How to query MongoDB to test if an item exists?

MongodbFind

Mongodb Problem Overview


Does MongoDB offer a find or query method to test if an item exists based on any field value? We just want check existence, not return the full contents of the item.

Mongodb Solutions


Solution 1 - Mongodb

Since you don't need the count, you should make sure the query will return after it found the first match. Since count performance is not ideal, that is rather important. The following query should accomplish that:

db.Collection.find({ /* criteria */}).limit(1).size();

Note that find().count() by default does not honor the limit clause and might hence return unexpected results (and will try to find all matches). size() or count(true) will honor the limit flag.

If you want to go to extremes, you should make sure that your query uses covered indexes. Covered indexes only access the index, but they require that the field you query on is indexed. In general, that should do it because a count() obviously does not return any fields. Still, covered indexes sometimes need rather verbose cursors:

db.values.find({"value" : 3553}, {"_id": 0, "value" : 1}).limit(1).explain();

{
  // ...
  "cursor" : "BtreeCursor value_1",
  "indexOnly" : true,  // covered!
}

Unfortunately, count() does not offer explain(), so whether it's worth it or not is hard to say. As usual, measurement is a better companion than theory, but theory can at least save you from the bigger problems.

Solution 2 - Mongodb

I dont believe that there is a straight way of checking the existence of the item by its value. But you could do that by just retrieving only id (with field selection)

db.your_collection.find({..criteria..}, {"_id" : 1});

Solution 3 - Mongodb

Starting Mongo 2.6, count has a limit optional parameter, which makes it a viable alternative to find whether a document exists or not:

db.collection.count({}, { limit: 1 })
// returns 1 if exists and 0 otherwise

or with a filtering query:

db.collection.count({/* criteria */}, { limit: 1 })

Limiting the number of matching occurrences makes the collection scan stop whenever a match is found instead of going through the whole collection.


Starting Mongo 4.0.3, since count() is considered deprecated we can use countDocuments instead:

db.collection.countDocuments({}, { limit: 1 })

or with a filtering query:

db.collection.countDocuments({/* criteria */}, { limit: 1 })

Solution 4 - Mongodb

> It is significantly faster to use find() + limit() because findOne() > will always read + return the document if it exists. find() just > returns a cursor (or not) and only reads the data if you iterate > through the cursor.

db.collection.find({_id: "myId"}, {_id: 1}).limit(1)

(instead of db.collection.findOne({_id: "myId"}, {_id: 1})).

Look at more details: Checking if a document exists – MongoDB slow findOne vs find

Solution 5 - Mongodb

filter_dict = {"key":value}
if db.collection.count_documents(filter_dict):
    print("item is existed")
else:
    print("item is not existed")

Solution 6 - Mongodb

An update to Xavier's answer:

db.collection.countDocuments({}, { limit: 1 })

Expects a callback as a second argument now, so this can be used instead:

db.collection.countDocuments({}).limit(1)

Solution 7 - Mongodb

Im currently using something like this:

async check(query) {
  const projection = { _id: 1 };

  return !!db.collection.findOne(query, projection);
}

It will return true or false, of course returning only _id: 1 for smallest data transfer.

Solution 8 - Mongodb

I'm surprised to find the $exists operator not being mentioned here.

db.collection.findOne({myFieldName: {$exists: 1}})

If you want the opposite (find one where the field does not exists): db.collection.findOne({myFieldName: {$exists: 0}})

If you want to get a cursor, use find() instad of findOne() and you can get a boolean with db.collection.find({myFieldName: {$exists: 1}}).isExhausted()

Note that isExhausted() is a mongo shell method only

Solution 9 - Mongodb

I have simply used lodash framework - _isEmpty();

const {
    MongoClient,
    ObjectId
} = require('mongodb');
const _ = require('lodash');

MongoClient.connect(testURL, {
    useNewUrlParser: true
}, (err, client) => {
    let db = client.db('mycompany');

    if (err) {
        console.log('unable to connect to the mycompany database');
    } else {
        console.log('test connection to the database');
    };

    db.collection('employee').find({
        name: 'Test User'
    }).toArray((err, result) => {

        if (err) {
            console.log('The search errored');
        } else if (_.isEmpty(result)) {
            console.log('record not found')
        } else {
            console.log(result);
        };
    });
    client.close();
});

Solution 10 - Mongodb

If you use Java and Spring you can use that:

public interface UserRepository extends MongoRepository<User, ObjectId> {

    boolean existsByUsername(String username);

}

It works for me.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionuser646584View Question on Stackoverflow
Solution 1 - MongodbmnemosynView Answer on Stackoverflow
Solution 2 - MongodbRameshVelView Answer on Stackoverflow
Solution 3 - MongodbXavier GuihotView Answer on Stackoverflow
Solution 4 - MongodbgihanchanukaView Answer on Stackoverflow
Solution 5 - Mongodbwendell sunView Answer on Stackoverflow
Solution 6 - MongodbVolodymyr BobyrView Answer on Stackoverflow
Solution 7 - MongodbMartin HoangView Answer on Stackoverflow
Solution 8 - MongodbErawView Answer on Stackoverflow
Solution 9 - MongodbufookoroView Answer on Stackoverflow
Solution 10 - MongodbGeorge GalantsevView Answer on Stackoverflow