The syntax to store the command output into a variable is `var=$(command)`.

So you can directly do:

    result=$(ls -l | grep -c &quot;rahul.*patle&quot;)

And the variable `$result` will contain the number of matches.

I have a list of tuples like

    data = [
    (&#39;r1&#39;, &#39;c1&#39;, avg11, stdev11),
    (&#39;r1&#39;, &#39;c2&#39;, avg12, stdev12),
    (&#39;r2&#39;, &#39;c1&#39;, avg21, stdev21),
    (&#39;r2&#39;, &#39;c2&#39;, avg22, stdev22)
    ]

and I would like to put them into a pandas DataFrame with rows named by the first column and columns named by the 2nd column. It seems the way to take care of the row names is something like `pandas.DataFrame([x[1:] for x in data], index = [x[0] for x in data])` but how do I take care of the columns to get a 2x2 matrix (the output from the previous set is 3x4)? Is there a more intelligent way of taking care of row labels as well, instead of explicitly omitting them?

**EDIT** It seems I will need 2 DataFrames - one for averages and one for standard deviations, is that correct? Or can I store a list of values in each &quot;cell&quot;?

Construct pandas DataFrame from list of tuples of (row,col,values)

I&#39;ve got a simple app set up that shows a list of `Projects`. I&#39;ve removed the `autopublish` package so that I&#39;m not sending everything to the client.

     &lt;template name=&quot;projectsIndex&quot;&gt;    
       {{#each projects}}      
         {{name}}
       {{/each}}
     &lt;/template&gt;

When `autopublish` was turned on, this would display all the projects:

    if Meteor.isClient
      Template.projectsIndex.projects = Projects.find()

With it removed, I have to additionally do:

     if Meteor.isServer
       Meteor.publish &quot;projects&quot;, -&gt;
         Projects.find()
     if Meteor.isClient
       Meteor.subscribe &quot;projects&quot;
       Template.projectsIndex.projects = Projects.find()

So, is it accurate to say that the client-side `find()` method only searches records which have been published from the server-side? It&#39;s been tripping me up because I felt like I should only be calling `find()` once.

Understanding Meteor Publish / Subscribe

I want to find out the number of directories and files in home directory and store that in a shell variable. I am using the following set of commands.

    command=&quot;ls -l | grep -c \&quot;rahul.*patle\&quot;&quot;
    eval $command

I want to store the result in a variable. How can I do this?

How to store command results in a shell variable?

I want to find out the number of directories and files in home directory and store that in a shell variable. I am using the following set of commands.
<pre><code class="hljs language-bash">command="ls -l | grep -c \"rahul.*patle\""
eval $command
</code></pre>
I want to store the result in a variable. How can I do this?

Is there any way to determine if a process (script) runs inside an lxc container (~ Docker runtime)? I know that some programs are able to detect whether they run inside a virtual machine, is something similar available for lxc/docker?

How to determine if a process runs inside lxc/Docker?

I&#39;m trying to write a bash script that will get the output of a command that runs in the background. Unfortunately I can&#39;t get it to work, the variable I assign the output to is empty - if I replace the assignment with an echo command everything works as expected though.

    #!/bin/bash
    
    function test {
        echo &quot;$1&quot;
    }
    
    echo $(test &quot;echo&quot;) &amp;
    wait
    
    a=$(test &quot;assignment&quot;) &amp;
    wait
    
    echo $a
    
    echo done

This code produces the output:

    echo
    
    done

Changing the assignment to 

    a=`echo $(test &quot;assignment&quot;) &amp;`

works, but it seems like there should be a better way of doing this.

Bash: Capture output of command run in background

The following code works on the command line

    mysql --user=&#39;myusername&#39; --password=&#39;mypassword&#39; --database=&#39;mydatabase&#39; --execute=&#39;DROP DATABASE myusername; 
    CREATE DATABASE mydatabase;&#39;

However, it doesn&#39;t work on bash file on execution

    #!/bin/bash
    user=myusername
    password=mypassword
    database=mydatabase

    mysql --user=&#39;$user&#39; --password=&#39;$password&#39; --database=&#39;$database&#39; --execute=&#39;DROP DATABASE $user; CREATE DATABASE $database;&#39;

I receive the following error:
&gt;ERROR 1045 (28000): Access denied for user &#39;$user&#39;@&#39;localhost&#39; (using password: YES)

How to make the bash file run as the command line?

How to run MySQL command on bash?

Let&#39;s take a little example:

    $ cat source.sh
    #!/bin/bash
    echo &quot;I&#39;m file source-1&quot;

    . source-2.sh

And:

    $ cat source-2.sh
    #!/bin/bash
    echo &quot;I&#39;m file source-2&quot;

Now run:

    $ ./source.sh
    I&#39;m file source-1
    I&#39;m file source-2

If I&#39;ll change the call of the second file in first:

    $ cat source.sh
    #!/bin/bash
    echo &quot;I&#39;m file source-1&quot;

    source source-2.sh

It will have the same effect as using `dot`.

What is difference between these methods?





Using dot or &quot;source&quot; while calling another script - what is the difference?

I have this command that does what I want but I can&#39;t get to alias it in my .bashrc (note that it uses both single and double quotes):

    svn status | awk &#39;$1 ==&quot;M&quot;{print $2;}&#39;

I&#39;ve tried:
  
    alias xx=&quot;svn status | awk &#39;$1 ==\&quot;M\&quot;{print $2;}&#39;&quot;

And some other common sense combinations with no luck.. I know that bash is very picky with quotes.. So what&#39;s the correct way to alias it and why ? Thanks

bash alias command with both single and double quotes

I am confused about what error code the command will return when executing a variable assignment plainly and with command substitution:

    a=$(false); echo $?

It outputs `1`, which let me think that variable assignment doesn&#39;t sweep or produce new error code upon the last one. But when I tried this:

    false; a=&quot;&quot;; echo $?

It outputs `0`, obviously this is what `a=&quot;&quot;` returns and it override `1` returned by `false`.

I want to know why this happens, is there any particularity in variable assignment that differs from other normal commands? Or just be cause `a=$(false)` is considered to be a single command and only command substitution part make sense?

**-- UPDATE --**

Thanks everyone, from the answers and comments I got the point &quot;When you assign a variable using command substitution, the exit status is the status of the command.&quot; (by @Barmar), this explanation is excellently clear and easy to understand, but speak doesn&#39;t precise enough for programmers, I want to see the reference of this point from authorities such as TLDP or GNU man page, please help me find it out, thanks again!

Exit code of variable assignment to command substitution in Bash

Created a childprocess using shelljs

  
    !/usr/bin/env node
    
    require(&#39;/usr/local/lib/node_modules/shelljs/global&#39;);
       fs = require(&quot;fs&quot;);  
       var child=exec(&quot;sudo mongod &amp;&quot;,{async:true,silent:true});
          
       function on_exit(){
        	console.log(&#39;Process Exit&#39;);
        	child.kill(&quot;SIGINT&quot;);
        	process.exit(0)
        }
      
        process.on(&#39;SIGINT&#39;,on_exit);
        process.on(&#39;exit&#39;,on_exit);
        


Child process is still running .. after kill the parent process


How to kill childprocess in nodejs?

Its must be a popular question but I could not find an answer.

How to move all files via * including hidden files as well to parent directory like this:

    mv /path/subfolder/* /path/

This will move all files to parent directory like expected but will not move hidden files. How to do that?



How to move all files including hidden files into parent directory via *

I&#39;ve a file with a sequence of JSON element:

    { element0: &quot;lorem&quot;, value0: &quot;ipsum&quot; }
    { element1: &quot;lorem&quot;, value0: &quot;ipsum&quot; }
    ...
    { elementN: &quot;lorem&quot;, value0: &quot;ipsum&quot; }

Is there a shell script to format JSON to display file content in a readable form? 

I&#39;ve seen [this][1] post, and I think is a good starting point!

My idea is to iterate rows in the file and then: 

    while read row; do echo ${row} | python -mjson.tool; done &lt; &quot;file_name&quot;

Does anyone have any other ideas?

  [1]: https://stackoverflow.com/questions/352098/how-can-i-pretty-print-json-from-the-command-line

How can I pretty-print a JSON file from the command line?

How can I highlight the Bash/shell commands in Markdown files?

---

For example, to highlight `js`, I write:

&lt;!-- language: lang-none --&gt;

    ```js
    function () { return &quot;This code is highlighted as Javascript!&quot;}
    ```

To highlight HTML code I use ` ```html `.

How can we highlight Bash/shell commands?





Content Type	Original Author	Original Content on Stackoverflow
Question	Rahul KP	View Question on Stackoverflow
Solution 1 - Bash	fedorqui	View Answer on Stackoverflow

How to store command results in a shell variable?

Bash Problem Overview

Bash Solutions

Solution 1 - Bash

Understanding Meteor Publish / Subscribe

Construct pandas DataFrame from list of tuples of (row,col,values)

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