How to get HttpClient returning status code and response body?

JavaHttpApache Httpclient-4.x

Java Problem Overview


I am trying to get Apache HttpClient to fire an HTTP request, and then display the HTTP response code (200, 404, 500, etc.) as well as the HTTP response body (text string). It is important to note that I am using v4.2.2 because most HttpClient examples out there are from v.3.x.x and the API changed greatly from version 3 to version 4.

Unfortunately I've only been able to get HttpClient returning the status code or the response body (but not both).

Here's what I have:

// Getting the status code.
HttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet("http://whatever.blah.com");
HttpResponse resp = client.execute(httpGet);

int statusCode = resp.getStatusLine().getStatusCode();


// Getting the response body.
HttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet("http://whatever.blah.com");
ResponseHandler<String> handler = new BasicResponseHandler();

String body = client.execute(httpGet, handler);

So I ask: Using the v4.2.2 library, how can I obtain both status code and response body from the same client.execute(...) call? Thanks in advance!

Java Solutions


Solution 1 - Java

Don't provide the handler to execute.

Get the HttpResponse object, use the handler to get the body and get the status code from it directly

try (CloseableHttpClient httpClient = HttpClients.createDefault()) {
    final HttpGet httpGet = new HttpGet(GET_URL);
    
    try (CloseableHttpResponse response = httpClient.execute(httpGet)) {
        StatusLine statusLine = response.getStatusLine();
        System.out.println(statusLine.getStatusCode() + " " + statusLine.getReasonPhrase());
        String responseBody = EntityUtils.toString(response.getEntity(), StandardCharsets.UTF_8);
        System.out.println("Response body: " + responseBody);
    }
}

For quick single calls, the fluent API is useful:

Response response = Request.Get(uri)
        .connectTimeout(MILLIS_ONE_SECOND)
        .socketTimeout(MILLIS_ONE_SECOND)
        .execute();
HttpResponse httpResponse = response.returnResponse();
StatusLine statusLine = httpResponse.getStatusLine();

For older versions of java or httpcomponents, the code might look different.

Solution 2 - Java

You can avoid the BasicResponseHandler, but use the HttpResponse itself to get both status and response as a String.

HttpResponse response = httpClient.execute(get);

// Getting the status code.
int statusCode = response.getStatusLine().getStatusCode();

// Getting the response body.
String responseBody = EntityUtils.toString(response.getEntity());

Solution 3 - Java

BasicResponseHandler throws if the status is not 2xx. See its javadoc.

Here is how I would do it:

HttpResponse response = client.execute( get );
int code = response.getStatusLine().getStatusCode();
InputStream body = response.getEntity().getContent();
// Read the body stream

Or you can also write a ResponseHandler starting from BasicResponseHandler source that don't throw when the status is not 2xx.

Solution 4 - Java

Fluent facade API:

Response response = Request.Get(uri)
        .connectTimeout(MILLIS_ONE_SECOND)
        .socketTimeout(MILLIS_ONE_SECOND)
        .execute();
HttpResponse httpResponse = response.returnResponse();
StatusLine statusLine = httpResponse.getStatusLine();
if (statusLine.getStatusCode() == HttpStatus.SC_OK) {
    // 响应内容编码自适应?(好像没那么智能)
    String responseContent = EntityUtils.toString(
            httpResponse.getEntity(), StandardCharsets.UTF_8.name());
}

Solution 5 - Java

If you are using Spring

return new ResponseEntity<String>("your response", HttpStatus.ACCEPTED);

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionIAmYourFajaView Question on Stackoverflow
Solution 1 - JavaAviram SegalView Answer on Stackoverflow
Solution 2 - JavalkamalView Answer on Stackoverflow
Solution 3 - JavaeskatosView Answer on Stackoverflow
Solution 4 - JavaEdward LeeView Answer on Stackoverflow
Solution 5 - JavavsinghView Answer on Stackoverflow