Python requests library how to pass Authorization header with single token

PythonGetAuthorizationTokenPython Requests

Python Problem Overview

I have a request URI and a token. If I use:

curl -s "<MY_URI>" -H "Authorization: TOK:<MY_TOKEN>"

etc., I get a 200 and view the corresponding JSON data. So, I installed requests and when I attempt to access this resource I get a 403 probably because I do not know the correct syntax to pass that token. Can anyone help me figure it out? This is what I have:

import sys,socket
import requests

r = requests.get('<MY_URI>','<MY_TOKEN>')
r. status_code

I already tried:

r = requests.get('<MY_URI>',auth=('<MY_TOKEN>'))
r = requests.get('<MY_URI>',auth=('TOK','<MY_TOKEN>'))
r = requests.get('<MY_URI>',headers=('Authorization: TOK:<MY_TOKEN>'))

But none of these work.

Python Solutions

Solution 1 - Python

In python:


is equivalent to


And requests interprets

('TOK', '<MY_TOKEN>')

As you wanting requests to use Basic Authentication and craft an authorization header like so:


Which is the base64 representation of 'TOK:<MY_TOKEN>'

To pass your own header you pass in a dictionary like so:

r = requests.get('<MY_URI>', headers={'Authorization': 'TOK:<MY_TOKEN>'})

Solution 2 - Python

I was looking for something similar and came across this. It looks like in the first option you mentioned

r = requests.get('<MY_URI>', auth=('<MY_TOKEN>'))

"auth" takes two parameters: username and password, so the actual statement should be

r=requests.get('<MY_URI>', auth=('<YOUR_USERNAME>', '<YOUR_PASSWORD>'))

In my case, there was no password, so I left the second parameter in auth field empty as shown below:

r=requests.get('<MY_URI', auth=('MY_USERNAME', ''))

Hope this helps somebody :)

Solution 3 - Python

This worked for me:

access_token = #yourAccessTokenHere#

result =,
               'Authorization': 'Bearer {}'.format(access_token)})

Solution 4 - Python

You can also set headers for the entire session:

TOKEN = 'abcd0123'
HEADERS = {'Authorization': 'token {}'.format(TOKEN)}

with requests.Session() as s:

    resp = s.get('')

Solution 5 - Python

i founded here, its ok with me for linkedin: so my code with with linkedin login here:

ref = ''
headers = {"content-type": "application/json; charset=UTF-8",'Authorization':'Bearer {}'.format(access_token)}
Linkedin_user_info = requests.get(ref1, headers=headers).json()

Solution 6 - Python

You can try something like this

r = requests.get(ENDPOINT, params=params, headers={'Authorization': 'Basic %s' %  API_KEY})

Solution 7 - Python

Requests natively supports basic auth only with user-pass params, not with tokens.

You could, if you wanted, add the following class to have requests support token based basic authentication:

import requests
from base64 import b64encode

class BasicAuthToken(requests.auth.AuthBase):
    def __init__(self, token):
        self.token = token
    def __call__(self, r):
        authstr = 'Basic ' + b64encode(('token:' + self.token).encode('utf-8')).decode('utf-8')
        r.headers['Authorization'] = authstr
        return r

Then, to use it run the following request :

r = requests.get(url, auth=BasicAuthToken(api_token))

An alternative would be to formulate a custom header instead, just as was suggested by other users here.

Solution 8 - Python

This worked for me:

r = requests.get('', headers={'Authorization': 'Token 22ec0cc4207ebead1f51dea06ff149342082b190'})

My code uses user generated token.

Solution 9 - Python

You have a request needing an authorization maybe you have a result 401.

Suppose your request is like this :

REQ =''

You have your token :

TOKEN = 'fliuzabuvdgfnsuczkncsq12454632'

build your header like this :

HEADER = {'Authorization': f'{TOKEN}'}

and use it like this :

req.get(REQ, headers=HEADER)

display your result like this :

req.get(COACH, headers=HEADER).json()


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Questionuser1552586View Question on Stackoverflow
Solution 1 - PythonIan Stapleton CordascoView Answer on Stackoverflow
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