java.lang.IllegalArgumentException: Illegal pattern character 'Y' for SimpleDateFormat

Java

Java Problem Overview


The following code:

Calendar now = Calendar.getInstance();
month = now.get(Calendar.MONTH) + 1;
year = now.get(Calendar.YEAR);
System.out.println("Month " + month + " year " + year);
SimpleDateFormat dt1 = new SimpleDateFormat("MMMM YYYY");
e.setMonthnYear(dt1.format(now.getTime()));

After deploying on server is showing following exception:

java.lang.IllegalArgumentException: Illegal pattern character 'Y'
	java.text.SimpleDateFormat.compile(SimpleDateFormat.java:768)
	java.text.SimpleDateFormat.initialize(SimpleDateFormat.java:575)
	java.text.SimpleDateFormat.<init>(SimpleDateFormat.java:500)
	java.text.SimpleDateFormat.<init>(SimpleDateFormat.java:475)
	iland.employee.EmployeeAction.fetchAllAtted(EmployeeAction.java:169)
	sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
	sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
	sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
	java.lang.reflect.Method.invoke(Method.java:597)

On my local host I am using JDK v1.8 and the above code is working perfectly, but on server it is not working.

How can I resolve this?

Java Solutions


Solution 1 - Java

try

SimpleDateFormat dt1 = new SimpleDateFormat("MMMM yyyy");

Solution 2 - Java

On your Local you might be using Java 8, so do check the version of Java on your Server. If it is less than Java JDK 7 the capital Y will not work.

Refer To Java 6 Oracle Docs for SimpleDateFormat

You have to write year in small y not in capitals Y.

Like for 2 digit year:

 SimpleDateFormat dt1 = new SimpleDateFormat("yy");

And for 4 digit year:

 SimpleDateFormat dt1 = new SimpleDateFormat("yyyy");

In case if you are using Java 7 or above: You can use the capital Y which represents Week Year.

Refer to Java 7 Oracle Docs SimpleDateFormat

Solution 3 - Java

Android

The documentation differs from the implementation. The supported characters are defined in a string constant in SimpleDateFormat up to API level 23. From the source code:

static final String PATTERN_CHARS = "GyMdkHmsSEDFwWahKzZLc";

Since 'Y' (Week Year) is not included, the pattern validation throws the exception:

java.lang.IllegalArgumentException: Unknown pattern character 'Y'

A quick fix, when week year behaviour isn't required, is to use the 'y', e.g.: yyyy-MM-dd.

'Y' as a pattern character is supported as of API level 24.

Update

The documentation now lists the supported API levels for pattern characters.

Solution 4 - Java

As per the javadocs

If week year 'Y' is specified and the calendar doesn't support any week years,
the calendar year ('y') is used instead. The support of week years can be tested
with a call to getCalendar().isWeekDateSupported().

So the only problem is guess is your version of java < 1.7 because JRE1.7 has added 'Y' pattern for Week year and in JRE1.6 there is no pattern for this.

Or simply stay on the safer side use y instead of Y.

One more thing always try to use locale to be on safer side

SimpleDateFormat dt1 = new SimpleDateFormat("MMMM yyyy",java.util.Locale.ENGLISH);

Solution 5 - Java

i have taken this table from java docs.

Letter	Date or Time Component	Presentation	Examples
G	Era designator	Text	AD
y	Year	Year	1996; 96
M	Month in year	Month	July; Jul; 07
w	Week in year	Number	27
W	Week in month	Number	2
D	Day in year	Number	189
d	Day in month	Number	10
F	Day of week in month	Number	2
E	Day in week	Text	Tuesday; Tue

In your case just replace"Y" to "y" you can see Docs here

Solution 6 - Java

From java.text.SimpleDateFormat:

Letter 	Date or Time Component 	Presentation 	Examples 
y 	    Year 	                Year 	        1996; 96
Y 	    Week year 	            Year 	        2009; 09

You are asking for Week year instead of year in your call to SimpleDateFormat()

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionxrcwrnView Question on Stackoverflow
Solution 1 - JavaEvgeniy DorofeevView Answer on Stackoverflow
Solution 2 - JavaMandar PanditView Answer on Stackoverflow
Solution 3 - JavaaruhView Answer on Stackoverflow
Solution 4 - JavaSparkOnView Answer on Stackoverflow
Solution 5 - JavajaiminView Answer on Stackoverflow
Solution 6 - JavaDavidPostillView Answer on Stackoverflow