How to use patterns in a case statement?

BashCase Statement

Bash Problem Overview


The man page says that case statements use "filename expansion pattern matching".
I usually want to have short names for some parameters, so I go:

case $1 in
    req|reqs|requirements) TASK="Functional Requirements";;
    met|meet|meetings) TASK="Meetings with the client";;
esac

logTimeSpentIn "$TASK"

I tried patterns like req* or me{e,}t which I understand would expand correctly to match those values in the context of filename expansion, but it doesn't work.

Bash Solutions


Solution 1 - Bash

Brace expansion doesn't work, but *, ? and [] do. If you set shopt -s extglob then you can also use extended pattern matching:

  • ?() - zero or one occurrences of pattern
  • *() - zero or more occurrences of pattern
  • +() - one or more occurrences of pattern
  • @() - one occurrence of pattern
  • !() - anything except the pattern

Here's an example:

shopt -s extglob
for arg in apple be cd meet o mississippi
do
    # call functions based on arguments
    case "$arg" in
        a*             ) foo;;    # matches anything starting with "a"
        b?             ) bar;;    # matches any two-character string starting with "b"
        c[de]          ) baz;;    # matches "cd" or "ce"
        me?(e)t        ) qux;;    # matches "met" or "meet"
        @(a|e|i|o|u)   ) fuzz;;   # matches one vowel
        m+(iss)?(ippi) ) fizz;;   # matches "miss" or "mississippi" or others
        *              ) bazinga;; # catchall, matches anything not matched above
    esac
done

Solution 2 - Bash

I don't think you can use braces.

According to the Bash manual about case in Conditional Constructs. > Each pattern undergoes tilde > expansion, parameter expansion, > command substitution, and arithmetic > expansion.

Nothing about Brace Expansion unfortunately.

So you'd have to do something like this:

case $1 in
    req*)
        ...
        ;;
    met*|meet*)
        ...
        ;;
    *)
        # You should have a default one too.
esac

Solution 3 - Bash

if and grep -Eq

arg='abc'
if echo "$arg" | grep -Eq 'a.c|d.*'; then
  echo 'first'
elif echo "$arg" | grep -Eq 'a{2,3}'; then
  echo 'second'
fi

where:

  • -q prevents grep from producing output, it just produces the exit status
  • -E enables extended regular expressions

I like this because:

One downside is that this is likely slower than case since it calls an external grep program, but I tend to consider performance last when using Bash.

case is POSIX 7

Bash appears to follow POSIX by default without shopt as mentioned by https://stackoverflow.com/a/4555979/895245

Here is the quote: http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_01 section "Case Conditional Construct":

> The conditional construct case shall execute the compound-list corresponding to the first one of several patterns (see Pattern Matching Notation) [...] Multiple patterns with the same compound-list shall be delimited by the '|' symbol. [...]

> The format for the case construct is as follows:

> case word in [(] pattern1 ) compound-list ;; [[(] pattern[ | pattern] ... ) compound-list ;;] ... [[(] pattern[ | pattern] ... ) compound-list] esac

and then http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_13 section "2.13. Pattern Matching Notation" only mentions ?, * and [].

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionRamiro RelaView Question on Stackoverflow
Solution 1 - BashDennis WilliamsonView Answer on Stackoverflow
Solution 2 - BashplundraView Answer on Stackoverflow
Solution 3 - BashCiro Santilli Путлер Капут 六四事View Answer on Stackoverflow