[0].files[0].size;

    var ext =  imgname.substr( (imgname.lastIndexOf('.') +1) );
    if(ext=='jpg' || ext=='jpeg' || ext=='png' || ext=='gif' || ext=='PNG' || ext=='JPG' || ext=='JPEG')
    {
     if(size<=1000000)
     {
    $.ajax({
      url: "<?php echo base_url() ?>/upload.php",
      type: "POST",
      data: data,
      enctype: 'multipart/form-data',
      processData: false,  // tell jQuery not to process the data
      contentType: false   // tell jQuery not to set contentType
    }).done(function(data) {
       if(data!='FILE_SIZE_ERROR' || data!='FILE_TYPE_ERROR' )
       {
        fcnt = parseInt(fcnt)+1;
        $('#filecount').val(fcnt);
        var img = '<div class="dialog" id ="img_'+fcnt+'" ><img src="<?php echo base_url() ?>/local_cdn/'+data+'"><a href="#" id="rmv_'+fcnt+'" onclick="return removeit('+fcnt+')" class="close-classic"></a></div><input type="hidden" id="name_'+fcnt+'" value="'+data+'">';
        $('#prv').append(img);
        if(fname!=='')
        {
          fname = fname+','+data;
        }else
        {
          fname = data;
        }
         $('#filename').val(fname);
          imgclean.replaceWith( imgclean = imgclean.clone( true ) );
       }
       else
       {
         imgclean.replaceWith( imgclean = imgclean.clone( true ) );
         alert('SORRY SIZE AND TYPE ISSUE');
       }

    });
    return false;
  }//end size
  else
  {
      imgclean.replaceWith( imgclean = imgclean.clone( true ) );//Its for reset the value of file type
    alert('Sorry File size exceeding from 1 Mb');
  }
  }//end FILETYPE
  else
  {
     imgclean.replaceWith( imgclean = imgclean.clone( true ) );
    alert('Sorry Only you can uplaod JPEG|JPG|PNG|GIF file type ');
  }
  }//end filecount
  else
  {    imgclean.replaceWith( imgclean = imgclean.clone( true ) );
     alert('You Can not Upload more than 6 Photos');
  }
}

Here is PHP code :

$filetype = array('jpeg','jpg','png','gif','PNG','JPEG','JPG');
   foreach ($_FILES as $key )
    {

          $name =time().$key['name'];

          $path='local_cdn/'.$name;
          $file_ext =  pathinfo($name, PATHINFO_EXTENSION);
          if(in_array(strtolower($file_ext), $filetype))
          {
            if($key['name']<1000000)
            {

             @move_uploaded_file($key['tmp_name'],$path);
             echo $name;
           
            }
           else
           {
               echo "FILE_SIZE_ERROR";
           }
        }
        else
        {
            echo "FILE_TYPE_ERROR";
        }// Its simple code.Its not with proper validation.

Here upload and preview part done.Now if you want to delete and remove image from page and folder both then code is here for deletion. Ajax Part:

function removeit (arg) {
       var id  = arg;
       // GET FILE VALUE
       var fname = $('#filename').val();
       var fcnt = $('#filecount').val();
        // GET FILE VALUE

       $('#img_'+id).remove();
       $('#rmv_'+id).remove();
       $('#img_'+id).css('display','none');

        var dname  =  $('#name_'+id).val();
        fcnt = parseInt(fcnt)-1;
        $('#filecount').val(fcnt);
        var fname = fname.replace(dname, "");
        var fname = fname.replace(",,", "");
        $('#filename').val(fname);
        $.ajax({
          url: 'delete.php',
          type: 'POST',
          data:{'name':dname},
          success:function(a){
            console.log(a);
            }
        });
    } 

Here is PHP part(delete.php):

$path='local_cdn/'.$_POST['name'];

   if(@unlink($path))
   {
     echo "Success";
   }
   else
   {
     echo "Failed";
   }

Solution 3 - Php

You can use jquery.form.js plugin to upload image via ajax to the server.

http://malsup.com/jquery/form/

Here is the sample jQuery ajax image upload script

(function() {
$('form').ajaxForm({
	beforeSubmit: function() {	
		//do validation here
		
		 
    },
	
	beforeSend:function(){
	   $('#loader').show();
	   $('#image_upload').hide();
	},
    success: function(msg) {
    	
    	///on success do some here
    }
}); })();  

If you have any doubt, please refer following ajax image upload tutorial here

http://www.smarttutorials.net/ajax-image-upload-using-jquery-php-mysql/

Solution 4 - Php

Image upload using ajax and check image format and upload max size   

<form class='form-horizontal' method="POST"  id='document_form' enctype="multipart/form-data">
                                    <div class='optionBox1'>
                                        <div class='row inviteInputWrap1 block1'>
                                            <div class='col-3'>
                                                <label class='col-form-label'>Name</label>
                                                <input type='text' class='form-control form-control-sm' name='name[]' id='name' Value=''>
                                            </div>
                                            <div class='col-3'>
                                                <label class='col-form-label'>File</label>
                                                <input type='file' class='form-control form-control-sm' name='file[]' id='file' Value=''>
                                            </div>
                                            <div class='col-3'>
                                                <span class='deleteInviteWrap1 remove1 d-none'>
                                                    <i class='fas fa-trash'></i>
                                                </span>
                                            </div>
                                        </div>
                                        <div class='row'>
                                             <div class='col-8 pl-3 pb-4 mt-4'>
                                                <span class='btn btn-info add1 pr-3'>+ Add More</span>
                                                 <button class='btn btn-primary'>Submit</button> 
                                            </div>
                                        </div>
                                    </div>
                                    </form>     
                                    
                                    </div>  
                      
    
      $.validator.setDefaults({
       submitHandler: function (form) 
         {
               $.ajax({
                    url : "action1.php",
                    type : "POST",
                    data : new FormData(form),
                    mimeType: "multipart/form-data",
                    contentType: false,
                    cache: false,
                    dataType:'json',
                    processData: false,
                    success: function(data)
                    {
                        if(data.status =='success')
                            {
                                 swal("Document has been successfully uploaded!", {
                                    icon: "success",
                                 });
                                 setTimeout(function(){
                                    window.location.reload(); 
                                },1200);
                            }
                            else
                            {
                                swal('Oh noes!', "Error in document upload. Please contact to administrator", "error");
                            }   
                    },
                    error:function(data)
                    {
                        swal ( "Ops!" ,  "error in document upload." ,  "error" );
                    }
                });
            }
      });
    
      $('#document_form').validate({
        rules: {
            "name[]": {
              required: true
          },
          "file[]": {
              required: true,
              extension: "jpg,jpeg,png,pdf,doc",
              filesize :2000000 
          }
        },
        messages: {
            "name[]": {
            required: "Please enter name"
          },
          "file[]": {
            required: "Please enter file",
            extension :'Please upload only jpg,jpeg,png,pdf,doc'
          }
        },
        errorElement: 'span',
        errorPlacement: function (error, element) {
          error.addClass('invalid-feedback');
          element.closest('.col-3').append(error);
        },
        highlight: function (element, errorClass, validClass) {
          $(element).addClass('is-invalid');
        },
        unhighlight: function (element, errorClass, validClass) {
          $(element).removeClass('is-invalid');
        }
      });
    
      $.validator.addMethod('filesize', function(value, element, param) {
         return this.optional(element) || (element.files[0].size <= param)
        }, 'File size must be less than 2 MB');

Solution 5 - Php

Here is simple way using HTML5 and jQuery:

  1. include two JS file

  2. include CSS to have cool buttons

  3. create DIV or SPAN

  4. write this code in your HTML page

    $('.demo').ajaxupload({ url:'upload.php' });

  5. create you upload.php file to have PHP code to upload data.

You can download required JS file from here Here is Example

Its too cool and too fast And easy too! :)

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionRelmView Question on Stackoverflow
Solution 1 - PhpSohil DesaiView Answer on Stackoverflow
Solution 2 - PhpRITUView Answer on Stackoverflow
Solution 3 - PhpmuniView Answer on Stackoverflow
Solution 4 - PhpVikas kumarView Answer on Stackoverflow
Solution 5 - PhpParas PitrodaView Answer on Stackoverflow