Remove last character of a StringBuilder?
JavaStringbuilderJava Problem Overview
When you have to loop through a collection and make a string of each data separated by a delimiter, you always end up with an extra delimiter at the end, e.g.
for (String serverId : serverIds) {
sb.append(serverId);
sb.append(",");
}
Gives something like : serverId_1, serverId_2, serverId_3,
I would like to delete the last character in the StringBuilder (without converting it because I still need it after this loop).
Java Solutions
Solution 1 - Java
Others have pointed out the deleteCharAt
method, but here's another alternative approach:
String prefix = "";
for (String serverId : serverIds) {
sb.append(prefix);
prefix = ",";
sb.append(serverId);
}
Alternatively, use the Joiner
class from Guava :)
As of Java 8, StringJoiner
is part of the standard JRE.
Solution 2 - Java
Another simple solution is:
sb.setLength(sb.length() - 1);
A more complicated solution:
The above solution assumes that sb.length() > 0
... i.e. there is a "last character" to remove. If you can't make that assumption, and/or you can't deal with the exception that would ensue if the assumption is incorrect, then check the StringBuilder's length first; e.g.
// Readable version
if (sb.length() > 0) {
sb.setLength(sb.length() - 1);
}
or
// Concise but harder-to-read version of the above.
sb.setLength(Math.max(sb.length() - 1, 0));
Solution 3 - Java
if(sb.length() > 0){
sb.deleteCharAt(sb.length() - 1);
}
Solution 4 - Java
As of Java 8, the String class has a static method join
. The first argument is a string that you want between each pair of strings, and the second is an Iterable<CharSequence>
(which are both interfaces, so something like List<String>
works. So you can just do this:
String.join(",", serverIds);
Also in Java 8, you could use the new StringJoiner
class, for scenarios where you want to start constructing the string before you have the full list of elements to put in it.
Solution 5 - Java
Just get the position of the last character occurrence.
for(String serverId : serverIds) {
sb.append(serverId);
sb.append(",");
}
sb.deleteCharAt(sb.lastIndexOf(","));
Since lastIndexOf
will perform a reverse search, and you know that it will find at the first try, performance won't be an issue here.
EDIT
Since I keep getting ups on my answer (thanks folks ), it is worth regarding that:
On Java 8 onward it would just be more legible and explicit to use StringJoiner. It has one method for a simple separator, and an overload for prefix and suffix.
Examples taken from here: example
Example using simple separator:
> StringJoiner mystring = new StringJoiner("-");
>
> // Joining multiple strings by using add() method
> mystring.add("Logan");
> mystring.add("Magneto");
> mystring.add("Rogue");
> mystring.add("Storm");
>
> System.out.println(mystring);
Output:
> Logan-Magneto-Rogue-Storm
Example with suffix and prefix:
> StringJoiner mystring = new StringJoiner(",", "(", ")");
>
> // Joining multiple strings by using add() method
> mystring.add("Negan");
> mystring.add("Rick");
> mystring.add("Maggie");
> mystring.add("Daryl");
>
> System.out.println(mystring);
Output
> (Negan,Rick,Maggie,Daryl)
Solution 6 - Java
In this case,
sb.setLength(sb.length() - 1);
is preferable as it just assign the last value to '\0'
whereas deleting last character does System.arraycopy
Solution 7 - Java
With Java-8
you can use static method of String
class,
String#join(CharSequence delimiter,Iterable<? extends CharSequence> elements)
.
public class Test {
public static void main(String[] args) {
List<String> names = new ArrayList<>();
names.add("James");
names.add("Harry");
names.add("Roy");
System.out.println(String.join(",", names));
}
}
OUTPUT
James,Harry,Roy
Solution 8 - Java
Another alternative
for(String serverId : serverIds) {
sb.append(",");
sb.append(serverId);
}
sb.deleteCharAt(0);
Solution 9 - Java
Alternatively,
StringBuilder result = new StringBuilder();
for(String string : collection) {
result.append(string);
result.append(',');
}
return result.substring(0, result.length() - 1) ;
Solution 10 - Java
StringBuilder sb = new StringBuilder();
sb.append("abcdef");
sb.deleteCharAt(sb.length() - 1);
assertEquals("abcde",sb.toString());
// true
Solution 11 - Java
Yet another alternative:
public String join(Collection<String> collection, String seperator) {
if (collection.isEmpty()) return "";
Iterator<String> iter = collection.iterator();
StringBuilder sb = new StringBuilder(iter.next());
while (iter.hasNext()) {
sb.append(seperator);
sb.append(iter.next());
}
return sb.toString();
}
Solution 12 - Java
To avoid reinit(affect performance) of prefix
use TextUtils.isEmpty:
String prefix = "";
for (String item : list) {
sb.append(prefix);
if (TextUtils.isEmpty(prefix))
prefix = ",";
sb.append(item);
}
Solution 13 - Java
I am doing something like below:
StringBuilder stringBuilder = new StringBuilder();
for (int i = 0; i < value.length; i++) {
stringBuilder.append(values[i]);
if (value.length-1) {
stringBuilder.append(", ");
}
}
Solution 14 - Java
You may try to use 'Joiner' class instead of removing the last character from your generated text;
List<String> textList = new ArrayList<>();
textList.add("text1");
textList.add("text2");
textList.add("text3");
Joiner joiner = Joiner.on(",").useForNull("null");
String output = joiner.join(textList);
//output : "text1,text2,text3"
Solution 15 - Java
Here is another solution:
for(String serverId : serverIds) {
sb.append(",");
sb.append(serverId);
}
String resultingString = "";
if ( sb.length() > 1 ) {
resultingString = sb.substring(1);
}
Solution 16 - Java
stringBuilder.Remove(stringBuilder.Length - 1, 1);
Solution 17 - Java
I found myself doing this quite a bit so I wrote a benchmark for the 3 main append delimiter techniques:
(benchmark with proper warmup and 100 rounds of 100,000 iterations)
"Append After"
static void appendAfter()
{
sb.append('{');
for (int i = 0; i < 10; i++)
{
sb.append('"');
sb.append(i);
sb.append('"');
sb.append(':');
sb.append(i);
sb.append(',');
}
sb.setLength(sb.length() - 1);
sb.append('}');
}
"Append Before"
static void appendBefore()
{
sb.append('{');
String delimiter = "";
for (int i = 0; i < 10; i++)
{
sb.append(delimiter);
sb.append('"');
sb.append(i);
sb.append('"');
sb.append(':');
sb.append(i);
delimiter = ",";
}
sb.append('}');
}
"Append Maybe"
static void appendMaybe()
{
sb.append('{');
for (int i = 0; i < 10; i++)
{
sb.append('"');
sb.append(i);
sb.append('"');
sb.append(':');
sb.append(i);
if (i < 9)
{
sb.append(',');
}
}
sb.append('}');
}
I got the following results:
Platform | Append After | Append Before | Append Maybe |
---|---|---|---|
Windows Server 2016, Java 11 - Hotspot | 26ms | 40ms | 26ms |
Windows Server 2016, Java 8 - Hotspot | 27ms | 36ms | 21ms |
Windows Server 2016, Java 11 - OpenJ9 | 63ms | 81ms | 59ms |
Windows Server 2016, Java 8 - OpenJ9 | 66ms | 64ms | 55ms |
Aside from being the fastest, I am of the opinion that the "Append Maybe" implementation shows the intent of the code the best. That is usually more important than the fraction of nanoseconds gained per iteration.
I left the benchmark code here in case anyone wanted to try it on their platform. Please contribute your results above if you do so!