One-line list comprehension: if-else variants
PythonList ComprehensionTernary OperatorConditional OperatorPython Problem Overview
It's more about python list comprehension syntax. I've got a list comprehension that produces list of odd numbers of a given range:
[x for x in range(1, 10) if x % 2]
This makes a filter - I've got a source list, where I remove even numbers (if x % 2
). I'd like to use something like if-then-else here. Following code fails:
>>> [x for x in range(1, 10) if x % 2 else x * 100]
File "<stdin>", line 1
[x for x in range(1, 10) if x % 2 else x * 100]
^
SyntaxError: invalid syntax
There is a python expression like if-else:
1 if 0 is 0 else 3
How to use it inside a list comprehension?
Python Solutions
Solution 1 - Python
x if y else z
is the syntax for the expression you're returning for each element. Thus you need:
[ x if x%2 else x*100 for x in range(1, 10) ]
The confusion arises from the fact you're using a filter in the first example, but not in the second. In the second example you're only mapping each value to another, using a ternary-operator expression.
With a filter, you need:
[ EXP for x in seq if COND ]
Without a filter you need:
[ EXP for x in seq ]
and in your second example, the expression is a "complex" one, which happens to involve an if-else
.
Solution 2 - Python
[x if x % 2 else x * 100 for x in range(1, 10) ]
Solution 3 - Python
You can do that with list comprehension too:
A=[[x*100, x][x % 2 != 0] for x in range(1,11)]
print A
Solution 4 - Python
Just another solution, hope some one may like it :
Using: [False, True][Expression]
>>> map(lambda x: [x*100, x][x % 2 != 0], range(1,10))
[1, 200, 3, 400, 5, 600, 7, 800, 9]
>>>
Solution 5 - Python
#how you can squre a list of an array of negative and positive values
my_list=[-2,-3,0,1,5]
squred_values=[]
squred_values=[-i**2 if i<0 else i**2 for i in my_list]
#or
for i in my_list:
if i<0:
squred_values.append( -i**2)`enter code here`
else:
squred_values.append( i**2)
Solution 6 - Python
two for in one list comprehension
ex = [['obi', 'is', '#alive'],['oge', 'is', 'beautiful'],
['Ade', 'the', '#comedian', 'de', '#rich'],['Jesus', 'wept']]
res = [j if j.startswith("#") else "_"+j for i in ex for j in i]