Test class with a new() call in it with Mockito

JavaUnit TestingJunitMockito

Java Problem Overview


I have a legacy class that contains a new() call to instantiate a LoginContext object:

public class TestedClass {
  public LoginContext login(String user, String password) {
    LoginContext lc = new LoginContext("login", callbackHandler);
  }
}

I want to test this class using Mockito to mock the LoginContext as it requires that the JAAS security stuff be set up before instantiating, but I'm not sure how to do that without changing the login() method to externalize the LoginContext.

Is it possible using Mockito to mock the LoginContext class?

Java Solutions


Solution 1 - Java

For the future I would recommend Eran Harel's answer (refactoring moving new to factory that can be mocked). But if you don't want to change the original source code, use very handy and unique feature: spies. From the documentation:

> You can create spies of real objects. When you use the spy then the real methods are called (unless a method was stubbed). > > Real spies should be used carefully and occasionally, for example when dealing with legacy code.

In your case you should write:

TestedClass tc = spy(new TestedClass());
LoginContext lcMock = mock(LoginContext.class);
when(tc.login(anyString(), anyString())).thenReturn(lcMock);

Solution 2 - Java

I am all for Eran Harel's solution and in cases where it isn't possible, Tomasz Nurkiewicz's suggestion for spying is excellent. However, it's worth noting that there are situations where neither would apply. E.g. if the login method was a bit "beefier":

public class TestedClass {
    public LoginContext login(String user, String password) {
        LoginContext lc = new LoginContext("login", callbackHandler);
        lc.doThis();
        lc.doThat();
        return lc;
    }
}

... and this was old code that could not be refactored to extract the initialization of a new LoginContext to its own method and apply one of the aforementioned solutions.

For completeness' sake, it's worth mentioning a third technique - using PowerMock to inject the mock object when the new operator is called. PowerMock isn't a silver bullet, though. It works by applying byte-code manipulation on the classes it mocks, which could be dodgy practice if the tested classes employ byte code manipulation or reflection and at least from my personal experience, has been known to introduce a performance hit to the test. Then again, if there are no other options, the only option must be the good option:

@RunWith(PowerMockRunner.class)
@PrepareForTest(TestedClass.class)
public class TestedClassTest {

    @Test
    public void testLogin() {
        LoginContext lcMock = mock(LoginContext.class);
        whenNew(LoginContext.class).withArguments(anyString(), anyString()).thenReturn(lcMock);
        TestedClass tc = new TestedClass();
        tc.login ("something", "something else");
        // test the login's logic
    }
}

Solution 3 - Java

You can use a factory to create the login context. Then you can mock the factory and return whatever you want for your test.

public class TestedClass {
  private final LoginContextFactory loginContextFactory;

  public TestedClass(final LoginContextFactory loginContextFactory) {
    this.loginContextFactory = loginContextFactory;
  }

  public LoginContext login(String user, String password) {
    LoginContext lc = loginContextFactory.createLoginContext();
  }
}

public interface LoginContextFactory {
  public LoginContext createLoginContext();
}

Solution 4 - Java

    public class TestedClass {
    public LoginContext login(String user, String password) {
        LoginContext lc = new LoginContext("login", callbackHandler);
        lc.doThis();
        lc.doThat();
    }
  }

-- Test Class:

    @RunWith(PowerMockRunner.class)
    @PrepareForTest(TestedClass.class)
    public class TestedClassTest {
    
        @Test
        public void testLogin() {
            LoginContext lcMock = mock(LoginContext.class);
            whenNew(LoginContext.class).withArguments(anyString(), anyString()).thenReturn(lcMock);
//comment: this is giving mock object ( lcMock )
            TestedClass tc = new TestedClass();
            tc.login ("something", "something else"); ///  testing this method.
            // test the login's logic
        }
    }

When calling the actual method tc.login ("something", "something else"); from the testLogin() {

  • This LoginContext lc is set to null and throwing NPE while calling lc.doThis();

Solution 5 - Java

Not that I know of, but what about doing something like this when you create an instance of TestedClass that you want to test:

TestedClass toTest = new TestedClass() {
    public LoginContext login(String user, String password) {
        //return mocked LoginContext
    }
};

Another option would be to use Mockito to create an instance of TestedClass and let the mocked instance return a LoginContext.

Solution 6 - Java

In situations where the class under test can be modified and when it's desirable to avoid byte code manipulation, to keep things fast or to minimise third party dependencies, here is my take on the use of a factory to extract the new operation.

public class TestedClass {

    interface PojoFactory { Pojo getNewPojo(); }

    private final PojoFactory factory;

    /** For use in production - nothing needs to change. */
    public TestedClass() {
        this.factory = new PojoFactory() {
            @Override
            public Pojo getNewPojo() {
                return new Pojo();
            }
        };
    }

    /** For use in testing - provide a pojo factory. */
    public TestedClass(PojoFactory factory) {
        this.factory = factory;
    }

    public void doSomething() {
        Pojo pojo = this.factory.getNewPojo();
        anythingCouldHappen(pojo);
    }
}

With this in place, your testing, asserts and verify calls on the Pojo object are easy:

public  void testSomething() {
    Pojo testPojo = new Pojo();
    TestedClass target = new TestedClass(new TestedClass.PojoFactory() {
                @Override
                public Pojo getNewPojo() {
                    return testPojo;
                }
            });
    target.doSomething();
    assertThat(testPojo.isLifeStillBeautiful(), is(true));
}

The only downside to this approach potentially arises if TestClass has multiple constructors which you'd have to duplicate with the extra parameter.

For SOLID reasons you'd probably want to put the PojoFactory interface onto the Pojo class instead, and the production factory as well.

public class Pojo {

    interface PojoFactory { Pojo getNewPojo(); }

    public static final PojoFactory productionFactory = 
        new PojoFactory() {
            @Override 
            public Pojo getNewPojo() {
                return new Pojo();
            }
        };

Solution 7 - Java

I happened to be in a particular situation where my usecase resembled the one of Mureinik but I ended-up using the solution of Tomasz Nurkiewicz.

Here is how:

class TestedClass extends AARRGGHH {
    public LoginContext login(String user, String password) {
        LoginContext lc = new LoginContext("login", callbackHandler);
        lc.doThis();
        lc.doThat();
        return lc;
    }
}

Now, PowerMockRunner failed to initialize TestedClass because it extends AARRGGHH, which in turn does more contextual initialization... You see where this path was leading me: I would have needed to mock on several layers. Clearly a HUGE smell.

I found a nice hack with minimal refactoring of TestedClass: I created a small method

LoginContext initLoginContext(String login, CallbackHandler callbackHandler) {
    new lc = new LoginContext(login, callbackHandler);
}

The scope of this method is necessarily package.

Then your test stub will look like:

LoginContext lcMock = mock(LoginContext.class)
TestedClass testClass = spy(new TestedClass(withAllNeededArgs))
doReturn(lcMock)
    .when(testClass)
    .initLoginContext("login", callbackHandler)

and the trick is done...

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionbwobbonesView Question on Stackoverflow
Solution 1 - JavaTomasz NurkiewiczView Answer on Stackoverflow
Solution 2 - JavaMureinikView Answer on Stackoverflow
Solution 3 - JavaEran HarelView Answer on Stackoverflow
Solution 4 - JavasunjavaxView Answer on Stackoverflow
Solution 5 - JavaKajView Answer on Stackoverflow
Solution 6 - JavaAdamView Answer on Stackoverflow
Solution 7 - Javaavi.elkharratView Answer on Stackoverflow