Why is System.nanoTime() way slower (in performance) than System.currentTimeMillis()?

JavaPerformanceTime

Java Problem Overview


Today I did a little quick Benchmark to test speed performance of System.nanoTime() and System.currentTimeMillis():

long startTime = System.nanoTime();
		
for(int i = 0; i < 1000000; i++) {
  long test = System.nanoTime();
}
		
long endTime = System.nanoTime();
		
System.out.println("Total time: "+(endTime-startTime));

This are the results:

System.currentTimeMillis(): average of 12.7836022 / function call
System.nanoTime():          average of 34.6395674 / function call

Why are the differences in running speed so big?

Benchmark system:

Java 1.7.0_25
Windows 8 64-bit
CPU: AMD FX-6100

Java Solutions


Solution 1 - Java

From this Oracle blog:

> System.currentTimeMillis() is implemented using the > GetSystemTimeAsFileTime method, which essentially just reads the low > resolution time-of-day value that Windows maintains. Reading this > global variable is naturally very quick - around 6 cycles according to > reported information. > > System.nanoTime() is implemented using the > QueryPerformanceCounter/ QueryPerformanceFrequency API (if available, > else it returns currentTimeMillis*10^6). > QueryPerformanceCounter(QPC) is implemented in different ways > depending on the hardware it's running on. Typically it will use > either the programmable-interval-timer (PIT), or the ACPI power > management timer (PMT), or the CPU-level timestamp-counter (TSC). > Accessing the PIT/PMT requires execution of slow I/O port instructions > and as a result the execution time for QPC is in the order of > microseconds. In contrast reading the TSC is on the order of 100 clock > cycles (to read the TSC from the chip and convert it to a time value > based on the operating frequency).

Perhaps this answer the question. The two methods use different number of clock cycles, thus resulting in slow speed of the later one.

Further in that blog in the conclusion section:

> If you are interested in measuring/calculating elapsed time, then always use System.nanoTime(). On most systems it will give a resolution on the order of microseconds. Be aware though, this call can also take microseconds to execute on some platforms.

Solution 2 - Java

Most OS's (you didn't mention which one you are using) have an in memory counter/clock which provides millisecond accuracy (or close to that). For nanosecond accuracy most have to read a hardware counter. Communicating with hardware is slower then reading some value already in memory.

Solution 3 - Java

It may only be the case on Windows. See this answer to a similar question.

Basically, System.currentTimeMillis() just reads a global variable maintained by Windows (which is why it has low granularity), whereas System.nanoTime() actually has to do IO operations.

Solution 4 - Java

You are measuring that on Windows, aren't you. I went through this exercise in 2008. nanoTime IS slower on Windows than currentTimeMillis. As I recall, on Linux, nanotime is faster than currentTimeMillis and is certainly faster than it is on Windows.

The important thing to note is if you are trying to measure the aggregate of multiple sub-millisecond operations, you must use nanotime as if the operation finished in less than 1/1000th of a second your code, comparing currentTimeMillis will show the operation as instantaneous so 1,000 of these will still be instantaneous. What you might want to do is use nanotime then round to the nearest millisecond, so if an operation took 8000 nanoseconds it will be counted as 1 millisecond, not 0.

Solution 5 - Java

>What you might want to do is use nanotime then round to the nearest millisecond, so if an operation took 8000 nanoseconds it will be counted as 1 millisecond, not 0.

Arithmetic note:

8000 nanoseconds is 8 microseconds is 0.008 milliseconds. Rounding will take that to 0 milliseconds.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionFrithjofView Question on Stackoverflow
Solution 1 - JavaRohit JainView Answer on Stackoverflow
Solution 2 - JavaEelkeView Answer on Stackoverflow
Solution 3 - JavaMichael BorgwardtView Answer on Stackoverflow
Solution 4 - JavaWalt CoreyView Answer on Stackoverflow
Solution 5 - JavadaveView Answer on Stackoverflow