What is the bit size of long on 64-bit Windows?
C++CWindows64 BitPortingC++ Problem Overview
Not to long ago, someone told me that long are not 64 bits on 64 bit machines and I should always use int. This did not make sense to me. I have seen docs (such as the one on Apple's official site) say that long are indeed 64 bits when compiling for a 64-bit CPU. I looked up what it was on 64-bit Windows and found
> - Windows: long and int remain 32-bit in length, and special new data types
> are defined for 64-bit integers.
(from http://www.intel.com/cd/ids/developer/asmo-na/eng/197664.htm?page=2)
What should I use? Should I define something like uw, sw ((un)signed width) as a long if not on Windows, and otherwise do a check on the target CPU bitsize?
C++ Solutions
Solution 1 - C++
In the Unix world, there were a few possible arrangements for the sizes of integers and pointers for 64-bit platforms. The two mostly widely used were ILP64 (actually, only a very few examples of this; Cray was one such) and LP64 (for almost everything else). The acronynms come from 'int, long, pointers are 64-bit' and 'long, pointers are 64-bit'.
Type ILP64 LP64 LLP64
char 8 8 8
short 16 16 16
int 64 32 32
long 64 64 32
long long 64 64 64
pointer 64 64 64
The ILP64 system was abandoned in favour of LP64 (that is, almost all later entrants used LP64, based on the recommendations of the Aspen group; only systems with a long heritage of 64-bit operation use a different scheme). All modern 64-bit Unix systems use LP64. MacOS X and Linux are both modern 64-bit systems.
Microsoft uses a different scheme for transitioning to 64-bit: LLP64 ('long long, pointers are 64-bit'). This has the merit of meaning that 32-bit software can be recompiled without change. It has the demerit of being different from what everyone else does, and also requires code to be revised to exploit 64-bit capacities. There always was revision necessary; it was just a different set of revisions from the ones needed on Unix platforms.
If you design your software around platform-neutral integer type names, probably using the C99 <inttypes.h> header, which, when the types are available on the platform, provides, in signed (listed) and unsigned (not listed; prefix with 'u'):
int8_t- 8-bit integersint16_t- 16-bit integersint32_t- 32-bit integersint64_t- 64-bit integersuintptr_t- unsigned integers big enough to hold pointersintmax_t- biggest size of integer on the platform (might be larger thanint64_t)
You can then code your application using these types where it matters, and being very careful with system types (which might be different). There is an intptr_t type - a signed integer type for holding pointers; you should plan on not using it, or only using it as the result of a subtraction of two uintptr_t values (ptrdiff_t).
But, as the question points out (in disbelief), there are different systems for the sizes of the integer data types on 64-bit machines. Get used to it; the world isn't going to change.
Solution 2 - C++
It is not clear if the question is about the Microsoft C++ compiler or the Windows API. However, there is no [c++] tag so I assume it is about the Windows API. Some of the answers have suffered from link rot so I am providing yet another link that can rot.
For information about Windows API types like INT, LONG etc. there is a page on MSDN:
The information is also available in various Windows header files like WinDef.h. I have listed a few relevant types here:
Type | S/U | x86 | x64 ----------------------------+-----+--------+------- BYTE, BOOLEAN | U | 8 bit | 8 bit ----------------------------+-----+--------+------- SHORT | S | 16 bit | 16 bit USHORT, WORD | U | 16 bit | 16 bit ----------------------------+-----+--------+------- INT, LONG | S | 32 bit | 32 bit UINT, ULONG, DWORD | U | 32 bit | 32 bit ----------------------------+-----+--------+------- INT_PTR, LONG_PTR, LPARAM | S | 32 bit | 64 bit UINT_PTR, ULONG_PTR, WPARAM | U | 32 bit | 64 bit ----------------------------+-----+--------+------- LONGLONG | S | 64 bit | 64 bit ULONGLONG, QWORD | U | 64 bit | 64 bit
The column "S/U" denotes signed/unsigned.
Solution 3 - C++
This article on MSDN references a number of type aliases (available on Windows) that are a bit more explicit with respect to their width:
http://msdn.microsoft.com/en-us/library/aa505945.aspx
For instance, although you can use ULONGLONG to reference a 64-bit unsigned integral value, you can also use UINT64. (The same goes for ULONG and UINT32.) Perhaps these will be a bit clearer?
Solution 4 - C++
Microsoft has also defined UINT_PTR and INT_PTR for integers that are the same size as a pointer.
Here is a list of Microsoft specific types - it's part of their driver reference, but I believe it's valid for general programming as well.
Solution 5 - C++
The easiest way to get to know it for your compiler/platform:
#include <iostream>
int main() {
std::cout << sizeof(long)*8 << std::endl;
}
Themultiplication by 8 is to get bits from bytes.
When you need a particular size, it is often easiest to use one of the predefined types of a library. If that is undesirable, you can do what often happens with autoconf software and have the configuration system determine the right type for the needed size.
Solution 6 - C++
The size of long on Windows platforms is 32 bits (4 bytes).
You can check this using sizeof(long), which returns the size in bytes.
Solution 7 - C++
If you need to use integers of certain length, you probably should use some platform independent headers to help you. Boost is a good place to look at.