Specify custom Date format for colClasses argument in read.table/read.csv

RDateread.tableread.csv

R Problem Overview


Question:

Is there a way to specify the Date format when using the colClasses argument in read.table/read.csv?

(I realise I can convert after importing, but with many date columns like this, it would be easier to do it in the import step)


Example:

I have a .csv with date columns in the format %d/%m/%Y.

dataImport <- read.csv("data.csv", colClasses = c("factor","factor","Date"))

This gets the conversion wrong. For example, 15/07/2008 becomes 0015-07-20.


Reproducible code:

data <- 
structure(list(func_loc = structure(c(1L, 2L, 3L, 3L, 3L, 3L, 
3L, 4L, 4L, 5L), .Label = c("3076WAG0003", "3076WAG0004", "3076WAG0007", 
"3076WAG0009", "3076WAG0010"), class = "factor"), order_type = structure(c(3L, 
3L, 1L, 1L, 1L, 1L, 2L, 2L, 3L, 1L), .Label = c("PM01", "PM02", 
"PM03"), class = "factor"), actual_finish = structure(c(4L, 6L, 
1L, 2L, 3L, 7L, 1L, 8L, 1L, 5L), .Label = c("", "11/03/2008", 
"14/08/2008", "15/07/2008", "17/03/2008", "19/01/2009", "22/09/2008", 
"6/09/2007"), class = "factor")), .Names = c("func_loc", "order_type", 
"actual_finish"), row.names = c(NA, 10L), class = "data.frame")
                                                        
                                                        
write.csv(data,"data.csv", row.names = F)                                                        
                                             
dataImport <- read.csv("data.csv")
str(dataImport)
dataImport

dataImport <- read.csv("data.csv", colClasses = c("factor","factor","Date"))
str(dataImport)
dataImport

And here's what the output looks like:

code output

R Solutions


Solution 1 - R

You can write your own function that accepts a string and converts it to a Date using the format you want, then use the setAs to set it as an as method. Then you can use your function as part of the colClasses.

Try:

setAs("character","myDate", function(from) as.Date(from, format="%d/%m/%Y") )

tmp <- c("1, 15/08/2008", "2, 23/05/2010")
con <- textConnection(tmp)

tmp2 <- read.csv(con, colClasses=c('numeric','myDate'), header=FALSE)
str(tmp2)

Then modify if needed to work for your data.

Edit ---

You might want to run setClass('myDate') first to avoid the warning (you can ignore the warning, but it can get annoying if you do this a lot and this is a simple call that gets rid of it).

Solution 2 - R

If there is only 1 date format you want to change, you could use the Defaults package to change the default format within as.Date.character

library(Defaults)
setDefaults('as.Date.character', format = '%d/%M/%Y')
dataImport <- read.csv("data.csv", colClasses = c("factor","factor","Date"))
str(dataImport)
## 'data.frame':	10 obs. of  3 variables:
##  $ func_loc     : Factor w/ 5 levels "3076WAG0003",..: 1 2 3 3 3 3 3 4 4 5
##  $ order_type   : Factor w/ 3 levels "PM01","PM02",..: 3 3 1 1 1 1 2 2 3 1
##  $ actual_finish: Date, format: "2008-10-15" "2009-10-19" NA "2008-10-11" ...

I think @Greg Snow's answer is far better, as it does not change the default behaviour of an often used function.

Solution 3 - R

In case you need time also:

setClass('yyyymmdd-hhmmss')
setAs("character","yyyymmdd-hhmmss", function(from) as.POSIXct(from, format="%Y%m%d-%H%M%S"))
d <- read.table(colClasses="yyyymmdd-hhmmss", text="20150711-130153")
str(d)
## 'data.frame':	1 obs. of  1 variable:
## $ V1: POSIXct, format: "2015-07-11 13:01:53"

Solution 4 - R

A long time ago, in the meantime the problem has been solved by Hadley Wickham. So nowadays the solution is reduced to a oneliner:

library(readr)
data <- read_csv("data.csv", 
                  col_types = cols(actual_finish = col_datetime(format = "%d/%m/%Y")))

Maybe we want even to get rid of unnecessary stuff:

data <- as.data.frame(data)

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionTommy O&#39;DellView Question on Stackoverflow
Solution 1 - RGreg SnowView Answer on Stackoverflow
Solution 2 - RmnelView Answer on Stackoverflow
Solution 3 - RMark RajcokView Answer on Stackoverflow
Solution 4 - RAndri SignorellView Answer on Stackoverflow