How to get a random number between a float range?
PythonRandomFloating PointPython Problem Overview
randrange(start, stop) only takes integer arguments. So how would I get a random number between two float values?
Python Solutions
Solution 1 - Python
Use random.uniform(a, b):
>>> random.uniform(1.5, 1.9)
1.8733202628557872
Solution 2 - Python
if you want generate a random float with N digits to the right of point, you can make this :
round(random.uniform(1,2), N)
the second argument is the number of decimals.
Solution 3 - Python
random.uniform(a, b) appears to be what your looking for. From the docs:
> Return a random floating point number N such that a <= N <= b for a <= b and b <= N <= a for b < a.
See here.
Solution 4 - Python
From my experience dealing with python, I can only say that the random function can help in generating random float numbers. Take the example below;
import random
# Random float number between range 15.5 to 80.5
print(random.uniform(15.5, 80.5))
# between 10 and 100
print(random.uniform(10, 100))
The random.uniform() function returns a random floating-point number between a given range in Python
The two sets of code generates random float numbers. You can try experimenting with it to give you what you want.
Solution 5 - Python
Most commonly, you'd use:
import random
random.uniform(a, b) # range [a, b) or [a, b] depending on floating-point rounding
Python provides other distributions if you need.
If you have numpy imported already, you can used its equivalent:
import numpy as np
np.random.uniform(a, b) # range [a, b)
Again, if you need another distribution, numpy provides the same distributions as python, as well as many additional ones.