PHP date(): minutes without leading zeros
PhpDateFormatPhp Problem Overview
I'd like to know if there is a formatting letter for PHP's date() that allows me to print minutes without leading zeros, or whether I have to manually test for and remove leading zeros?
Php Solutions
Solution 1 - Php
Use:
$minutes = intval(date('i'));
Solution 2 - Php
For times with more information than just minutes:
ltrim() - Strip whitespace (or other characters) from the beginning of a string
ltrim(date('i:s'), 0);
returns:
8:24
Solution 3 - Php
According to the PHP Documentation, the date() function does not have a placeholder for minutes without leading zeros.
You could, however, get that information by simply multiplying the dates, with a leading zero, by 1, turning it into an integer.
$minutesWithoutZero = 1* date( 'i' );
Solution 4 - Php
I tried to find this for seconds as well, gave up the search and just casting the result as a int like this:
echo (int)date("s");
That will get rid of the leading zero's in a fast efficient way.
Solution 5 - Php
Doesn't look like it, but you could do something like...
echo date('g:') . ltrim(date('i'), '0');
Alternately, you could cast the second call to date() with (int).
Solution 6 - Php
This also works
$timestamp = time(); // Or Your timestamp. Skip passing $timestamp if you want current time
echo (int)date('i',$timestamp);
Solution 7 - Php
I use this format if I need a XXmXXs format:
//Trim leading 0's and the 'm' if no minutes
ltrim(ltrim(gmdate("i\ms\s", $seconds), '0'), 'm');
This will output the following:
12m34s
1m23s
12s
Solution 8 - Php
i just did this one line solution
> $min = intval(date('i',strtotime($date)));
Using ltrim method may remove all the leading zeroes.For ex if '00' min.In this case this will remove all the zeroes and gives you empty result.
Solution 9 - Php
My solution:
function seconds2string($seconds) {
if ($seconds == 0) {
return '-';
}
if ($seconds < 60) {
return date('0:s', $seconds);
}
if ($seconds < 3600) {
return ltrim(date('i:s', $seconds), 0);
}
return date('G:i:s', $seconds);
}
This will output:
0 seconds: -
10 seconds: 0:10
90 seconds: 1:30
301 seconds: 5:01
1804 seconds: 30:04
3601 seconds: 1:00:01
Solution 10 - Php
Just use this:
(int) date('i');
Solution 11 - Php
Or in mySQL just multiply it by 1, like such:
select f1, ..., date_format( fldTime , '%i' ) * 1 as myTime, ..., ...
Solution 12 - Php
$current_date = Date("n-j-Y");
echo $current_date;
// Result m-d-yy
9-10-2012
Solution 13 - Php
A quickie from me. Tell me what you think:
<?php function _wo_leading_zero($n) {
if(!isset($n[1])) return $n;
if(strpos($n, '.') !== false) {
$np = explode('.', $n); $nd = '.';
}
if(strpos($n, ',') !== false) {
if(isset($np)) return false;
$np = explode(',', $n); $nd = ',';
}
if(isset($np) && count($np) > 2) return false;
$n = isset($np) ? $np[0] : $n;
$nn = ltrim($n, '0');
if($nn == '') $nn = '0';
return $nn.(isset($nd) ? $nd : '').(isset($np[1]) ? $np[1] : '');
}
echo '0 => '._wo_leading_zero('0').'<br/>'; // returns 0
echo '00 => '._wo_leading_zero('00').'<br/>'; // returns 0
echo '05 => '._wo_leading_zero('05').'<br/>'; // returns 5
echo '0009 => '._wo_leading_zero('0009').'<br/>'; //returns 9
echo '01 => '._wo_leading_zero('01').'<br/>'; //returns 1
echo '0000005567 => '._wo_leading_zero('0000005567').'<br/>'; //returns 5567
echo '000.5345453 => '._wo_leading_zero('000.5345453').'<br/>'; //returns 0.5345453
echo '000.5345453.2434 => '._wo_leading_zero('000.5345453.2434').'<br/>'; //returns false
echo '000.534,2434 => '._wo_leading_zero('000.534,2434').'<br/>'; //returns false
echo date('m').' => '._wo_leading_zero(date('m')).'<br/>';
echo date('s').' => '._wo_leading_zero(date('s')).'<br/>'; ?>
Solution 14 - Php
use PHP's absolute value function:
abs( '09' ); // result = 9
abs( date( 'i' ) ); // result = minutes without leading zero
Solution 15 - Php
My Suggestion is Read this beautiful documentation it have all details of php date functions
And as per your question you can use i - Minutes with leading zeros (00 to 59) Which return you minutes with leading zero(0).
And Also introducing [Intval()][2] function returns the integer value of a variable. You can not use the intval() function on an object