How to pause and resume CSS3 animation using JavaScript?

JavascriptAnimationCssResume

Javascript Problem Overview


I've tried to google and look from this forum a solution for my problem but no luck so far. I would like to pause my CSS3 animation (image slide show) by clicking a picture and also resume to the same animation by clicking a picture.

I know how to pause the slide show and I was also able to resume it once, but then it stops working if try to pause and resume more than one time. Here is how my code looks like:

<!DOCTYPE html>
<html>

<head>
<title></title>
<style type="text/css">
.pic {
    position: absolute;
    opacity: 0;
}

#pic1 {
	-webkit-animation: pic1 4s infinite linear;
}

#pic2 {
	-webkit-animation: pic2 4s infinite linear;
}

@-webkit-keyframes pic1 {
    0%   {opacity: 0;}
    5%   {opacity: 1;}
    45%  {opacity: 1;}
    50%  {opacity: 0;}
    100% {opacity: 0;}
}

@-webkit-keyframes pic2 {
    0%   {opacity: 0;}
    50%  {opacity: 0;}
    55%  {opacity: 1;}
    95%  {opacity: 1;}
    100% {opacity: 0;}
}
</style>

<script type="text/javascript">
function doStuff(){
	var pic1 = document.getElementById("pic1");
	var pic2 = document.getElementById("pic2");
	
	pic1.style.webkitAnimationPlayState="paused";
	pic2.style.webkitAnimationPlayState="paused";
	
	pic1.onclick = function(){
        pic1.style.webkitAnimationPlayState="running";
        pic2.style.webkitAnimationPlayState="running";
    }
    
    pic2.onclick = function(){
        pic1.style.webkitAnimationPlayState="running";
        pic2.style.webkitAnimationPlayState="running";
    }
}
</script>
</head>  

<body>
    <img id="pic1" class="pic" src="photo1.jpg" />
    <img id="pic2" class="pic" src="photo2.jpg" onclick="doStuff()" />
</body>                                                                

</html>

I don't want to use any JS libraries (e.g. jQuery) or any other external solution.

My guess is that my functions inside doStuff function are still running and that's why pause and resume works only once.

Is there a way to clear these functions after I have clicked them once? Or am I trying to do this in a totally wrong way? Help is appreciated. :)

Javascript Solutions


Solution 1 - Javascript

I find it easier to do it with a css class. With it, you can use prefixes for every browser.

.paused{
    -webkit-animation-play-state:paused;
    -moz-animation-play-state:paused;
    -o-animation-play-state:paused; 
    animation-play-state:paused;
}

Then you only have to add or remove this class to your animated element yo pause / resume the animation.

Solution 2 - Javascript

Here is a solution using javascript:

var imgs = document.querySelectorAll('.pic');

for (var i = 0; i < imgs.length; i++) {
  imgs[i].onclick = toggleAnimation;
  imgs[i].style.webkitAnimationPlayState = 'running';
}

function toggleAnimation() {
  var style;
  for (var i = 0; i < imgs.length; i++) {
    style = imgs[i].style;
    if (style.webkitAnimationPlayState === 'running') {
      style.webkitAnimationPlayState = 'paused';
      document.body.className = 'paused';
    } else {
      style.webkitAnimationPlayState = 'running';
      document.body.className = '';
    }
  }
}

.pic {
  position: absolute;
  opacity: 0;
}

#pic1 {
  -webkit-animation: pic1 4s infinite linear;
}

#pic2 {
  -webkit-animation: pic2 4s infinite linear;
}

@-webkit-keyframes pic1 {
  0% {
    opacity: 0;
  }
  5% {
    opacity: 1;
  }
  45% {
    opacity: 1;
  }
  50% {
    opacity: 0;
  }
  100% {
    opacity: 0;
  }
}

@-webkit-keyframes pic2 {
  0% {
    opacity: 0;
  }
  50% {
    opacity: 0;
  }
  55% {
    opacity: 1;
  }
  95% {
    opacity: 1;
  }
  100% {
    opacity: 0;
  }
}

.paused {
  background-color: #ddd;
}

<img id="pic1" class="pic" src="http://placehold.it/200x200/ff0000/ffffff">
<img id="pic2" class="pic" src="http://placehold.it/200x200/ff00ff/ffffff">

jQuery solution (shorter and more readable):

var imgs = $('.pic'),
  playState = '-webkit-animation-play-state';

imgs.click(function() {
  imgs.css(playState, function(i, v) {
    return v === 'paused' ? 'running' : 'paused';
  });
  $('body').toggleClass('paused', $(this).css(playState) === 'paused');
});

.pic {
  position: absolute;
  opacity: 0;
}

#pic1 {
  -webkit-animation: pic1 4s infinite linear;
}

#pic2 {
  -webkit-animation: pic2 4s infinite linear;
}

@-webkit-keyframes pic1 {
  0% {
    opacity: 0;
  }
  5% {
    opacity: 1;
  }
  45% {
    opacity: 1;
  }
  50% {
    opacity: 0;
  }
  100% {
    opacity: 0;
  }
}

@-webkit-keyframes pic2 {
  0% {
    opacity: 0;
  }
  50% {
    opacity: 0;
  }
  55% {
    opacity: 1;
  }
  95% {
    opacity: 1;
  }
  100% {
    opacity: 0;
  }
}

.paused {
  background-color: #ddd;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<img id="pic1" class="pic" src="http://placehold.it/200x200/ff0000/ffffff">
<img id="pic2" class="pic" src="http://placehold.it/200x200/ff00ff/ffffff">

Solution 3 - Javascript

This is to extend the answer given by Luis Hijarrubia

.pause {
   -webkit-animation-play-state: paused !important; 
   -moz-animation-play-state: paused !important; 
   -o-animation-play-state: paused !important;
    animation-play-state: paused !important;
}

In my page I was triggering the change of class from the parent element. All I wanted to do was rotate the image inside. But it seems that because I was not using the hover, the adding of the paused class made no difference to the animation state.

The use of !important ensured that these values were overwritten by the new added CSS values.

Solution 4 - Javascript

var e = document.getElementsById("Your_Id");


e.addEventListener("animationstart", listener, false);
e.addEventListener("animationend", listener, false);
e.addEventListener("animationiteration", listener, false);


function listener(e) {  alert("Your POSITION parameter:" + .target.style.position);
  switch(e.type) {
    case "animationstart":
      d = "Started: elapsed time is " + e.elapsedTime;
      break;
    case "animationend":
      d = "Ended: elapsed time is " + e.elapsedTime;
      break;
    case "animationiteration":
      d= "New loop started at time " + e.elapsedTime;  alert("pausing for 1 seconddddddd!!!!!!!"); e.target.style.animationPlayState = "paused";		window.setTimeout(function(){e.target.style.animationPlayState = "running";}, 1000);
      break;
  }
}

Solution 5 - Javascript

I havent tested it but perhaps something like this?

<!DOCTYPE html>
<html>
<head>
<title></title>
<style type="text/css">
.pic {   position: absolute;opacity: 0;  }
.pic1 {  -webkit-animation: pic1 4s infinite linear;   }
.pic2 {  -webkit-animation: pic2 4s infinite linear;   }
@-webkit-keyframes pic1 {  0%   {opacity: 0;}
                           5%   {opacity: 1;}
                           45%  {opacity: 1;}
                           50%  {opacity: 0;}
                           100% {opacity: 0;}    }
@-webkit-keyframes pic2 {  0%   {opacity: 0;}
                           50%  {opacity: 0;}
                           55%  {opacity: 1;}
                           95%  {opacity: 1;}
                           100% {opacity: 0;}    }
</style>
<script type="text/javascript">
function doStuff(){
    var pic1 = document.getElementById("pic1");
    var pic2 = document.getElementById("pic2");

    pic1.className="pic paused";
    pic2.className="pic paused";

    pic1.onclick = function(){
       pic1.className="pic pic1";
       pic2.className="pic pic2";
    }
    pic2.onclick = function(){
       pic1.className="pic pic1";
       pic2.className="pic pic2";
    }
}
</script>
</head>  
<body>
    <img id="pic1" class="pic pic1" src="photo1.jpg" />
    <img id="pic2" class="pic pic2" src="photo2.jpg" onclick="doStuff()" />
</body>                                                                 
</html>

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionnqw1View Question on Stackoverflow
Solution 1 - JavascriptLuis HijarrubiaView Answer on Stackoverflow
Solution 2 - JavascriptŠime VidasView Answer on Stackoverflow
Solution 3 - JavascripttensaiView Answer on Stackoverflow
Solution 4 - JavascriptT.ToduaView Answer on Stackoverflow
Solution 5 - Javascriptuser40521View Answer on Stackoverflow