JQuery Event for user pressing enter in a textbox?

JavascriptJqueryJquery Events

Javascript Problem Overview


Is there any event in Jquery that's triggered only if the user hits the enter button in a textbox? Or any plugin that can be added to include this? If not, how would I write a quick plugin that would do this?

Javascript Solutions


Solution 1 - Javascript

You can wire up your own custom event

$('textarea').bind("enterKey",function(e){
   //do stuff here
});
$('textarea').keyup(function(e){
    if(e.keyCode == 13)
    {
        $(this).trigger("enterKey");
    }
});

http://jsfiddle.net/x7HVQ/

Solution 2 - Javascript

   $('#textbox').on('keypress', function (e) {
         if(e.which === 13){
    		
            //Disable textbox to prevent multiple submit
            $(this).attr("disabled", "disabled");

            //Do Stuff, submit, etc..

            //Enable the textbox again if needed.
            $(this).removeAttr("disabled");
         }
   });

Solution 3 - Javascript

Here is a plugin for you: (Fiddle: http://jsfiddle.net/maniator/CjrJ7/)

$.fn.pressEnter = function(fn) {  
  
    return this.each(function() {  
        $(this).bind('enterPress', fn);
        $(this).keyup(function(e){
            if(e.keyCode == 13)
            {
              $(this).trigger("enterPress");
            }
        })
    });  
 }; 

//use it:
$('textarea').pressEnter(function(){alert('here')})

Solution 4 - Javascript

heres a jquery plugin to do that

(function($) {
    $.fn.onEnter = function(func) {
        this.bind('keypress', function(e) {
            if (e.keyCode == 13) func.apply(this, [e]);    
        });               
        return this; 
     };
})(jQuery);

to use it, include the code and set it up like this:

$( function () {
    console.log($("input"));
    $("input").onEnter( function() {
        $(this).val("Enter key pressed");                
    });
});

jsfiddle of it here http://jsfiddle.net/VrwgP/30/

Solution 5 - Javascript

It should be well noted that the use of live() in jQuery has been deprecated since version 1.7 and has been removed in jQuery 1.9. Instead, the use of on() is recommended.

I would highly suggest the following methodology for binding, as it solves the following potential challenges:

  1. By binding the event onto document.body and passing $selector as the second argument to on(), elements can be attached, detached, added or removed from the DOM without needing to deal with re-binding or double-binding events. This is because the event is attached to document.body rather than $selector directly, which means $selector can be added, removed and added again and will never load the event bound to it.
  2. By calling off() before on(), this script can live either within within the main body of the page, or within the body of an AJAX call, without having to worry about accidentally double-binding events.
  3. By wrapping the script within $(function() {...}), this script can again be loaded by either the main body of the page, or within the body of an AJAX call. $(document).ready() does not get fired for AJAX requests, while $(function() {...}) does.

Here is an example:

<!DOCTYPE html>
  <head>
    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
    <script type="text/javascript">
      $(function() {
        var $selector = $('textarea');

        // Prevent double-binding
        // (only a potential issue if script is loaded through AJAX)
        $(document.body).off('keyup', $selector);

        // Bind to keyup events on the $selector.
        $(document.body).on('keyup', $selector, function(event) {
          if(event.keyCode == 13) { // 13 = Enter Key
            alert('enter key pressed.');
          }
        });
      });
    </script>
  </head>
  <body>

  </body>
</html>

Solution 6 - Javascript

If your input is search, you also can use on 'search' event. Example

<input type="search" placeholder="Search" id="searchTextBox">

.

$("#searchPostTextBox").on('search', function () {
	alert("search value: "+$(this).val());
});

Solution 7 - Javascript

HTML Code:-

<input type="text" name="txt1" id="txt1" onkeypress="return AddKeyPress(event);" />      
                                          
<input type="button" id="btnclick">

Java Script Code

function AddKeyPress(e) { 
        // look for window.event in case event isn't passed in
        e = e || window.event;
        if (e.keyCode == 13) {
            document.getElementById('btnEmail').click();
            return false;
        }
        return true;
    }

Your Form do not have Default Submit Button

Solution 8 - Javascript

Another subtle variation. I went for a slight separation of powers, so I have a plugin to enable catching the enter key, then I just bind to events normally:

(function($) { $.fn.catchEnter = function(sel) {  
	return this.each(function() { 
		$(this).on('keyup',sel,function(e){
			if(e.keyCode == 13)
			  $(this).trigger("enterkey");
		})
	});  
};
})(jQuery);

And then in use:

$('.input[type="text"]').catchEnter().on('enterkey',function(ev) { });

This variation allows you to use event delegation (to bind to elements you haven't created yet).

$('body').catchEnter('.onelineInput').on('enterkey',function(ev) { /*process input */ });

Solution 9 - Javascript

I could not get the keypress event to fire for the enter button, and scratched my head for some time, until I read the jQuery docs:

"The keypress event is sent to an element when the browser registers keyboard input. This is similar to the keydown event, except that modifier and non-printing keys such as Shift, Esc, and delete trigger keydown events but not keypress events." (https://api.jquery.com/keypress/)

I had to use the keyup or keydown event to catch a press of the enter button.

Solution 10 - Javascript

//Short and simple solution

$(document).ready(function(){

$('#TextboxId').keydown(function(event){
    if (event.which == 13){
       //body or action to be performed
    }
});

});

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAliView Question on Stackoverflow
Solution 1 - JavascriptJishnu A PView Answer on Stackoverflow
Solution 2 - JavascriptEtienne DupuisView Answer on Stackoverflow
Solution 3 - JavascriptNaftaliView Answer on Stackoverflow
Solution 4 - JavascriptjzillaView Answer on Stackoverflow
Solution 5 - JavascriptJoshua BurnsView Answer on Stackoverflow
Solution 6 - JavascriptLinhView Answer on Stackoverflow
Solution 7 - Javascriptyogesh lodhaView Answer on Stackoverflow
Solution 8 - JavascriptWilcoView Answer on Stackoverflow
Solution 9 - JavascriptArne MView Answer on Stackoverflow
Solution 10 - JavascriptZeeshan LiaqatView Answer on Stackoverflow