How to get the mouse position without events (without moving the mouse)?

JavascriptMouseeventDom Events

Javascript Problem Overview


Is it possible to get the mouse position with JavaScript after page loads without any mouse movement event (without moving the mouse)?

Javascript Solutions


Solution 1 - Javascript

Real answer: No, it's not possible.

OK, I have just thought of a way. Overlay your page with a div that covers the whole document. Inside that, create (say) 2,000 x 2,000 <a> elements (so that the :hover pseudo-class will work in IE 6, see), each 1 pixel in size. Create a CSS :hover rule for those <a> elements that changes a property (let's say font-family). In your load handler, cycle through each of the 4 million <a> elements, checking currentStyle / getComputedStyle() until you find the one with the hover font. Extrapolate back from this element to get the co-ordinates within the document.

N.B. DON'T DO THIS.

Solution 2 - Javascript

Edit 2020: This does not work any more. It seems so, that the browser vendors patched this out. Because the most browsers rely on chromium, it might be in its core.

Old answer: You can also hook mouseenter (this event is fired after page reload, when the mousecursor is inside the page). Extending Corrupted's code should do the trick:

var x = null; var y = null;

document.addEventListener('mousemove', onMouseUpdate, false); document.addEventListener('mouseenter', onMouseUpdate, false);

function onMouseUpdate(e) { x = e.pageX; y = e.pageY; console.log(x, y); }

function getMouseX() { return x; }

function getMouseY() { return y; }

You can also set x and y to null on mouseleave-event. So you can check if the user is on your page with it's cursor.

Solution 3 - Javascript

What you can do is create variables for the x and y coordinates of your cursor, update them whenever the mouse moves and call a function on an interval to do what you need with the stored position.

The downside to this of course is that at least one initial movement of the mouse is required to have it work. As long as the cursor updates its position at least once, we are able to find its position regardless of whether it moves again.

var cursor_x = -1;
var cursor_y = -1;
document.onmousemove = function(event)
{
 cursor_x = event.pageX;
 cursor_y = event.pageY;
}
setInterval(check_cursor, 1000);
function check_cursor(){console.log('Cursor at: '+cursor_x+', '+cursor_y);}

The preceding code updates once a second with a message of where your cursor is. I hope this helps.

Solution 4 - Javascript

@Tim Down's answer is not performant if you render 2,000 x 2,000 <a> elements:

> OK, I have just thought of a way. Overlay your page with a div that > covers the whole document. Inside that, create (say) 2,000 x 2,000 > elements (so that the :hover pseudo-class will work in IE 6, see), > each 1 pixel in size. Create a CSS :hover rule for those elements > that changes a property (let's say font-family). In your load handler, > cycle through each of the 4 million elements, checking > currentStyle / getComputedStyle() until you find the one with the > hover font. Extrapolate back from this element to get the co-ordinates > within the document. > > N.B. DON'T DO THIS.

But you don't have to render 4 million elements at once, instead use binary search. Just use 4 <a> elements instead:

  • Step 1: Consider the whole screen as the starting search area
  • Step 2: Split the search area into 2 x 2 = 4 rectangle <a> elements
  • Step 3: Using the getComputedStyle() function determine in which rectangle mouse hovers
  • Step 4: Reduce the search area to that rectangle and repeat from step 2.

This way you would need to repeat these steps max 11 times, considering your screen is not wider than 2048px.

So you will generate max 11 x 4 = 44 <a> elements.

If you don't need to determine the mouse position exactly to a pixel, but say 10px precision is OK. You would repeat the steps at most 8 times, so you would need to draw max 8 x 4 = 32 <a> elements.

Also generating and then destroying the <a> elements is not performat as DOM is generally slow. Instead, you can just reuse the initial 4 <a> elements and just adjust their top, left, width and height as you loop through steps.

Now, creating 4 <a> is an overkill as well. Instead, you can reuse the same one <a> element for when testing for getComputedStyle() in each rectangle. So, instead of splitting the search area into 2 x 2 <a> elements just reuse a single <a> element by moving it with top and left style properties.

So, all you need is a single <a> element change its width and height max 11 times, and change its top and left max 44 times and you will have the exact mouse position.

Solution 5 - Javascript

You could try something similar to what Tim Down suggested - but instead of having elements for each pixel on the screen, create just 2-4 elements (boxes), and change their location, width, height dynamically to divide the yet possible locations on screen by 2-4 recursively, thus finding the mouse real location quickly.

For example - first elements take right and left half of screen, afterwards the upper and lower half. By now we already know in which quarter of screen the mouse is located, are able to repeat - discover which quarter of this space...

Solution 6 - Javascript

Here's my solution. It exports window.currentMouseX and window.currentMouseY properties you can use anywhere. It uses the position of a hovered element (if any) initially and afterwards listens to mouse movements to set the correct values.

(function () {
	window.currentMouseX = 0;
	window.currentMouseY = 0;

	// Guess the initial mouse position approximately if possible:
	var hoveredElement = document.querySelectorAll(':hover');
	hoveredElement = hoveredElement[hoveredElement.length - 1]; // Get the most specific hovered element

	if (hoveredElement != null) {
		var rect = hoveredElement.getBoundingClientRect();
        // Set the values from hovered element's position
		window.currentMouseX = window.scrollX + rect.x;
		window.currentMouseY = window.scrollY + rect.y;
	}

    // Listen for mouse movements to set the correct values
	window.addEventListener('mousemove', function (e) {
		window.currentMouseX = e.pageX;
		window.currentMouseY = e.pageY;
	}, /*useCapture=*/true);
}())

Composr CMS Source: https://github.com/ocproducts/composr/commit/a851c19f925be20bc16bfe016be42924989f262e#diff-b162dc9c35a97618a96748639ff41251R1202

Solution 7 - Javascript

The most simple solution but not 100% accurate

$(':hover').last().offset()

Result: {top: 148, left: 62.5}
The result depend on the nearest element size and return undefined when user switched the tab

Solution 8 - Javascript

Not mouse position, but, if you're looking for current cursor postion (for use cases like getting last typed character etc) then, below snippet works fine.
This will give you the cursor index related to text content.

window.getSelection().getRangeAt(0).startOffset

Solution 9 - Javascript

Yes, It's possible.

If you add "mouseover" event to the document it will fire instantly and you can get the mouse position, of course if mouse pointer was over the document.

   document.addEventListener('mouseover', setInitialMousePos, false);

   function setInitialMousePos( event ) {
       console.log( event.clientX, event.clientY);
       document.removeEventListener('mouseover', setInitialMousePos, false);
   }

Previously it was possible to read mouse position through window.event but it's deprecated now.

Solution 10 - Javascript

var x = 0;
var y = 0;

document.addEventListener('mousemove', onMouseMove, false)

function onMouseMove(e){
    x = e.clientX;
    y = e.clientY;
}

function getMouseX() {
    return x;
}

function getMouseY() {
    return y;
}

Solution 11 - Javascript

I implemented a horizontal/vertical search, (first make a div full of vertical line links arranged horizontally, then make a div full of horizontal line links arranged vertically, and simply see which one has the hover state) like Tim Down's idea above, and it works pretty fast. Sadly, does not work on Chrome 32 on KDE.

jsfiddle.net/5XzeE/4/

Solution 12 - Javascript

You do not have to move the mouse to get the cursor's location. The location is also reported on events other than mousemove. Here's a click-event as an example:

document.body.addEventListener('click',function(e)
{
	console.log("cursor-location: " + e.clientX + ',' + e.clientY);
});

Solution 13 - Javascript

Riffing on @SuperNova's answer, here's an approach using ES6 classes that keeps the context for this correct in your callback:

class Mouse {
  constructor() {
    this.x = 0;
    this.y = 0;
    this.callbacks = {
      mouseenter: [],
      mousemove: [],
    };
  }

  get xPos() {
    return this.x;
  }

  get yPos() {
    return this.y;
  }

  get position() {
    return `${this.x},${this.y}`;
  }

  addListener(type, callback) {
    document.addEventListener(type, this); // Pass `this` as the second arg to keep the context correct
    this.callbacks[type].push(callback);
  }

  // `handleEvent` is part of the browser's `EventListener` API.
  // https://developer.mozilla.org/en-US/docs/Web/API/EventListener/handleEvent
  handleEvent(event) {
    const isMousemove = event.type === 'mousemove';
    const isMouseenter = event.type === 'mouseenter';

    if (isMousemove || isMouseenter) {
      this.x = event.pageX;
      this.y = event.pageY;
    }

    this.callbacks[event.type].forEach((callback) => {
      callback();
    });
  }
}

const mouse = new Mouse();

mouse.addListener('mouseenter', () => console.log('mouseenter', mouse.position));
mouse.addListener('mousemove', () => console.log('mousemove A', mouse.position));
mouse.addListener('mousemove', () => console.log('mousemove B', mouse.position));

Solution 14 - Javascript

I envision that maybe you have a parent page with a timer and after a certain amount of time or a task is completed, you forward the user to a new page. Now you want the cursor position, and because they are waiting, they aren't necessarily touching the mouse. So track the mouse on the parent page using standard events and pass the last value to the new page in a get or a post variable.

You can use JHarding's code on your parent page so that the latest position is always available in a global variable:

var cursorX;
var cursorY;
document.onmousemove = function(e){
    cursorX = e.pageX;
    cursorY = e.pageY;
}

This won't help users that navigate to this page by means other than your parent page.

Solution 15 - Javascript

I think i may have a reasonable solution with out counting divs and pixels..lol

Simply use animation frame or a time interval of a function. you will still need a mouse event one time though just to initiate, but technically you position this where ever you like.

Essentially we are tracking a dummy div at all times with out mouse movement.

// create a div(#mydiv) 1px by 1px set opacity to 0 & position:absolute;

Below is the logic..

var x,y;


$('body').mousemove(function( e ) {

    var x = e.clientX - (window.innerWidth / 2);
    var y = e.clientY - (window.innerHeight / 2);
 }


function looping (){

   /* track my div position 60 x 60 seconds!
      with out the mouse after initiation you can still track the dummy div.x & y
      mouse doesn't need to move.*/

   $('#mydiv').x = x;    // css transform x and y to follow 
   $('#mydiv)'.y = y;

   console.log(#mydiv.x etc)

   requestAnimationFrame( looping , frame speed here);
}  

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionNorbert TamasView Question on Stackoverflow
Solution 1 - JavascriptTim DownView Answer on Stackoverflow
Solution 2 - JavascriptSuperNovaView Answer on Stackoverflow
Solution 3 - JavascriptJHardingView Answer on Stackoverflow
Solution 4 - JavascriptAlex PetersonView Answer on Stackoverflow
Solution 5 - JavascriptAlexTRView Answer on Stackoverflow
Solution 6 - JavascriptSalman von AbbasView Answer on Stackoverflow
Solution 7 - JavascriptStefansAryaView Answer on Stackoverflow
Solution 8 - JavascriptGorvGoylView Answer on Stackoverflow
Solution 9 - JavascriptMakanView Answer on Stackoverflow
Solution 10 - JavascriptCorruptedView Answer on Stackoverflow
Solution 11 - Javascriptuser2958613View Answer on Stackoverflow
Solution 12 - JavascriptLonnie BestView Answer on Stackoverflow
Solution 13 - JavascriptPatrick BerkeleyView Answer on Stackoverflow
Solution 14 - Javascriptuser2892032View Answer on Stackoverflow
Solution 15 - JavascriptjoshuaView Answer on Stackoverflow