Why are we using "({ })" in jQuery?

JavascriptJqueryJson

Javascript Problem Overview


Why are we using ({ })?

Is it delegate?

What does it mean to use this syntax?

What are we wrapping with it?

For example:

$.ajaxSetup ({ // <-- THIS
    error: fError,
    compelete: fComp,
    success: fSucc
}); // <-- AND THIS

Javascript Solutions


Solution 1 - Javascript

{} is object notation in JavaScript. For example:

$('selector').plugin({ option1: 'value' });

In this case you're passing an object containing your settings to the plugin. The plugin can deal with this as a object, whatever it's referenced as, for example:

settings.option1 //the option you passed in.

Of course it has a lot more uses, but this is the most common example in jQuery. The same is true for the .animate(), $.ajax(), .css() functions, etc. Anything that takes properties generally uses this format.


As requested, some other examples:
Any object inside the passed object can be a function as well, not only properties, for example:

$("<input>", {
  type: "text",
  focusin: function() { alert("Hi, you focused me!"); }
});    

This would set the focus event of that input to have an alert. Another is extending an object, adding properties to it, like this:

var person = { first_name: "John" };
$.extend(person, { last_name: "Smith" });
//equivalent to: 
person.last_name = "Smith";
//or:
person["last_name"] = "Smith";

Now person has the last_name property. This is often used by plugins as well, to take the default settings, then merge any settings you passed in, overwriting with any settings you specified, using defaults for the rest.

Why are we using it? Well...that's how JavaScript works, and in the jQuery spirit: it's an extremely terse and flexible way to pass information.

Solution 2 - Javascript

>I mean, what we are wrapping it ?

No. That's JavaScript object notation (JSON). In your example you're invoking the function ajaxSetup with an object whose properties are:

error: fError,
compelete: fComp,
success: fSucc

For instance, to create an "user" object you could write:

user = { 
    "name":"Oscar", 
    "lastName":"Reyes"
};

And then use one of its attributes:

alert( a.name );

Shows: Oscar

What you see there (in your code) is the creation of an object and passing it as an argument.

It would be equivalent to:

var setUpInfo = {
    "error": fError,
    "compelete": fComp,
    "success": fSucc
};  

$.ajaxSetup( setUpInfo );

Solution 3 - Javascript

It is either a JavaScript object literal or more specifically JSON when it comes to sending parameters over Ajax. JSON is subset of JavaScript object literals.

For example:

// This is JSON data sent via the Ajax request (JSON is subset of JavaScript object literals)
var json = {id: 1, first_name: "John", last_name: "Smith"};

// This is a JavaScript object literal, it is not used for transfer of data so doesn't need to be JSON
var jsol = {type: 'POST', url: url, data: json};

$.ajax(jsol);

Please read more about it here:

Solution 4 - Javascript

The question was about the notation "({ })".

In this context, the parentheses "(...)" following an expression, such as $.ajaxSetup, causes the function specified by the expression to be called.

The expression inside the parentheses (which could be a comma separated list of expressions) results in a value (or a list of values) that is the argument(s) passed to the function.

Finally, when "{...}" is used in an expression context, it constructs an object with the name-value properties specified. This is like JSON but it is, more generally, any legal JS object literal.

Solution 5 - Javascript

If you mean in this context:

$("#theId").click( function() { /* body here */ } );

Then the ( function() {}) is an anonymous function. But without an example, can't be sure that's what you mean.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionuzay95View Question on Stackoverflow
Solution 1 - JavascriptNick CraverView Answer on Stackoverflow
Solution 2 - JavascriptOscarRyzView Answer on Stackoverflow
Solution 3 - JavascriptIvo SabevView Answer on Stackoverflow
Solution 4 - JavascriptdlaliberteView Answer on Stackoverflow
Solution 5 - JavascriptArmstrongestView Answer on Stackoverflow