This particular timestamp is in milliseconds since the epoch, not the standard seconds since the epoch. Divide by 1000:

    $ date -d @1361234760.790
    Mon Feb 18 17:46:00 MST 2013

For Mac OS X, it&#39;s `date -r &lt;timestamp_in_seconds_with_no_fractions&gt;`
```
$ date -r 1553024528
Tue Mar 19 12:42:08 PDT 2019
```
or
```
$ date -r `expr 1553024527882 / 1000`
Tue Mar 19 12:42:07 PDT 2019
```
or
```
$ date -r $((1553024527882/1000))
Tue Mar 19 12:42:07 PDT 2019
```

You can use bash arithmetic expansion to perform the division:

    date -d @$((value/1000))

Note that &quot;`value`&quot; is a bash variable with the `$` being optional; i.e., `$value` or `value` can be used.

If an image on a separate server doesn&#39;t exist I&#39;d like to display a default image. Is there an angular directive to accomplish this?

Angular directive for a fallback image

I&#39;m trying to run this simple HelloWorld code written in Java from my browser ([Chrome][1]):

    public class HelloWorld extends JApplet {
    public void init() {
        try {
            SwingUtilities.invokeAndWait(new Runnable() {
                public void run() {
                    JLabel lbl = new JLabel(&quot;Hello World&quot;);
                    add(lbl);
                }
            });
        }
        catch (Exception e) {
            System.err.println(&quot;createGUI didn&#39;t complete successfully&quot;);
        }
    }

I compiled it with [NetBeans][2], and then I created a WebApplication project. The [HTML][3] code that runs the applet is:

    &lt;html&gt;
        &lt;head&gt;
            &lt;title&gt;&lt;/title&gt;
            &lt;meta http-equiv=&quot;Content-Type&quot; content=&quot;text/html; charset=UTF-8&quot;&gt;
        &lt;/head&gt;
        &lt;body&gt;
            &lt;p&gt;&lt;applet code=&quot;HelloWorld&quot; archive=&quot;applet_HelloWorld.jar&quot;  width=&quot;590&quot; height=&quot;530&quot;&gt;&lt;/applet&gt;&lt;/p&gt;
        &lt;/body&gt;
    &lt;/html&gt;

If run the applet from NetBeans it works. But when I run the HTML code by double clicking it, the following message pops up from the browser:

&gt; Your security settings have blocked a local application from running. 

I tried with Internet&amp;nbsp;Explorer and Firefox but nothing.

This message started to appear after the last update of Java. Where is the problem?

  [1]: http://en.wikipedia.org/wiki/Google_Chrome
  [2]: http://en.wikipedia.org/wiki/NetBeans
  [3]: http://en.wikipedia.org/wiki/HTML


Java Error: &quot;Your security settings have blocked a local application from running&quot;

How come date is converting to wrong time?

    result=$(ls /path/to/file/File.*)
    #/path/to/file/File.1361234760790

    currentIndexTime=${result##*.}
    echo &quot;$currentIndexTime&quot;
    #1361234760790

    date -d@&quot;$currentIndexTime&quot;
    #Tue 24 Oct 45105 10:53:10 PM GMT

Bash convert epoch to date, showing wrong time

How come date is converting to wrong time?
<pre><code class="hljs language-bash">result=$(ls /path/to/file/File.*)
#/path/to/file/File.1361234760790

currentIndexTime=${result##*.}
echo "$currentIndexTime"
#1361234760790

date -d@"$currentIndexTime"
#Tue 24 Oct 45105 10:53:10 PM GMT
</code></pre>

I have a number of lines retrieved from a file after running the [grep][1] command as follows:

    var=`grep xyz abc.txt`

Let’s say I got 10 lines which consists of xyz as a result.

Now I need to process each line I got as a result of the grep command. How do I proceed for this?

  [1]: http://linux.die.net/man/1/grep


How to process each output line in a loop?

Here is my problem: Any number of lines of text is given from standard input.
Output: number of non repeating lines

**INPUT:**

    She is wearing black shoes.
    My name is Johny.
    I hate mondays.
    My name is Johny.
    I don&#39;t understand you.
    She is wearing black shoes.

**OUTPUT:**

    2



Number of non repeating lines - unique count

I have two Bash scripts. The parent scripts calls the subscript to perform some actions and return a value. How can I return a value from the subscript to the parent script? Adding a `return` in the subscript and catching the value in the parent did not work.

Bash - Return value from subscript to parent script

I would like to do this in Bash:

- in the current directory, find the first folder that contains &quot;foo&quot; in the name

I&#39;ve been playing around with the find command, but a little confused. Any suggestions?

Use bash to find first folder name that contains a string

In a shell script, I want to download a file from some URL and save it to a specific folder. What is the specific CLI flag I should use to download files to a specific folder with the `curl` command, or how else do I get that result?


Save file to specific folder with curl command

I have a query like this:

    SELECT * FROM Cases WHERE created_at BETWEEN &#39;2013-05-01&#39; AND &#39;2013-05-01&#39;

But this gives no results even though there is data on the 1st.

`created_at` looks like `2013-05-01 22:25:19`, I suspect it has to do with the time? How could this be resolved?

It works just fine if I do larger date ranges, but it should (inclusive) work with a single date too.

SQL &quot;between&quot; not inclusive

Check if year is leap year in javascript

I wrote a function to get a current date and time in format: `DD-MM-YYYY HH:MM:SS`. It works but let&#39;s say, its pretty ugly. How can I do **exactly the same thing** but simpler?

    string currentDateToString()
    {
        time_t now = time(0);
        tm *ltm = localtime(&amp;now);
    
        string dateString = &quot;&quot;, tmp = &quot;&quot;;
        tmp = numToString(ltm-&gt;tm_mday);
        if (tmp.length() == 1)
            tmp.insert(0, &quot;0&quot;);
        dateString += tmp;
        dateString += &quot;-&quot;;
        tmp = numToString(1 + ltm-&gt;tm_mon);
        if (tmp.length() == 1)
            tmp.insert(0, &quot;0&quot;);
        dateString += tmp;
        dateString += &quot;-&quot;;
        tmp = numToString(1900 + ltm-&gt;tm_year);
        dateString += tmp;
        dateString += &quot; &quot;;
        tmp = numToString(ltm-&gt;tm_hour);
        if (tmp.length() == 1)
            tmp.insert(0, &quot;0&quot;);
        dateString += tmp;
        dateString += &quot;:&quot;;
        tmp = numToString(1 + ltm-&gt;tm_min);
        if (tmp.length() == 1)
            tmp.insert(0, &quot;0&quot;);
        dateString += tmp;
        dateString += &quot;:&quot;;
        tmp = numToString(1 + ltm-&gt;tm_sec);
        if (tmp.length() == 1)
            tmp.insert(0, &quot;0&quot;);
        dateString += tmp;
    
        return dateString;
    }

Current date and time as string

I can&#39;t seem to find how to print out the date of a file. I&#39;m so far able to print out all the files in a directory, but I need to print out the dates with it. 

I know I need to attach a date format with the echo of the entry, but all I can&#39;t find the correct format.

    echo &quot;Please type in the directory you want all the files to be listed&quot;
    
    read directory 
    
    for entry in &quot;$directory&quot;/*
    do
      echo &quot;$entry&quot;
    done



Print a file&#39;s last modified date in Bash

How to reduce one month from current date and want to sore in `java.util.Date` variable
im using this code but it&#39;s shows error in 2nd line

     java.util.Date da = new Date();
     da.add(Calendar.MONTH, -1); //error
How to store this date in `java.util.Date` variable?


How to reduce one month from current date and stored in date variable using java?

The statement gives me the date and time. 

How could I modify the statement so that it returns only the date (and not the time)?

    SELECT to_timestamp( TRUNC( CAST( epoch_ms AS bigint ) / 1000 ) );

PostgreSQL: how to convert from Unix epoch to date?

I have used a ruby script to convert iso time stamp to epoch, the files that I am parsing has following time stamp structure: 

    2009-03-08T00:27:31.807

Since I want to keep milliseconds I used following ruby code to convert it to epoch time: 

    irb(main):010:0&gt; DateTime.parse(&#39;2009-03-08T00:27:31.807&#39;).strftime(&quot;%Q&quot;)
    =&gt; &quot;1236472051807&quot;

But In python I tried following: 

    import time 
    time.strftime(&#39;%Y-%m-%d %H:%M:%S&#39;, time.gmtime(1236472051807))

But I don&#39;t get the original time date time back, 

    &gt;&gt;&gt; time.strftime(&#39;%Y-%m-%d %H:%M:%S&#39;, time.gmtime(1236472051807))
    &#39;41152-03-29 02:50:07&#39;
    &gt;&gt;&gt; 

I wonder is it related to how I am formatting? 

Converting epoch time with milliseconds to datetime

How do I extract the epoch value to `Long` from instances of `LocalDateTime` or `LocalDate`? I&#39;ve tried 
the following, but it gives me other results:

    LocalDateTime time = LocalDateTime.parse(&quot;04.02.2014  19:51:01&quot;, DateTimeFormatter.ofPattern(&quot;dd.MM.yyyy  HH:mm:ss&quot;));
    System.out.println(time.getLong(ChronoField.SECOND_OF_DAY)); // gives 71461
    System.out.println(time.getLong(ChronoField.EPOCH_DAY)); // gives 16105
What I want is simply the value `1391539861` for the local datetime `&quot;04.02.2014  19:51:01&quot;`.
My timezone is `Europe/Oslo` UTC+1 with daylight saving time.

How to extract epoch from LocalDate and LocalDateTime?

Java 8&#39;s `LocalDateTime` has an `ofEpochSecond` method. Unfortunately, there is no such method in the `ZonedDateTime`. Now, I have an Epoch value and an explicit `ZoneId` given. How do I get a `ZonedDateTime` out of these?

Java 8: How to create a ZonedDateTime from an Epoch value?

I have a sheet with a column of unix epoch times (in seconds): 1500598288

How can I convert these into normal dates?

Content Type	Original Author	Original Content on Stackoverflow
Question	bobbyrne01	View Question on Stackoverflow
Solution 1 - Bash	andrewdotn	View Answer on Stackoverflow
Solution 2 - Bash	Marcus	View Answer on Stackoverflow
Solution 3 - Bash	Richard Jessop	View Answer on Stackoverflow

Bash convert epoch to date, showing wrong time

Bash Problem Overview

Bash Solutions

Solution 1 - Bash

Solution 2 - Bash

Solution 3 - Bash

Java Error: "Your security settings have blocked a local application from running"

Angular directive for a fallback image

Attributions