UIImageView - How to get the file name of the image assigned?

IosObjective CSwiftUiimageviewUiimage

Ios Problem Overview


Is it possible to read the name of an UIImageView's UIImage that's presently stored in the UIImageView?

I was hoping you could do something kind of like this, but haven't figured it out.

NSString *currentImageName = [MyIImageView getFileName];

Ios Solutions


Solution 1 - Ios

you can use setAccessibilityIdentifier method for any subclass of UIView

UIImageView *image ;
[image setAccessibilityIdentifier:@"file name"] ;

NSString *file_name = [image accessibilityIdentifier] ;

Solution 2 - Ios

Nope. You can't do that.

The reason is that a UIImageView instance does not store an image file. It stores a displays a UIImage instance. When you make an image from a file, you do something like this:

UIImage *picture = [UIImage imageNamed:@"myFile.png"];

Once this is done, there is no longer any reference to the filename. The UIImage instance contains the data, regardless of where it got it. Thus, the UIImageView couldn't possibly know the filename.

Also, even if you could, you would never get filename info from a view. That breaks MVC.

Solution 3 - Ios

No no no… in general these things are possible. It'll just make you feel like a dirty person. If you absolutely must, do this:

I can verify that this works, with the caveat that you can't get the names of UIImage's loaded in NIBs. It appears that images loaded from NIBs are not created through any standard function calls, so it's really a mystery to me.

I'm leaving the implementation up to you. Copy-pasting code that screws with the Objective-C runtime is a very bad idea, so think carefully about your project's needs and implement this only if you must.

Solution 4 - Ios

There is no native way to do this; however, you could easily create this behavior yourself.

You can subclass UIImageView and add a new instance variable:

NSString* imageFileName;

Then you could override setImage, first setting imageFileName to the filename of the image you're setting, and then calling [super setImage:imageFileName]. Something like this:

-(void) setImage:(NSString*)fileName
{
   imageFileName = fileName;
   [super setImage:fileName];
}

Just because it can't be done natively doesn't mean it isn't possible :)

Solution 5 - Ios

if ([imageForCheckMark.image isEqual:[UIImage imageNamed:@"crossCheckMark.png"]]||[imageForCheckMark.image isEqual:[UIImage imageNamed:@"checkMark.png"]])
{

}
              
                    
                

Solution 6 - Ios

Nope. No way to do that natively. You're going to have to subclass UIImageView, and add an imageFileName property (which you set when you set the image).

Solution 7 - Ios

Neither UIImageView not UIImage holds on to the filename of the image loaded.

You can either

1: (as suggested by Kenny Winker above) subclass UIImageView to have a fileName property or

2: name the image files with numbers (image1.jpg, image2.jpg etc) and tag those images with the corresponding number (tag=1 for image1.jpg, tag=2 for image2.jpg etc) or

3: Have a class level variable (eg. NSString *currentFileName) which updates whenever you update the UIImageView's image

Solution 8 - Ios

Or you can use the restoration identifier, like this:

let myImageView = UIImageView()
myImageView.image = UIImage(named: "anyImage")
myImageView.restorationIdentifier = "anyImage" // Same name as image's name!

// Later, in UI Tests:
print(myImageView.restorationIdentifier!) // Prints "anyImage"

Basically in this solution you're using the restoration identifier to hold the image's name, so you can use it later anywhere. If you update the image, you must also update the restoration identifier, like this:

myImageView.restorationIdentifier = "newImageName"

I hope that helps you, good luck!

Solution 9 - Ios

This code will help you out:-

- (NSString *)getFileName:(UIImageView *)imgView{
    NSString *imgName = [imgView image].accessibilityIdentifier;
    NSLog(@"%@",imgName);
    return imgName;
}

Use this as:-

NSString *currentImageName = [self getFileName:MyIImageView];

Solution 10 - Ios

You can use objective c Runtime feature for associating imagename with the UImageView.

First import #import <objc/runtime.h> in your class

then implement your code as below :

NSString *filename = @"exampleImage";
UIImage *image = [UIImage imagedName:filename];
objc_setAssociatedObject(image, "imageFilename", filename, OBJC_ASSOCIATION_COPY);
UIImageView *imageView = [[UIImageView alloc] initWithImage:image];
//You can then get the image later:
NSString *filename = objc_getAssociatedObject(imageView, "imageFilename");

Hope it helps you.

Solution 11 - Ios

Yes you can compare with the help of data like below code

UITableViewCell *cell = (UITableViewCell*)[self.view viewWithTag:indexPath.row + 100];

UIImage *secondImage = [UIImage imageNamed:@"boxhover.png"];

NSData *imgData1 = UIImagePNGRepresentation(cell.imageView.image);
NSData *imgData2 = UIImagePNGRepresentation(secondImage);

BOOL isCompare =  [imgData1 isEqual:imgData2];
if(isCompare)
{
    //contain same image
    cell.imageView.image = [UIImage imageNamed:@"box.png"];
}
else
{
    //does not contain same image
    cell.imageView.image = secondImage;
}

Solution 12 - Ios

Get image name Swift 4.2

There is a way if you want to compare button image names that you have in assets.

@IBOutlet weak var extraShotCheckbox: UIButton!

@IBAction func extraShotCheckBoxAction(_ sender: Any) {
    extraShotCheckbox.setImage(changeCheckBoxImage(button: extraShotCheckbox), for: .normal)
}

func changeCheckBoxImage(button: UIButton) -> UIImage {
    if let imageView = button.imageView, let image = imageView.image {
        if image == UIImage(named: "checkboxGrayOn") {
            return UIImage(named: "checkbox")!
        } else {
            return UIImage(named: "checkboxGrayOn")!
        }
    }
    return UIImage()
}

Solution 13 - Ios

Swift 3

First set the accessibilityIdentifier as imageName

myImageView.image?.accessibilityIdentifier = "add-image"

Then Use the following code.

extension UIImageView {
  func getFileName() -> String? {
    // First set accessibilityIdentifier of image before calling.
    let imgName = self.image?.accessibilityIdentifier
    return imgName
  }
}

Finally, The calling way of method to identify

myImageView.getFileName()

Solution 14 - Ios

I have deal with this problem, I have been solved it by MVC design pattern, I created Card class:

@interface Card : NSObject

@property (strong,nonatomic) UIImage* img;

@property  (strong,nonatomic) NSString* url;

@end

//then in the UIViewController in the DidLoad Method to Do :

// init Cards
Card* card10= [[Card alloc]init];
card10.url=@"image.jpg";  
card10.img = [UIImage imageNamed:[card10 url]];

// for Example

UIImageView * myImageView = [[UIImageView alloc]initWithImage:card10.img];
[self.view addSubview:myImageView];

//may you want to check the image name , so you can do this:

//for example

 NSString * str = @"image.jpg";
 
 if([str isEqualToString: [card10 url]]){
 // your code here
 }

Solution 15 - Ios

use below

 UIImageView *imageView = ((UIImageView *)(barButtonItem.customView.subviews.lastObject));
 file_name = imageView.accessibilityLabel;

Solution 16 - Ios

The code is work in swift3 - write code inside didFinishPickingMediaWithInfo delegate method:

if let referenceUrl = info[UIImagePickerControllerReferenceURL] as? NSURL {
  ALAssetsLibrary().asset(for: referenceUrl as URL!, resultBlock: { asset in

  let fileName = asset?.defaultRepresentation().filename()
  print(fileName!)

  //do whatever with your file name            
  }, failureBlock: nil)
}

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionKuberchaunView Question on Stackoverflow
Solution 1 - IosNizar AhmedView Answer on Stackoverflow
Solution 2 - IosJonathan SterlingView Answer on Stackoverflow
Solution 3 - IosBen GotowView Answer on Stackoverflow
Solution 4 - IosWendiKiddView Answer on Stackoverflow
Solution 5 - IosiEinsteinView Answer on Stackoverflow
Solution 6 - IosKenny WinkerView Answer on Stackoverflow
Solution 7 - IosMihir MathuriaView Answer on Stackoverflow
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