Serializing to JSON in jQuery

JavascriptJqueryAjaxJsonSerialization

Javascript Problem Overview


I need to serialize an object to JSON. I'm using jQuery. Is there a "standard" way to do this?

My specific situation: I have an array defined as shown below:

var countries = new Array();
countries[0] = 'ga';
countries[1] = 'cd';
...

and I need to turn this into a string to pass to $.ajax() like this:

$.ajax({
    type: "POST",
    url: "Concessions.aspx/GetConcessions",
    data: "{'countries':['ga','cd']}",
...

Javascript Solutions


Solution 1 - Javascript

JSON-js - JSON in JavaScript.

To convert an object to a string, use JSON.stringify:

var json_text = JSON.stringify(your_object, null, 2);

To convert a JSON string to object, use JSON.parse:

var your_object = JSON.parse(json_text);

It was recently recommended by John Resig:

> ...PLEASE start migrating > your JSON-using applications over to > Crockford's json2.js. It is fully > compatible with the ECMAScript 5 > specification and gracefully degrades > if a native (faster!) implementation > exists. > > In fact, I just landed a change in jQuery yesterday that utilizes the > JSON.parse method if it exists, now > that it has been completely specified.

I tend to trust what he says on JavaScript matters :)

All modern browsers (and many older ones which aren't ancient) support the JSON object natively. The current version of Crockford's JSON library will only define JSON.stringify and JSON.parse if they're not already defined, leaving any browser native implementation intact.

Solution 2 - Javascript

I've been using jquery-json for 6 months and it works great. It's very simple to use:

var myObj = {foo: "bar", "baz": "wockaflockafliz"};
$.toJSON(myObj);

// Result: {"foo":"bar","baz":"wockaflockafliz"}

Solution 3 - Javascript

Works on IE8+

No need for jQuery, use:

JSON.stringify(countries); 

Solution 4 - Javascript

I haven't used it but you might want to try the jQuery plugin written by Mark Gibson

It adds the two functions: $.toJSON(value), $.parseJSON(json_str, [safe]).

Solution 5 - Javascript

No, the standard way to serialize to JSON is to use an existing JSON serialization library. If you don't wish to do this, then you're going to have to write your own serialization methods.

If you want guidance on how to do this, I'd suggest examining the source of some of the available libraries.

EDIT: I'm not going to come out and say that writing your own serliazation methods is bad, but you must consider that if it's important to your application to use well-formed JSON, then you have to weigh the overhead of "one more dependency" against the possibility that your custom methods may one day encounter a failure case that you hadn't anticipated. Whether that risk is acceptable is your call.

Solution 6 - Javascript

I did find this somewhere. Can't remember where though... probably on StackOverflow :)

$.fn.serializeObject = function(){
    var o = {};
    var a = this.serializeArray();
    $.each(a, function() {
        if (o[this.name]) {
            if (!o[this.name].push) {
                o[this.name] = [o[this.name]];
            }
            o[this.name].push(this.value || '');
        } else {
            o[this.name] = this.value || '';
        }
    });
    return o;
};

Solution 7 - Javascript

If you don't want to use external libraries there is .toSource() native JavaScript method, but it's not perfectly cross-browser.

Solution 8 - Javascript

Yes, you should JSON.stringify and JSON.parse your Json_PostData before calling $.ajax:

$.ajax({
        url:    post_http_site,  
        type: "POST",         
        data:   JSON.parse(JSON.stringify(Json_PostData)),       
        cache: false,
        error: function (xhr, ajaxOptions, thrownError) {
            alert(" write json item, Ajax error! " + xhr.status + " error =" + thrownError + " xhr.responseText = " + xhr.responseText );    
        },
        success: function (data) {
            alert("write json item, Ajax  OK");
       
        } 
});

Solution 9 - Javascript

The best way is to include the polyfill for JSON object.

But if you insist create a method for serializing an object to JSON notation (valid values for JSON) inside the jQuery namespace, you can do something like this:

##Implementation

// This is a reference to JSON.stringify and provides a polyfill for old browsers.
// stringify serializes an object, array or primitive value and return it as JSON.
jQuery.stringify = (function ($) {
  var _PRIMITIVE, _OPEN, _CLOSE;
  if (window.JSON && typeof JSON.stringify === "function")
    return JSON.stringify;

  _PRIMITIVE = /string|number|boolean|null/;

  _OPEN = {
    object: "{",
    array: "["
  };

  _CLOSE = {
    object: "}",
    array: "]"
  };

  //actions to execute in each iteration
  function action(key, value) {
    var type = $.type(value),
      prop = "";

    //key is not an array index
    if (typeof key !== "number") {
      prop = '"' + key + '":';
    }
    if (type === "string") {
      prop += '"' + value + '"';
    } else if (_PRIMITIVE.test(type)) {
      prop += value;
    } else if (type === "array" || type === "object") {
      prop += toJson(value, type);
    } else return;
    this.push(prop);
  }

  //iterates over an object or array
  function each(obj, callback, thisArg) {
    for (var key in obj) {
      if (obj instanceof Array) key = +key;
      callback.call(thisArg, key, obj[key]);
    }
  }

  //generates the json
  function toJson(obj, type) {
    var items = [];
    each(obj, action, items);
    return _OPEN[type] + items.join(",") + _CLOSE[type];
  }

  //exported function that generates the json
  return function stringify(obj) {
    if (!arguments.length) return "";
    var type = $.type(obj);
    if (_PRIMITIVE.test(type))
      return (obj === null ? type : obj.toString());
    //obj is array or object
    return toJson(obj, type);
  }
}(jQuery));

##Usage

var myObject = {
    "0": null,
    "total-items": 10,
    "undefined-prop": void(0),
    sorted: true,
    images: ["bg-menu.png", "bg-body.jpg", [1, 2]],
    position: { //nested object literal
        "x": 40,
        "y": 300,
        offset: [{ top: 23 }]
    },
    onChange: function() { return !0 },
    pattern: /^bg-.+\.(?:png|jpe?g)$/i
};

var json = jQuery.stringify(myObject);
console.log(json);

Solution 10 - Javascript

It's basically 2 step process:

First, you need to stringify like this:

var JSON_VAR = JSON.stringify(OBJECT_NAME, null, 2); 

After that, you need to convert the string to Object:

var obj = JSON.parse(JSON_VAR);

Solution 11 - Javascript

One thing that the above solutions don't take into account is if you have an array of inputs but only one value was supplied.

For instance, if the back end expects an array of People, but in this particular case, you are just dealing with a single person. Then doing:

<input type="hidden" name="People" value="Joe" />

Then with the previous solutions, it would just map to something like:

{
    "People" : "Joe"
}

But it should really map to

{
    "People" : [ "Joe" ]
}

To fix that, the input should look like:

<input type="hidden" name="People[]" value="Joe" />

And you would use the following function (based off of other solutions, but extended a bit)

$.fn.serializeObject = function() {
var o = {};
var a = this.serializeArray();
$.each(a, function() {
	if (this.name.substr(-2) == "[]"){
		this.name = this.name.substr(0, this.name.length - 2);
		o[this.name] = [];
	}

	if (o[this.name]) {
		if (!o[this.name].push) {
			o[this.name] = [o[this.name]];
		}
		o[this.name].push(this.value || '');
	} else {
		o[this.name] = this.value || '';
	}
});
return o;
};

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionHerb CaudillView Question on Stackoverflow
Solution 1 - Javascriptuser18015View Answer on Stackoverflow
Solution 2 - JavascriptJay TaylorView Answer on Stackoverflow
Solution 3 - JavascriptpestatijeView Answer on Stackoverflow
Solution 4 - JavascriptTahir AkhtarView Answer on Stackoverflow
Solution 5 - JavascriptAdam BellaireView Answer on Stackoverflow
Solution 6 - Javascriptjmort253View Answer on Stackoverflow
Solution 7 - JavascriptKain HaartView Answer on Stackoverflow
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Solution 10 - JavascriptShrish ShrivastavaView Answer on Stackoverflow
Solution 11 - JavascriptTim BurkhartView Answer on Stackoverflow