Javascript array search and remove string?

I have:

var array = new Array();
array.push("A");
array.push("B");
array.push("C");

I want to be able to do something like:

array.remove("B");

but there is no remove function. How do I accomplish this?

I'm actually updating this thread with a more recent 1-line solution:

let arr = ['A', 'B', 'C'];
arr = arr.filter(e => e !== 'B'); // will return ['A', 'C']

The idea is basically to filter the array by selecting all elements different to the element you want to remove.

Note: will remove all occurrences.

EDIT:

If you want to remove only the first occurence:

t = ['A', 'B', 'C', 'B'];
t.splice(t.indexOf('B'), 1); // will return ['B'] and t is now equal to ['A', 'C', 'B']

Loop through the list in reverse order, and use the .splice method.

var array = ['A', 'B', 'C']; // Test
var search_term = 'B';

for (var i=array.length-1; i>=0; i--) {
    if (array[i] === search_term) {
        array.splice(i, 1);
        // break;       //<-- Uncomment  if only the first term has to be removed
    }
}

The reverse order is important when all occurrences of the search term has to be removed. Otherwise, the counter will increase, and you will skip elements.

When only the first occurrence has to be removed, the following will also work:

var index = array.indexOf(search_term);    // <-- Not supported in <IE9
if (index !== -1) {
    array.splice(index, 1);
}

List of One Liners

Let's solve this problem for this array:

var array = ['A', 'B', 'C'];

1. Remove only the first: Use If you are sure that the item exist

array.splice(array.indexOf('B'), 1);

2. Remove only the last: Use If you are sure that the item exist

array.splice(array.lastIndexOf('B'), 1);

3. Remove all occurrences:

array = array.filter(v => v !== 'B'); 

DEMO

You need to find the location of what you're looking for with .indexOf() then remove it with .splice()

function remove(arr, what) {
    var found = arr.indexOf(what);

    while (found !== -1) {
        arr.splice(found, 1);
        found = arr.indexOf(what);
    }
}

var array = new Array();
array.push("A");
array.push("B");
array.push("C");
 ​   
remove(array, 'B');
alert(array)​​​​;

This will take care of all occurrences.

Simply

array.splice(array.indexOf(item), 1);

Simple solution (ES6)

If you don't have duplicate element

Array.prototype.remove = function(elem) {
  var indexElement = this.findIndex(el => el === elem);
  if (indexElement != -1)
    this.splice(indexElement, 1);
  return this;
};   

Online demo (fiddle)

const changedArray = array.filter( function(value) {
  return value !== 'B'
});

or you can use :

const changedArray = array.filter( (value) => value === 'B');

The changedArray will contain the without value 'B'

You have to write you own remove. You can loop over the array, grab the index of the item you want to remove, and use splice to remove it.

Alternatively, you can create a new array, loop over the current array, and if the current object doesn't match what you want to remove, put it in a new array.

use:

array.splice(2, 1);

This removes one item from the array, starting at index 2 (3rd item)

use array.splice

/*array.splice(index , howMany[, element1[, ...[, elementN]]])

array.splice(index) // SpiderMonkey/Firefox extension*/

array.splice(1,1)

Source: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice

This only valid on str list, look up this

myStrList.filter(item=> !["deletedValue","deletedValue2"].includes(item))