how to get date of yesterday using php?

I want to get the yesterday date using specific date format in php this is the format:

$today = date("d.m.Y"); //15.04.2013

Is it possible?

Take consideration of month and years if they should be changed in respective.

there you go

date('d.m.Y',strtotime("-1 days"));

this will work also if month change

Yesterday Date in PHP:

echo date("Y-m-d", strtotime("yesterday")); 

try this

		$tz    = new DateTimeZone('Your Time Zone');
		$date  = new DateTime($today,$tz);
		$interval = new DateInterval('P1D');
		$date->sub($interval); 
		
		echo $date->format('d.m.y');
		
		?>	         
				

you can do this by

date("F j, Y", time() - 60 * 60 * 24);

or by

date("F j, Y", strtotime("yesterday"));

If you define the timezone in your PHP app (as you should), which you can do this way:

date_default_timezone_set('Europe/Paris');

Then it's as simple as:

$yesterday = new DateTime('yesterday'); // will use our default timezone, Paris
echo $yesterday->format('Y-m-d'); // or whatever format you want

(You may want to define a constant or environment variable to store your default timezone.)

Step 1

We need set format data in function date(): Function date() returns a string formatted according to the givenformat string using the given integer timestamp or the current time ifno timestamp is given. In other words, timestampis optional anddefaults to the value of time().

<?php
echo date("F j, Y");
?>

result: March 30, 2010

Step 2

For "yesterday" date use php function mktime(): Function mktime() returns the Unix timestamp corresponding to thearguments given. This timestamp is a long integer containing the numberof seconds between the Unix Epoch (January 1 1970 00:00:00 GMT) and thetime specified. Arguments may be left out in order from right to left; any argumentsthus omitted will be set to the current value according to the localdate and time.

<?php
echo mktime(0, 0, 0, date("m"), date("d")-1, date("Y"));
?>

result: 1269820800

Step 3

Now merge all and look at this:

<?php
$yesterday = date("Y-m-d", mktime(0, 0, 0, date("m") , date("d")-1,date("Y")));
echo $yesterday;
?>

result: March 29, 2010

Operating similarly, it is possible to receive time hour back.

<?php
$yesterday = date("H:i:s",mktime(date("H"), 0, 0, date("m"),date("d"), date("Y")));
echo $yesterday;
?>

result: 20:00:00

or 7 days ago:

<?php
$week = date("Y-m-d",mktime(0, 0, 0, date("m"), date("d")-7,date("Y")));
echo $week;
?>

result: 2010-03-23

Another OOP method for DateTime with setting the exact hour:

$yesterday = new DateTime("yesterday 09:00:59", new DateTimeZone('Europe/London'));
echo $yesterday->format('Y-m-d H:i:s') . "\n";

try this

<?php
$yesterday = date(“d.m.Y”, time()-86400);
echo $yesterday;

Most of the answers are in procedural/mixed style. Here is the solution in pure OOP style:

$today = new DateTime();
$yesterday = $today->sub(new DateInterval("P1D"));
echo $yesterday->format("d.m.Y");

It will take care of the daylight saving and timezone issues as well. Simple solution.

You can also do this using Carbon library:

Carbon::yesterday()->format('d.m.Y');         // '26.03.2019'

In other formats:

Carbon::yesterday()->toDateString();          // '2019-03-26'
Carbon::yesterday()->toDateTimeString();      // '2019-03-26 00:00:00'

Carbon::yesterday()->toFormattedDateString(); // 'Mar 26, 2019'
Carbon::yesterday()->toDayDateTimeString();   // 'Tue, Mar 26, 2019 12:00 AM'

We can use the Fancy method. Like this for yesterday. By today

$date = new DateTime; // example 2021-04-02
date_sub($date, date_interval_create_from_date_string('1 days')); 
$date = date_format($date, 'Y-m-d'); // Output will be 2021-04-01

Or we can find yesterday by a specific date like this.

$date = date_create('2021-04-06');
date_sub($date, date_interval_create_from_date_string('5 days'));
$date = date_format($date, 'Y-m-d'); // The output will be 2021-04-01

Create a function

function getYesterday()
{
    return \Carbon\Carbon::yesterday()->format('Y-m-d');
}

Call the function

getYesterday();