What is the difference between "||" and "or" in Perl?

PerlOperators

Perl Problem Overview


What is the difference between the C-style operators &&, ||, ... and their Perl human-readable version "and", "or", ...?

It seems that Internet code uses them both:

open (FILE, $file) or die("cannot open $file");
open (FILE, $file) || die("cannot open $file");

Perl Solutions


Solution 1 - Perl

From Perl documentation:

OR

List operators

> On the right side of a list operator, it has very low precedence, such that it controls all comma-separated expressions found there. The only operators with lower precedence are the logical operators "and", "or", and "not", which may be used to evaluate calls to list operators without the need for extra parentheses.

Logical or, defined or, and exclusive or.

> Binary "or" returns the logical disjunction of the two surrounding expressions. It's equivalent to ||, except for the very low precedence. This makes it useful for control flow > > print FH $data or die "Can't write to FH: $!"; > > This means that it short-circuits: i.e., the right expression is evaluated only if the left expression is false. Due to its precedence, you should probably avoid using this for assignment, only for control flow. > > $a = $b or $c; # Bug: this is wrong
> ($a = $b) or $c; # Really means this
> $a = $b || $c; # Better written this way > > However, when it's a list-context assignment and you're trying to use "||" for control flow, you probably need "or" so that the assignment takes higher precedence. > > @info = stat($file) || die; # Oops, scalar sense of stat!
> @info = stat($file) or die; # Better, now @info gets its due > > Then again, you could always use parentheses.

||

> If any list operator (print(), etc.) or any unary operator (chdir(), etc.) is followed by a left parenthesis as the next token, the operator and arguments within parentheses are taken to be of highest precedence, just like a normal function call.


> For example, because named unary operators have higher precedence than ||: > > chdir $foo || die; # (chdir $foo) || die
> chdir($foo) || die; # (chdir $foo) || die
> chdir ($foo) || die; # (chdir $foo) || die
> chdir +($foo) || die; # (chdir $foo) || die

Solution 2 - Perl

!, &&, ||, and ^ have high precedence such that they are useful in constructing an expression; not, and, or, and xor have low precedence such that they are useful for flow control between what are essentially different expressions.

Solution 3 - Perl

The only difference is their precedence.

open  FILE,  $file  or die("cannot open $file");   # This works
open (FILE,  $file) or die("cannot open $file");   # ...because it means this
open  FILE,  $file  || die("cannot open $file");   # This doesn't work
open  FILE, ($file  || die("cannot open $file"));  # ...because it means this

Solution 4 - Perl

The "&&" and "||" operators have higher precedence than their "and", "or" counterparts.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionSteve SchneppView Question on Stackoverflow
Solution 1 - PerljoeView Answer on Stackoverflow
Solution 2 - PerlysthView Answer on Stackoverflow
Solution 3 - Perldave4420View Answer on Stackoverflow
Solution 4 - PerlInshallahView Answer on Stackoverflow