Can Mockito stub a method without regard to the argument?

JavaUnit TestingMockingMockito

Java Problem Overview


I'm trying to test some legacy code, using Mockito.

I want to stub a FooDao that is used in production as follows:

foo = fooDao.getBar(new Bazoo());

I can write:

when(fooDao.getBar(new Bazoo())).thenReturn(myFoo);

But the obvious problem is that getBar() is never called with the same Bazoo object that I stubbed the method for. (Curse that new operator!)

I would love it if I could stub the method in a way that it returns myFoo regardless of the argument. Failing that, I'll listen to other workaround suggestions, but I'd really like to avoid changing the production code until there is reasonable test coverage.

Java Solutions


Solution 1 - Java

when(
  fooDao.getBar(
    any(Bazoo.class)
  )
).thenReturn(myFoo);

or (to avoid nulls):

when(
  fooDao.getBar(
    (Bazoo)notNull()
  )
).thenReturn(myFoo);

Don't forget to import matchers (many others are available):

For Mockito 2.1.0 and newer:

import static org.mockito.ArgumentMatchers.*;

For older versions:

import static org.mockito.Matchers.*;

Solution 2 - Java

http://site.mockito.org/mockito/docs/1.10.19/org/mockito/Matchers.html

anyObject() should fit your needs.

Also, you can always consider implementing hashCode() and equals() for the Bazoo class. This would make your code example work the way you want.

Solution 3 - Java

Use like this:

when(
  fooDao.getBar(
    Matchers.<Bazoo>any()
  )
).thenReturn(myFoo);

Before you need to import Mockito.Matchers

Solution 4 - Java

Another option is to rely on good old fashion equals method. As long as the argument in the when mock equals the argument in the code being tested, then Mockito will match the mock.

Here is an example.

public class MyPojo {

    public MyPojo( String someField ) {
        this.someField = someField;
    }

    private String someField;

    @Override
    public boolean equals( Object o ) {
        if ( this == o ) return true;
        if ( o == null || getClass() != o.getClass() ) return false;
        MyPojo myPojo = ( MyPojo ) o;
        return someField.equals( myPojo.someField );
    }
    
}

then, assuming you know what the value for someField will be, you can mock it like this.

when(fooDao.getBar(new MyPojo(expectedSomeField))).thenReturn(myFoo);

pros: This is more explicit then any matchers. As a reviewer of code, I keep an eye open for any in the code junior developers write, as it glances over their code's logic to generate the appropriate object being passed.

con: Sometimes the field being passed to the object is a random ID. For this case you cannot easily construct the expected argument object in your mock code.

Another possible approach is to use Mockito's Answer object that can be used with the when method. Answer lets you intercept the actual call and inspect the input argument and return a mock object. In the example below I am using any to catch any request to the method being mocked. But then in the Answer lambda, I can further inspect the Bazo argument... maybe to verify that a proper ID was passed to it. I prefer this over any by itself so that at least some inspection is done on the argument.

	Bar mockBar = //generate mock Bar.

	when(fooDao.getBar(any(Bazo.class))
	.thenAnswer(  ( InvocationOnMock invocationOnMock) -> {
		Bazo actualBazo = invocationOnMock.getArgument( 0 );

		//inspect the actualBazo here and thrw exception if it does not meet your testing requirements.
		return mockBar;
	} );

So to sum it all up, I like relying on equals (where the expected argument and actual argument should be equal to each other) and if equals is not possible (due to not being able to predict the actual argument's state), I'll resort to Answer to inspect the argument.

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionEric WilsonView Question on Stackoverflow
Solution 1 - JavaTomasz NurkiewiczView Answer on Stackoverflow
Solution 2 - JavaBuhbView Answer on Stackoverflow
Solution 3 - Javauser3975308View Answer on Stackoverflow
Solution 4 - JavaJose MartinezView Answer on Stackoverflow