**Use**:

    ExpressionSelectingTable/tr[td//text()[contains(., &#39;targetString&#39;)]]

**This means**:

Select every `tr` that is a child of any table selected by the expression `ExpressionSelectingTable` and that (the `tr`) has at least one `td` child that has at least one text-node descendent that contains the string `&#39;targetString&#39;`

To select rows with cells containing some text you would use this XPath expression:

`//tr/td[normalize-space(text())=&quot;Banana&quot;]/..`

This selects any `td` that contains text &quot;Banana&quot; and then selects the parent with `/..`

I&#39;d like to know if there is a formatting letter for PHP&#39;s `date()` that allows me to print minutes _without_ leading zeros, or whether I have to manually test for and remove leading zeros?

PHP date(): minutes without leading zeros

Can anyone point me to some Java snippet wherein i can get business (except Sat and Sun) days between two dates.

Calculate number of weekdays between two dates in Java

How do I select a table row that has a cell containing specified text with XPath?

XPath to select a table row that has a cell containing specified text

<p>How do I select a table row that has a cell containing specified text with XPath?</p>


Let&#39;s say I have this HTML:

    &lt;h3&gt;Features&lt;/h3&gt;
    &lt;ul&gt;
        &lt;li&gt;&lt;img src=&quot;alphaball.png&quot;&gt;Smells Good&lt;/li&gt;
        &lt;li&gt;&lt;img src=&quot;alphaball.png&quot;&gt;Tastes Great&lt;/li&gt;
        &lt;li&gt;&lt;img src=&quot;alphaball.png&quot;&gt;Delicious&lt;/li&gt;
        &lt;li&gt;&lt;img src=&quot;alphaball.png&quot;&gt;Wholesome&lt;/li&gt;
        &lt;li&gt;&lt;img src=&quot;alphaball.png&quot;&gt;Eats Children&lt;/li&gt;
        &lt;li&gt;&lt;img src=&quot;alphaball.png&quot;&gt;Yo&#39; Mama&lt;/li&gt;
    &lt;/ul&gt;

and this CSS:

    li { text-align:center; display:inline-block; padding:0.1em 1em }
    img { width:64px; display:block; margin:0 auto }

The result can be seen here: http://jsfiddle.net/YMN7U/1/

Now imagine that I want to break this into three columns, the equivalent of injecting a `&lt;br&gt;` after the third `&lt;li&gt;`. _(Actually doing that would be semantically and syntactically invalid.)_

I know how to select the third `&lt;li&gt;` in CSS, but how do I force a line break after it? This does not work:

    li:nth-child(4):after { content:&quot;xxx&quot;; display:block }

_I also know that this particular case is possible by using `float` instead of `inline-block`, but I am not interested in solutions using `float`. I also know that with fixed-width blocks this is possible by setting the width on the parent `ul` to about 3x that width; I am not interested in this solution. I also know that I could use `display:table-cell` if I wanted real columns; I am not interested in this solution. I am interested in the possibility of forcing a break inside inline content._

**Edit**: To be clear, I am interested in &#39;theory&#39;, not the solution to a particular problem. _Can CSS inject a line break in the middle of `display:inline(-block)?` elements, or is it impossible?_ If you are certain that it is impossible, that is an acceptable answer.

CSS to line break before/after a particular `inline-block` item

My site is going to have some inline code (&quot;when using the `foo()` function...&quot;) and some block snippets. These tend to be XML, and have very long lines which I prefer the browser to wrap (i.e., I don&#39;t want to use `&lt;pre&gt;`). I&#39;d also like to put CSS formatting on the block snippets.

It seems that I can&#39;t use `&lt;code&gt;` for both, because if I put CSS block attributes on it (with `display: block;`), it will break the inline snippets.

I&#39;m curious what people do. Use `&lt;code&gt;` for blocks, and `&lt;samp&gt;` for inline? Use `&lt;code&gt;&lt;blockquote&gt;` or something similar?

I&#39;d like to keep the actual HTML as simple as possible, avoiding classes, as other users will be maintaining it.

&lt;code&gt; vs &lt;pre&gt; vs &lt;samp&gt; for inline and block code snippets

How do I get the height of the div which includes the clipped area of the div ?

    &lt;div style=&quot;height: 20px; overflow: hidden&quot;&gt;
      content&lt;br&gt;content&lt;br&gt;content&lt;br&gt;
      content&lt;br&gt;content&lt;br&gt;content&lt;br&gt;
      content&lt;br&gt;content&lt;br&gt;content&lt;br&gt;
    &lt;/div&gt;



Get full height of a clipped DIV

I&#39;m trying to do something that used to be really easy before the `start` attribute on ol tags was deprecated. I&#39;d just like to have a pair of ordered lists in my page, but start the numbering of the second list where the first one finished. Something like:

    1. do stuff
    2. do stuff
    
    Here&#39;s a paragraph
    
    3. do stuff

I&#39;ve seen that the `counter-reset` and `counter-increment` CSS properties should be able to achieve this, but I can&#39;t get it working. Here&#39;s my code so far:

    &lt;html&gt;
    &lt;head&gt;
      &lt;style type=&quot;text/css&quot;&gt;
        ol li { counter-increment: mycounter; }
        ol.start { counter-reset: mycounter; }
        ol.continue { counter-reset: mycounter 2; }
      &lt;/style&gt;
    &lt;/head&gt;
    
    &lt;body&gt;
      &lt;ol class=&quot;start&quot;&gt;
        &lt;li&gt;You can&#39;t touch this&lt;/li&gt;
        &lt;li&gt;You can&#39;t touch this&lt;/li&gt;
      &lt;/ol&gt;
      &lt;p&gt;STOP! Hammer time.&lt;/p&gt;
      &lt;ol class=&quot;continue&quot;&gt;
        &lt;li&gt;You can&#39;t touch this&lt;/li&gt;
      &lt;/ol&gt;
    &lt;/body&gt;
    &lt;/html&gt;

To be honest, even if that worked, it wouldn&#39;t be ideal. I don&#39;t want to have to specify the number reached by the first list in my `ol.continue` selector.

What am I doing wrong? What&#39;s the minimal HTML/CSS combination required to achieve the desired effect?

How to start a new list, continuing the numbering from the previous list?

Our webpage background images are having problems in FireFox as well as Safari in iOS on iPads/iPhones with white space showing up on the right side of the page. 

The background images extend fine on other browsers but we&#39;re having difficulty not extending the full length of the browser on those browsers. 

Take a [look at our site on FireFox][1] to see what I mean. 


  [1]: http://www.visibleequity.com

White space showing up on right side of page when background image should extend full length of page

I&#39;m trying to get the links from a page with xpath. The problem is that I only want the links inside a table, but if I apply the xpath expression on the whole page I&#39;ll capture links which I don&#39;t want.

For example:

    tree = lxml.html.parse(some_response)
    links = tree.xpath(&quot;//a[contains(@href, &#39;http://www.example.com/filter/&#39;)]&quot;)

The problem is that applies the expression to the whole document. I located the element I want, for example:

    tree = lxml.html.parse(some_response)
    root = tree.getroot()
    table = root[1][5] #for example
    links = table.xpath(&quot;//a[contains(@href, &#39;http://www.example.com/filter/&#39;)]&quot;)

But that seems to be performing the query in the whole document as well, as I still am capturing the links outside of the table. &lt;a href=&quot;http://codespeak.net/lxml/xpathxslt.html&quot;&gt;This page&lt;/a&gt; says that &quot;When xpath() is used on an Element, the XPath expression is evaluated against the element (if relative) or against the root tree (if absolute):&quot;. So, what I using is an absolute expression and I need to make it relative? Is that it?

Basically, how can I go about filtering only elements that exist inside of this table?

Python: Using xpath locally / on a specific element

How can I extract the value of an attribute node via XPath?

A sample XML file is:

    &lt;parents name=&#39;Parents&#39;&gt;
      &lt;Parent id=&#39;1&#39; name=&#39;Parent_1&#39;&gt;
        &lt;Children name=&#39;Children&#39;&gt;
          &lt;child name=&#39;Child_2&#39; id=&#39;2&#39;&gt;child2_Parent_1&lt;/child&gt;
          &lt;child name=&#39;Child_4&#39; id=&#39;4&#39;&gt;child4_Parent_1&lt;/child&gt;
          &lt;child name=&#39;Child_1&#39; id=&#39;3&#39;&gt;child1_Parent_1&lt;/child&gt;
          &lt;child name=&#39;Child_3&#39; id=&#39;1&#39;&gt;child3_Parent_1&lt;/child&gt;
        &lt;/Children&gt;
      &lt;/Parent&gt;
      &lt;Parent id=&#39;2&#39; name=&#39;Parent_2&#39;&gt;
        &lt;Children name=&#39;Children&#39;&gt;
          &lt;child name=&#39;Child_1&#39; id=&#39;8&#39;&gt;child1_parent2&lt;/child&gt;
          &lt;child name=&#39;Child_2&#39; id=&#39;7&#39;&gt;child2_parent2&lt;/child&gt;
          &lt;child name=&#39;Child_4&#39; id=&#39;6&#39;&gt;child4_parent2&lt;/child&gt;
          &lt;child name=&#39;Child_3&#39; id=&#39;5&#39;&gt;child3_parent2&lt;/child&gt;
        &lt;/Children&gt;
      &lt;/Parent&gt;
    &lt;/parents&gt;

So far I have this XPath string:

    //Parent[@id=&#39;1&#39;]/Children/child[@name]  

It returns only `child` elements, but I would like to have the value of the `name` attribute.

For my sample XML file, here&#39;s what I&#39;d like the output to be:

    Child_2
    Child_4
    Child_1
    Child_3


Extract value of attribute node via XPath

Having the following XML:

    &lt;node&gt;Text1&lt;subnode/&gt;text2&lt;/node&gt;

How do I select either the first or the second text node via XPath?

Something like this:

    /node/text()[2]

of course doesn&#39;t work because it&#39;s the merged result of every text inside the node.

XPath: select text node

I need an XPath to fetch all ChildNodes ( including Text Element, Comment Element &amp; Child Elements ) without Parent Element. Any help

Sample Example:

    &lt;DOC&gt;
    &lt;PRESENTEDIN&gt;
        &lt;X&gt;
            First Text Node #1 
            &lt;y&gt; Y can Have Child Nodes # 
                &lt;child&gt; deep to it &lt;/child&gt; 
             &lt;/y&gt;
             Second Text Node #2 &lt;z/&gt; 
        &lt;/X&gt;
        &lt;EVTS&gt;
            &lt;evt/&gt;
            &lt;evt&gt;
                &lt;mtg_descr&gt; SAE 2006 World Congress &amp;amp; Exhibition &lt;/mtg_descr&gt;
                &lt;sess_descr&gt; Advanced Hybrid Vehicle Powertrains (Part 1 of 5) &lt;/sess_descr&gt;
                &lt;loc&gt; Detroit,MI,United States &lt;/loc&gt;
                &lt;sess_prod_grp_cd&gt; TSESS &lt;/sess_prod_grp_cd&gt;
                &lt;sess_evt_name&gt; P13 &lt;/sess_evt_name&gt;
                &lt;sess_gen_num&gt; 138352 &lt;/sess_gen_num&gt;
                &lt;mtg_start_dt&gt; 04/03/2006 &lt;/mtg_start_dt&gt;
                &lt;mtg_end_dt&gt; 04/06/2006 &lt;/mtg_end_dt&gt;
                &lt;desig&gt; CONGRESS-2006 &lt;/desig&gt;
            &lt;/evt&gt;
        &lt;/EVTS&gt;
        &lt;EVTTYPE&gt;PAPER&lt;/EVTTYPE&gt;
        &lt;SUPERTECH&gt;
            &lt;![CDATA[C8585]]&gt;
        &lt;/SUPERTECH&gt;
    &lt;/PRESENTEDIN&gt;
&lt;/DOC&gt;



XPATH TRIED

       1. $doc/PRESENTEDIN/X
       2. $doc/PRESENTEDIN/X/descendant::*
       2. $doc/PRESENTEDIN/X/self::*

EXPECTED OUTPUT
     

 
        First Text Node #1 
        &lt;y&gt; Y can Have Child Nodes # 
            &lt;child&gt; deep to it &lt;/child&gt; 
         &lt;/y&gt;
         Second Text Node #2 &lt;z/&gt; 


I DON&#39;T WANT

    &lt;X&gt;
      First Text Node #1 
            &lt;y&gt; Y can Have Child Nodes # 
                &lt;child&gt; deep to it &lt;/child&gt; 
             &lt;/y&gt;
             Second Text Node #2 &lt;z/&gt; 
    &lt;/X&gt;



XPath to get all child nodes (elements, comments, and text) without parent

I have the following XML:

    &lt;List xmlns=&quot;http://schemas.microsoft.com/sharepoint/soap/&quot;&gt;
     &lt;Fields&gt;
       &lt;Field&gt;
       &lt;/Field&gt;
     &lt;/Fields&gt;
    &lt;/List&gt;

This is a slimmed down version of XML being returned from a SharePoint web service. I also have the following xPath:

    /List/Fields/Field

When I remove the `xmlns` from my XML the xPath works fine.  When it&#39;s in there my xPath finds nothing.  Is there something I should be doing differently with my xPath?  Modifying the XML is not an option.

Content Type	Original Author	Original Content on Stackoverflow
Question	KClough	View Question on Stackoverflow
Solution 1 - Html	Dimitre Novatchev	View Answer on Stackoverflow
Solution 2 - Html	stefan.natchev	View Answer on Stackoverflow

XPath to select a table row that has a cell containing specified text

Html Problem Overview

Html Solutions

Solution 1 - Html

Solution 2 - Html

Calculate number of weekdays between two dates in Java

PHP date(): minutes without leading zeros

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