What is simplest way to read a file into String?

JavaFileFile Io

Java Problem Overview


I am trying to read a simple text file into a String. Of course there is the usual way of getting the input stream and iterating with readLine() and reading contents into String.

Having done this hundreds of times in past, I just wondered how can I do this in minimum lines of code? Isn't there something in java like String fileContents = XXX.readFile(myFile/*File*/) .. rather anything that looks as simple as this?

I know there are libraries like Apache Commons IO which provide such simplifications or even I can write a simple Util class to do this. But all that I wonder is - this is a so frequent operation that everyone needs then why doesn't Java provide such simple function? Isn't there really a single method somewhere to read a file into string with some default or specified encoding?

Java Solutions


Solution 1 - Java

Yes, you can do this in one line (though for robust IOException handling you wouldn't want to).

String content = new Scanner(new File("filename")).useDelimiter("\\Z").next();
System.out.println(content);

This uses a java.util.Scanner, telling it to delimit the input with \Z, which is the end of the string anchor. This ultimately makes the input have one actual token, which is the entire file, so it can be read with one call to next().

There is a constructor that takes a File and a String charSetName (among many other overloads). These two constructor may throw FileNotFoundException, but like all Scanner methods, no IOException can be thrown beyond these constructors.

You can query the Scanner itself through the ioException() method if an IOException occurred or not. You may also want to explicitly close() the Scanner after you read the content, so perhaps storing the Scanner reference in a local variable is best.

See also

Third-party library options

For completeness, these are some really good options if you have these very reputable and highly useful third party libraries:

Guava

com.google.common.io.Files contains many useful methods. The pertinent ones here are:

Apache Commons/IO

org.apache.commons.io.IOUtils also offer similar functionality:

  • String toString(InputStream, String encoding)
    • Using the specified character encoding, gets the contents of an InputStream as a String
  • List readLines(InputStream, String encoding)
    • ... as a (raw) List of String, one entry per line

Solution 2 - Java

From Java 7 (API Description) onwards you can do:

new String(Files.readAllBytes(Paths.get(filePath)), StandardCharsets.UTF_8);

Where filePath is a String representing the file you want to load.

Solution 3 - Java

You can use apache commons IO..

FileInputStream fisTargetFile = new FileInputStream(new File("test.txt"));
		
String targetFileStr = IOUtils.toString(fisTargetFile, "UTF-8");

Solution 4 - Java

This should work for you:

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;

public static void main(String[] args) throws IOException {
    String content = new String(Files.readAllBytes(Paths.get("abc.java")));
}

Solution 5 - Java

Using Apache Commons IO.

import org.apache.commons.io.FileUtils;

//...

String contents = FileUtils.readFileToString(new File("/path/to/the/file"), "UTF-8")

You can see de javadoc for the method for details.

Solution 6 - Java

Don't write your own util class to do this - I would recommend using Guava, which is full of all kinds of goodness. In this case you'd want either the Files class (if you're really just reading a file) or CharStreams for more general purpose reading. It has methods to read the data into a list of strings (readLines) or totally (toString).

It has similar useful methods for binary data too. And then there's the rest of the library...

I agree it's annoying that there's nothing similar in the standard libraries. Heck, just being able to supply a CharSet to a FileReader would make life a little simpler...

Solution 7 - Java

Another alternative approach is:

https://stackoverflow.com/questions/326390/how-to-create-a-java-string-from-the-contents-of-a-file/326440#326440

Other option is to use utilities provided open source libraries
http://commons.apache.org/io/api-1.4/index.html?org/apache/commons/io/IOUtils.html

Why java doesn't provide such a common util API ?
a) to keep the APIs generic so that encoding, buffering etc is handled by the programmer.
b) make programmers do some work and write/share opensource util libraries :D ;-)

Solution 8 - Java

Sadly, no.

I agree that such frequent operation should have easier implementation than copying of input line by line in loop, but you'll have to either write helper method or use external library.

Solution 9 - Java

I discovered that the accepted answer actually doesn't always work, because \\Z may occur in the file. Another problem is that if you don't have the correct charset a whole bunch of unexpected things may happen which may cause the scanner to read only a part of the file.

The solution is to use a delimiter which you are certain will never occur in the file. However, this is theoretically impossible. What we CAN do, is use a delimiter that has such a small chance to occur in the file that it is negligible: such a delimiter is a UUID, which is natively supported in Java.

String content = new Scanner(file, "UTF-8")
    .useDelimiter(UUID.randomUUID().toString()).next();

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionGopiView Question on Stackoverflow
Solution 1 - JavapolygenelubricantsView Answer on Stackoverflow
Solution 2 - JavaJimView Answer on Stackoverflow
Solution 3 - JavaRakesh GoyalView Answer on Stackoverflow
Solution 4 - JavaDDasView Answer on Stackoverflow
Solution 5 - JavacjungelView Answer on Stackoverflow
Solution 6 - JavaJon SkeetView Answer on Stackoverflow
Solution 7 - JavaBhuvan GuptaView Answer on Stackoverflow
Solution 8 - JavaNikita RybakView Answer on Stackoverflow
Solution 9 - JavawvdzView Answer on Stackoverflow