How to find average from array in php?

Example:

$a[] = '56';
$a[] = '66';
$a[] = '';
$a[] = '58';
$a[] = '85';
$a[] = '';
$a[] = '';
$a[] = '76';
$a[] = '';
$a[] = '57';

Actually how to find average value from this array excluding empty. please help to resolve this problem.

first you need to remove empty values, otherwise average will be not accurate.

so

$a = array_filter($a);
$average = array_sum($a)/count($a);
echo $average;

DEMO

More concise and recommended way

$a = array_filter($a);
if(count($a)) {
    echo $average = array_sum($a)/count($a);
}

See here

The accepted answer works for the example values, but in general simply using array_filter($a) is probably not a good idea, because it will filter out any actual zero values as well as zero length strings.

Even '0' evaluates to false, so you should use a filter that explicitly excludes zero length strings.

$a = array_filter($a, function($x) { return $x !== ''; });
$average = array_sum($a) / count($a);

echo array_sum($a) / count(array_filter($a));

As a late look, item controls should be done with numeric check. Otherwise something like this $array = [1.2, 0.33, [123]] will corrupt the calculation:

// Get numerics only.
$array = array_filter($array, fn($v) => is_numeric($v));

// Get numerics only where value > 0.
$array = array_filter($array, fn($v) => is_numeric($v) && ($v > 0));

Finally:

public static function average(array $array, bool $includeEmpties = true): float
{
    $array = array_filter($array, fn($v) => (
        $includeEmpties ? is_numeric($v) : is_numeric($v) && ($v > 0)
    ));

    return array_sum($array) / count($array);
}

Credits: froq.util.Arrays