jQuery Ajax Request inside Ajax Request

JqueryAjaxGoogle MapsInstagram

Jquery Problem Overview


Is it possible to make an ajax request inside another ajax request? because I need some data from first ajax request to make the next ajax request.

First I'm using Google Maps API to get LAT & LNG, after that I use that LAT & LNG to request Instagram API (search based location).

Once again, is this possible, and if so how?

$('input#search').click(function(e) {
	e.preventDefault();
	var source = $('select[name=state] option:selected').text()+' '+$('select[name=city] option:selected').text()+' '+$('select[name=area] option:selected').text();
	var source = source.replace(/ /g, '+');
	if(working == false) {
		working = true;
		$(this).replaceWith('<span id="big_loading"></span>');
		$.ajax({
			type:'POST',
			url:'/killtime_local/ajax/location/maps.json',
			dataType:'json',
			cache: false,
			data:'via=ajax&address='+source,
			success:function(results) {
			// this is where i get the latlng
			}
		});
	} else {
		alert('please, be patient!');
	}
});

Jquery Solutions


Solution 1 - Jquery

Here is an example:

$.ajax({
    type: "post",
    url: "ajax/example.php",
    data: 'page=' + btn_page,
    success: function (data) {
        var a = data; // This line shows error.
        $.ajax({
            type: "post",
            url: "example.php",
            data: 'page=' + a,
            success: function (data) {
   
            }
        });
    }
});

Solution 2 - Jquery

Call second ajax from 'complete'

Here is the example

   var dt='';
   $.ajax({
    type: "post",
    url: "ajax/example.php",
    data: 'page='+btn_page,
    success: function(data){
        dt=data;
        /*Do something*/
    },
    complete:function(){
        $.ajax({
           var a=dt; // This line shows error.
           type: "post",
           url: "example.php",
           data: 'page='+a,
           success: function(data){
              /*do some thing in second function*/
           },
       });
    }
});

Solution 3 - Jquery

This is just an example. You may like to customize it as per your requirement.

 $.ajax({
      url: 'ajax/test1.html',
      success: function(data1) {
        alert('Request 1 was performed.');
        $.ajax({
            type: 'POST',
            url: url,
            data: data1, //pass data1 to second request
            success: successHandler, // handler if second request succeeds 
            dataType: dataType
        });
    }
});

For more details : see this

Solution 4 - Jquery

$.ajax({
    url: "<?php echo site_url('upToWeb/ajax_edit/')?>/" + id,
    type: "GET",
    dataType: "JSON",
    success: function (data) {
        if (data.web == 0) {
            if (confirm('Data product upToWeb ?')) {
                $.ajax({
                    url: "<?php echo site_url('upToWeb/set_web/')?>/" + data.id_item,
                    type: "post",
                    dataType: "json",
                    data: {web: 1},
                    success: function (respons) {
                        location.href = location.pathname;
                    },
                    error: function (xhr, ajaxOptions, thrownError) { // Ketika terjadi error
                        alert(xhr.responseText); // munculkan alert
                    }
                });
            }
        }
        else {
            if (confirm('Data product DownFromWeb ?')) {
                $.ajax({
                    url: "<?php echo site_url('upToWeb/set_web/')?>/" + data.id_item,
                    type: "post",
                    dataType: "json",
                    data: {web: 0},
                    success: function (respons) {
                        location.href = location.pathname;
                    },
                    error: function (xhr, ajaxOptions, thrownError) { // Ketika terjadi error
                        alert(xhr.responseText); // munculkan alert
                    }
                });
            }
        }
    },

    error: function (jqXHR, textStatus, errorThrown) {
        alert('Error get data from ajax');
    }

});

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionBias TegaralagaView Question on Stackoverflow
Solution 1 - JqueryTariqView Answer on Stackoverflow
Solution 2 - JqueryNishad UpView Answer on Stackoverflow
Solution 3 - JqueryVedView Answer on Stackoverflow
Solution 4 - JqueryYusnur HidayahView Answer on Stackoverflow