How to simulate a touch event in Android?

AndroidAdbGesture Recognition

Android Problem Overview


How to simulate a touch event with Android while giving the X and Y coordinates manually?

Android Solutions


Solution 1 - Android

Valentin Rocher's method works if you've extended your view, but if you're using an event listener, use this:

view.setOnTouchListener(new OnTouchListener()
{
    public boolean onTouch(View v, MotionEvent event)
    {
        Toast toast = Toast.makeText(
            getApplicationContext(), 
            "View touched", 
            Toast.LENGTH_LONG
        );
        toast.show();

        return true;
    }
});
            
            
// Obtain MotionEvent object
long downTime = SystemClock.uptimeMillis();
long eventTime = SystemClock.uptimeMillis() + 100;
float x = 0.0f;
float y = 0.0f;
// List of meta states found here: developer.android.com/reference/android/view/KeyEvent.html#getMetaState()
int metaState = 0;
MotionEvent motionEvent = MotionEvent.obtain(
    downTime, 
    eventTime, 
    MotionEvent.ACTION_UP, 
    x, 
    y, 
    metaState
);

// Dispatch touch event to view
view.dispatchTouchEvent(motionEvent);

For more on obtaining a MotionEvent object, here is an excellent answer: https://stackoverflow.com/questions/5867059/android-how-to-create-a-motionevent

Solution 2 - Android

Here is a monkeyrunner script that sends touch and drags to an application. I have been using this to test that my application can handle rapid repetitive swipe gestures.

# This is a monkeyrunner jython script that opens a connection to an Android
# device and continually sends a stream of swipe and touch gestures.
#
# See http://developer.android.com/guide/developing/tools/monkeyrunner_concepts.html
#
# usage: monkeyrunner swipe_monkey.py
#

# Imports the monkeyrunner modules used by this program
from com.android.monkeyrunner import MonkeyRunner, MonkeyDevice

# Connects to the current device
device = MonkeyRunner.waitForConnection()

# A swipe left from (x1, y) to (x2, y) in 2 steps
y = 400
x1 = 100
x2 = 300
start = (x1, y)
end = (x2, y)
duration = 0.2
steps = 2
pause = 0.2

for i in range(1, 250):
    # Every so often inject a touch to spice things up!
    if i % 9 == 0:
        device.touch(x2, y, 'DOWN_AND_UP')
        MonkeyRunner.sleep(pause)
    # Swipe right
    device.drag(start, end, duration, steps)
    MonkeyRunner.sleep(pause)
    # Swipe left
    device.drag(end, start, duration, steps)
    MonkeyRunner.sleep(pause)

Solution 3 - Android

use adb Shell Commands to simulate the touch event

adb shell input tap x y 

and also 

adb shell sendevent /dev/input/event0 3 0 5 
adb shell sendevent /dev/input/event0 3 1 29 

Solution 4 - Android

You should give the new monkeyrunner a go. Maybe this can solve your problems. You put keycodes in it for testing, maybe touch events are also possible.

Solution 5 - Android

If I understand clearly, you want to do this programatically. Then, you could use the onTouchEvent method of View, and create a MotionEvent with the coordinates you need.

Solution 6 - Android

When using Monkey Script I noticed that DispatchPress(KEYCODE_BACK) is doing nothing which really suck. In many cases this is due to the fact that the Activity doesn't consume the Key event. The solution to this problem is to use a mix of monkey script and adb shell input command in a sequence.

1 Using monkey script gave some great timing control. Wait a certain amount of second for the activity and is a blocking adb call.
2 Finally sending adb shell input keyevent 4 will end the running APK.

EG

adb shell monkey -p com.my.application -v -v -v -f /sdcard/monkey_script.txt 1
adb shell input keyevent 4

Solution 7 - Android

MotionEvent is generated only by touching the screen.

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionindiraView Question on Stackoverflow
Solution 1 - AndroiddvsView Answer on Stackoverflow
Solution 2 - AndroidWarwickView Answer on Stackoverflow
Solution 3 - AndroidArjun PrakashView Answer on Stackoverflow
Solution 4 - AndroidkeyboardsurferView Answer on Stackoverflow
Solution 5 - AndroidValentin RocherView Answer on Stackoverflow
Solution 6 - AndroidThomas J YounsiView Answer on Stackoverflow
Solution 7 - AndroidindiraView Answer on Stackoverflow