How can I change my current working directory in C++ in a platform-agnostic way?

I found the `direct.h` header file, which is Windows compatible, and the `unistd.h`, which is UNIX/POSIX compatible.

Change the current working directory in C++

I&#39;m running Ruby on Windows though I don&#39;t know if that should make a difference.  All I want to do is get the current working directory&#39;s absolute path.  Is this possible from irb?  Apparently from a script it&#39;s possible using `File.expand_path(__FILE__)`

But from irb I tried the following and got a &quot;Permission denied&quot; error:

    File.new(Dir.new(&quot;.&quot;).path).expand

how to get the current working directory&#39;s absolute path from irb

I have a working copy for my entire repository, which contains multiple Python projects.  When I choose right-click --&gt; SVN Update in Windows File Explorer I am getting an error message listing a particular project folder:

    Command: Update
    Updating: path\to\working\copy
    Skipped obstructing working copy: path\to\working\copy\project
    Completed: At revision: 176
    Warning!: One or more files are in a conflicted state.

When I go to that project and right-click --&gt; SVN Update, it updates successfully.  There is also not conflict editor available and when I right-click --&gt; TortoiseSVN --&gt; Resolved there are not files available.

What could be causing the conflict?  As long as this keeps occurring, it is impossible to update this project in my working copy.

TortoiseSVN reports conflict, but no conflict can be found

Is there a platform-agnostic and filesystem-agnostic method to obtain the full path of the directory from where a program is running using C/C++? Not to be confused with the current working directory. (Please don&#39;t suggest libraries unless they&#39;re standard ones like clib or STL.)

(If there&#39;s no platform/filesystem-agnostic method, suggestions that work in Windows and Linux for specific filesystems are welcome too.)

How do I get the directory that a program is running from?

I have a several Makefiles in app specific directories like this:

    /project1/apps/app_typeA/Makefile
    /project1/apps/app_typeB/Makefile
    /project1/apps/app_typeC/Makefile

Each Makefile includes a .inc file in this path one level up:

    /project1/apps/app_rules.inc

Inside app_rules.inc I&#39;m setting the destination of where I want the binaries to be placed when built. I want all binaries to be in their respective `app_type` path:

    /project1/bin/app_typeA/

**I tried using `$(CURDIR)`**, like this:

    OUTPUT_PATH = /project1/bin/$(CURDIR)

but instead I got the binaries buried in the entire path name like this: **(notice the redundancy)**

    /project1/bin/projects/users/bob/project1/apps/app_typeA

What can I do to get the &quot;current directory&quot; of execution so that I can know just the **`app_typeX`** in order to put the binaries in their respective types folder?

How to get current relative directory of your Makefile?

I know I can use `cd` command to change my working directory in bash.  

But if I do this command:

    cd SOME_PATH &amp;&amp; run_some_command

Then the working directory will be changed permanently. Is there some way to change the working directory just temporarily like this?

    PWD=SOME_PATH run_some_command

Temporarily change current working directory in bash to run a command

I run a python shell from crontab every minute:

    * * * * * /home/udi/foo/bar.py

`/home/udi/foo` has some necessary subdirectories, like `/home/udi/foo/log` and `/home/udi/foo/config`, which `/home/udi/foo/bar.py` refers to.

The problem is that `crontab` runs the script from a different working directory, so trying to open `./log/bar.log` fails.

Is there a nice way to tell the script to change the working directory to the script&#39;s own directory? I would fancy a solution that would work for any script location, rather than explicitly telling the script where it is.

**EDIT:**

    os.chdir(os.path.dirname(sys.argv[0]))

Was the most compact elegant solution. Thanks for your answers and explanations!

python: Change the scripts working directory to the script&#39;s own directory

I&#39;m making a C program where I need to get the directory that the program is started from.  This program is written for UNIX computers. I&#39;ve been looking at `opendir()` and `telldir()`, but `telldir()` returns a `off_t (long int)`, so it really doesn&#39;t help me. 

How can I get the current path in a string (char array)?

How to get the current directory in a C program?

How can I change the current working directory from within a Java program? Everything I&#39;ve been able to find about the issue claims that you simply can&#39;t do it, but I can&#39;t believe that that&#39;s really the case.

I have a piece of code that opens a file using a hard-coded relative file path from the directory it&#39;s normally started in, and I just want to be able to use that code from within a different Java program without having to start it from within a particular directory. It seems like you should just be able to call `System.setProperty( &quot;user.dir&quot;, &quot;/path/to/dir&quot; )`, but as far as I can figure out, calling that line just silently fails and does nothing.

I would understand if Java didn&#39;t allow you to do this, if it weren&#39;t for the fact that it allows you to *get* the current working directory, and even allows you to open files using relative file paths....

Changing the current working directory in Java?

I am working out some tutorials in R. Each R code is contained in a specific folder. There are data files and other files in there. I want to open the `.r` file and source it such that I do not have to change the working directory in Rstudio as shown below:

![enter image description here][1]

Is there a way to specify my working directory automatically in R.

  [1]: http://i.stack.imgur.com/7A467.jpg

R command for setting working directory to source file location in Rstudio

How to set the current working directory in Python?

How to set the current working directory?

I have a common command that gets called from within very specific directories. There is only one executable sitting in /bin for this program, and the current working directory is very important for running it correctly. The script affects the files that live inside the directory it is run within.

Now, I also have a custom shell script that does some things in one directory, but I need to call that command mentioned above as if it was in another directory.

How do you do this in a shell script?

How can Bash execute a command in a different directory context?

Let&#39;s say I have my main class in `C:\Users\Justian\Documents\`. How can I get my program to show that it&#39;s in `C:\Users\Justian\Documents`?

Hard-Coding is not an option- it needs to be adaptable if it&#39;s moved to another location.

**I want to dump a bunch of CSV files in a folder, have the program recognize all the files, then load the data and manipulate them. I really just want to know how to navigate to that folder.**

How to get current working directory in Java?

When I run the following script in IDLE

    import os
    print(os.getcwd())

I get output as

    D:\testtool

but when I run from cmd prompt, I get

    c:\Python33&gt;python D:\testtool\current_dir.py
    c:\Python33

How do I get same result which I got using IDLE ?

How to get the current working directory using python 3?

What is current directory of shell script? I this current directory from which I called it? Or this directory where script located?

Shell script current directory?

Is there a different way, other than `process.cwd()`, to get the pathname of the current project&#39;s root-directory. Does Node implement something like ruby&#39;s property, `Rails.root`,. I&#39;m looking for something that is constant, and reliable.

Determine project root from a running node.js application

I am trying to [execute a child][1] process in a different directory then the one of its parent. 

    var exec = require(&#39;child_process&#39;).exec;
    
    exec(
    	&#39;pwd&#39;,
    	{
    		cdw: someDirectoryVariable
    	},
    	function(error, stdout, stderr) {
    		// ...
    	}
    );

I&#39;m doing the above (though of course running &quot;pwd&quot; is not what I want to do in the end). This will end up writing the pwd of the parent process to stdout, regardless of what value I provided to the cdw option.

What am I missing?

(I did make sure the path passed as cwd option actually exists)


  [1]: http://nodejs.org/api/child_process.html#child_process_child_process_exec_command_options_callback

NodeJs child_process working directory

I&#39;m writing some unit tests for my application in Go. The tests fail however because it cannot find the configuration files. Normally the binary looks for the configuration files in the working directory under the path `conf/*.conf`.

I figured that browsing to the directory that has `conf/` and running `go test` in it would solve it, but it still reports that the file system cannot find the path specified.

How can I tell `go test` to use a certain directory as the working directory so that the tests may actually be executed?

Golang: tests and working directory

I have a Windows service that should look for a configuration file in its current directory.

So I use `directory.getcurrentdirectiry()` but instead of the service directory I get back 

    c:\windows\system32

Any idea why and how should I get the service directory?



Windows service - get current directory

Firstly, I saw [this topic][1] but I couldn&#39;t understand that.

**Question :**

There is a batch file in `D:\path\to\file.bat` with following content :

    echo %cd%
    pause

Output is :

    C:\
It must be `D:\path\to`

What am I doing wrong?


  [1]: https://stackoverflow.com/questions/4419868/what-is-the-current-directory-in-a-batch-file

Get current batchfile directory

I want to copy a file from a jar. The file that I am copying is going to be copied outside the working directory. I have done some tests and all methods I try end up with 0 byte files.

**EDIT**: I want the copying of the file to be done via a program, not manually.

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