Verify External Script Is Loaded

JavascriptJqueryasp.net

Javascript Problem Overview


I'm creating a jquery plugin and I want to verify an external script is loaded. This is for an internal web app and I can keep the script name/location consistent(mysscript.js). This is also an ajaxy plugin that can be called on many times on the page.

If I can verify the script is not loaded I'll load it using:

jQuery.getScript()

How can I verify the script is loaded because I don't want the same script loaded on the page more than once? Is this something that I shouldn't need to worry about due to caching of the script?

Update: I may not have control over who uses this plugin in our organization and may not be able to enforce that the script is not already on the page with or without a specific ID, but the script name will always be in the same place with the same name. I'm hoping I can use the name of the script to verify it's actually loaded.

Javascript Solutions


Solution 1 - Javascript

If the script creates any variables or functions in the global space you can check for their existance:

External JS (in global scope) --

var myCustomFlag = true;

And to check if this has run:

if (typeof window.myCustomFlag == 'undefined') {
    //the flag was not found, so the code has not run
    $.getScript('<external JS>');
}

#Update

You can check for the existence of the <script> tag in question by selecting all of the <script> elements and checking their src attributes:

//get the number of `<script>` elements that have the correct `src` attribute
var len = $('script').filter(function () {
    return ($(this).attr('src') == '<external JS>');
}).length;

//if there are no scripts that match, the load it
if (len === 0) {
    $.getScript('<external JS>');
}

Or you can just bake this .filter() functionality right into the selector:

var len = $('script[src="<external JS>"]').length;

Solution 2 - Javascript

Few too many answers on this one, but I feel it's worth adding this solution. It combines a few different answers.

Key points for me were

  • add an #id tag, so it's easy to find, and not duplicate

  • Use .onload() to wait until the script has finished loading before using it

     mounted() {
       // First check if the script already exists on the dom
       // by searching for an id
       let id = 'googleMaps'
       if(document.getElementById(id) === null) {
         let script = document.createElement('script')
         script.setAttribute('src', 'https://maps.googleapis.com/maps/api/js?key=' + apiKey)
         script.setAttribute('id', id)
         document.body.appendChild(script) 
    
         // now wait for it to load...
         script.onload = () => {
             // script has loaded, you can now use it safely
             alert('thank me later')
             // ... do something with the newly loaded script
         }      
       }
     }
    

Solution 3 - Javascript

@jasper's answer is totally correct but with modern browsers, a standard Javascript solution could be:

function isScriptLoaded(src)
{
    return Boolean(document.querySelector('script[src="' + src + '"]'));
}

UPDATE July 2021:

The accepted solutions above have changed & improved much over time. The scope of my previous answer above was only to detect if the script was inserted in the document to load (and not whether the script has actually finished loading).

To detect if the script has already loaded, I use the following method (in general):
  1. Create a common library function to dynamically load all scripts.
  2. Before loading, it uses the isScriptLoaded(src) function above to check whether the script has already been added (say, by another module).
  3. I use something like the following loadScript() function to load the script that uses callback functions to inform the calling modules if the script finished loading successfully.
  4. I also use additional logic to retry when script loading fails (in case of temporary network issues).
    1. Retry is done by removing the <script> tag from the body and adding it again.
    2. If it still fails to load after configured number of retries, the <script> tag is removed from the body.
    3. I have removed that logic from the following code for simplicity. It should be easy to add.

/** 
 * Mark/store the script as fully loaded in a global variable.
 * @param src URL of the script
 */
function markScriptFullyLoaded(src) {
	window.scriptLoadMap[src] = true;
}

/** 
 * Returns true if the script has been added to the page
 * @param src URL of the script
 */
function isScriptAdded(src) {
	return Boolean(document.querySelector('script[src="' + src + '"]'));
}

/** 
 * Returns true if the script has been fully loaded
 * @param src URL of the script
 */
function isScriptFullyLoaded(src) {
	return src in window.scriptLoadMap && window.scriptLoadMap[src];
}

/** 
 * Load a script. 
 * @param src URL of the script
 * @param onLoadCallback Callback function when the script is fully loaded
 * @param onLoadErrorCallback Callback function when the script fails to load
 * @param retryCount How many times retry laoding the script? (Not implimented here. Logic goes into js.onerror function)
 */
function loadScript(src, onLoadCallback, onLoadErrorCallback, retryCount) {
	if (!src) return;
	
	// Check if the script is already loaded
	if ( isScriptAdded(src) )
	{
		// If script already loaded successfully, trigger the callback function
		if (isScriptFullyLoaded(src)) onLoadCallback();
		
		console.warn("Script already loaded. Skipping: ", src);
		return;
	}

	// Loading the script...
	const js = document.createElement('script');
	js.setAttribute("async", "");
	js.src = src;
	
	js.onload = () => {
		markScriptFullyLoaded(src)
		
		// Optional callback on script load
		if (onLoadCallback) onLoadCallback();
	};
	
	js.onerror = () => {
		// Remove the script node (to be able to try again later)
		const js2 = document.querySelector('script[src="' + src +'"]');
		js2.parentNode.removeChild(js2);
		
		// Optional callback on script load failure
		if (onLoadErrorCallback) onLoadErrorCallback();
	};

	document.head.appendChild(js);
}

Solution 4 - Javascript

This was very simple now that I realize how to do it, thanks to all the answers for leading me to the solution. I had to abandon $.getScript() in order to specify the source of the script...sometimes doing things manually is best.

Solution

//great suggestion @Jasper
var len = $('script[src*="Javascript/MyScript.js"]').length; 

if (len === 0) {
        alert('script not loaded');

        loadScript('Javascript/MyScript.js');

        if ($('script[src*="Javascript/MyScript.js"]').length === 0) {
            alert('still not loaded');
        }
        else {
            alert('loaded now');
        }
    }
    else {
        alert('script loaded');
    }


function loadScript(scriptLocationAndName) {
    var head = document.getElementsByTagName('head')[0];
    var script = document.createElement('script');
    script.type = 'text/javascript';
    script.src = scriptLocationAndName;
    head.appendChild(script);
}

Solution 5 - Javascript

Create the script tag with a specific ID and then check if that ID exists?

Alternatively, loop through script tags checking for the script 'src' and make sure those are not already loaded with the same value as the one you want to avoid ?

Edit: following feedback that a code example would be useful:

(function(){
    var desiredSource = 'https://sitename.com/js/script.js';
    var scripts       = document.getElementsByTagName('script');
    var alreadyLoaded = false;

    if(scripts.length){
        for(var scriptIndex in scripts) {
            if(!alreadyLoaded && desiredSource === scripts[scriptIndex].src) {
                alreadyLoaded = true;
            }
        }
    }
    if(!alreadyLoaded){
        // Run your code in this block?
    }
})();

As mentioned in the comments (https://stackoverflow.com/users/1358777/alwin-kesler), this may be an alternative (not benchmarked):

(function(){
    var desiredSource = 'https://sitename.com/js/script.js';
    var scripts = document.getElementsByTagName('script');
    var alreadyLoaded = false;

    for(var scriptIndex in document.scripts) {
        if(!alreadyLoaded && desiredSource === scripts[scriptIndex].src) {
            alreadyLoaded = true;
        }
    }
    if(!alreadyLoaded){
        // Run your code in this block?
    }
})();

Solution 6 - Javascript

I think it's better to use window.addEventListener('error') to capture the script load error and try to load it again. It's useful when we load scripts from a CDN server. If we can't load script from the CDN, we can load it from our server.

window.addEventListener('error', function(e) {
  if (e.target.nodeName === 'SCRIPT') {
    var scriptTag = document.createElement('script');
    scriptTag.src = e.target.src.replace('https://static.cdn.com/', '/our-server/static/');
    document.head.appendChild(scriptTag);
  }
}, true);

Solution 7 - Javascript

Simply check if the global variable is available, if not check again. In order to prevent the maximum callstack being exceeded set a 100ms timeout on the check:

function check_script_loaded(glob_var) {
    if(typeof(glob_var) !== 'undefined') {
    // do your thing
    } else {
    setTimeout(function() {
    check_script_loaded(glob_var)
    }, 100)
    }
}

Solution 8 - Javascript

Another way to check an external script is loaded or not, you can use data function of jquery and store a validation flag. Example as :

if(!$("body").data("google-map"))
	{
		console.log("no js");
		
		$.getScript("https://maps.googleapis.com/maps/api/js?v=3.exp&sensor=false&callback=initilize",function(){
			$("body").data("google-map",true);
			
			},function(){
				alert("error while loading script");
			});
		}
	}
	else
	{
		console.log("js already loaded");
	}

Solution 9 - Javascript

Merging several answers from above into an easy to use function

function GetScriptIfNotLoaded(scriptLocationAndName)
{
  var len = $('script[src*="' + scriptLocationAndName +'"]').length;

  //script already loaded!
  if (len > 0)
      return;

  var head = document.getElementsByTagName('head')[0];
  var script = document.createElement('script');
  script.type = 'text/javascript';
  script.src = scriptLocationAndName;
  head.appendChild(script);
}

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
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Solution 1 - JavascriptJasperView Answer on Stackoverflow
Solution 2 - JavascriptcomfytodayView Answer on Stackoverflow
Solution 3 - JavascriptAbhishekView Answer on Stackoverflow
Solution 4 - JavascriptAGoodDisplayNameView Answer on Stackoverflow
Solution 5 - JavascriptMyStreamView Answer on Stackoverflow
Solution 6 - JavascriptDukeView Answer on Stackoverflow
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Solution 9 - JavascriptAaron ShermanView Answer on Stackoverflow