How to convert JSON string to array
PhpArraysJsonPhp Problem Overview
What I want to do is the following:
- taking JSON as input from text area in php
- use this input and convert it to JSON and pass it to php curl to send request.
this m getting at php from get of api this json string i want to pass to json but it is not converting to array
echo $str='{
action : "create",
record: {
type: "n$product",
fields: {
n$name: "Bread",
n$price: 2.11
},
namespaces: { "my.demo": "n" }
}
}';
$json = json_decode($str, true);
the above code is not returning me array.
Php Solutions
Solution 1 - Php
If you pass the JSON in your post to json_decode, it will fail. Valid JSON strings have quoted keys:
json_decode('{foo:"bar"}'); // this fails
json_decode('{"foo":"bar"}', true); // returns array("foo" => "bar")
json_decode('{"foo":"bar"}'); // returns an object, not an array.
Solution 2 - Php
Try this:
$data = json_decode($your_json_string, TRUE);
the second parameter will make decoded json string into an associative arrays.
Solution 3 - Php
If you are getting the JSON string from the form using $_REQUEST, $_GET, or $_POST the you will need to use the function html_entity_decode(). I didn't realize this until I did a var_dump of what was in the request vs. what I copied into and echo statement and noticed the request string was much larger.
Correct Way:
$jsonText = $_REQUEST['myJSON'];
$decodedText = html_entity_decode($jsonText);
$myArray = json_decode($decodedText, true);
With Errors:
$jsonText = $_REQUEST['myJSON'];
$myArray = json_decode($jsonText, true);
echo json_last_error(); //Returns 4 - Syntax error;
Solution 4 - Php
Use json_decode($json_string, TRUE) function to convert the JSON object to an array.
Example:
$json_string = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
$my_array_data = json_decode($json_string, TRUE);
NOTE: The second parameter will convert decoded JSON string into an associative array.
===========
Output:
var_dump($my_array_data);
array(5) {
["a"] => int(1)
["b"] => int(2)
["c"] => int(3)
["d"] => int(4)
["e"] => int(5)
}
Solution 5 - Php
your string should be in the following format:
$str = '{"action": "create","record": {"type": "n$product","fields": {"n$name": "Bread","n$price": 2.11},"namespaces": { "my.demo": "n" }}}';
$array = json_decode($str, true);
echo "<pre>";
print_r($array);
Output:
Array
(
[action] => create
[record] => Array
(
[type] => n$product
[fields] => Array
(
[n$name] => Bread
[n$price] => 2.11
)
[namespaces] => Array
(
[my.demo] => n
)
)
)
Solution 6 - Php
If you are getting json string from URL using file_get_contents, then follow the steps:
$url = "http://localhost/rest/users"; //The url from where you are getting the contents
$response = (file_get_contents($url)); //Converting in json string
$n = strpos($response, "[");
$response = substr_replace($response,"",0,$n+1);
$response = substr_replace($response, "" , -1,1);
print_r(json_decode($response,true));
Solution 7 - Php
> There is a problem with the string you are calling a json. I have made some changes to it below. If you properly format the string to a correct json, the code below works.
$str = '{
"action" : "create",
"record": {
"type": "n$product",
"fields": {
"nname": "Bread",
"nprice": 2.11
},
"namespaces": { "my.demo": "n" }
}
}';
$response = json_decode($str, TRUE);
echo '<br> action' . $response["action"] . '<br><br>';
Solution 8 - Php
<?php
$str='{
"action" : "create",
"record" : {
"type": "$product",
"fields": {
"name": "Bread",
"price": "2.11"
},
"namespaces": { "my.demo": "n" }
}
}';
echo $str;
echo "<br>";
$jsonstr = json_decode($str, true);
print_r($jsonstr);
?>
i think this should Work, its just that the Keys should also be in double quotes if they are not numerals.
Solution 9 - Php
this my solution:
json string $columns_validation = string(1736) "[{"colId":"N_ni","hide":true,"aggFunc":null,"width":136,"pivotIndex":null,"pinned":null,"rowGroupIndex":null},{"colId":"J_2_fait","hide":true,"aggFunc":null,"width":67,"pivotIndex":null,"pinned":null,"rowGroupIndex":null}]"
so i use json_decode twice like that :
$js_column_validation = json_decode($columns_validation);
$js_column_validation = json_decode($js_column_validation);
var_dump($js_column_validation);
and the result is :
array(15) { [0]=> object(stdClass)#23 (7) { ["colId"]=> string(4) "N_ni" ["hide"]=> bool(true) ["aggFunc"]=> NULL ["width"]=> int(136) ["pivotIndex"]=> NULL ["pinned"]=> NULL ["rowGroupIndex"]=> NULL } [1]=> object(stdClass)#2130 (7) { ["colId"]=> string(8) "J_2_fait" ["hide"]=> bool(true) ["aggFunc"]=> NULL ["width"]=> int(67) ["pivotIndex"]=> NULL ["pinned"]=> NULL ["rowGroupIndex"]=> NULL }
Solution 10 - Php
Make sure that the string is in the following JSON format which is something like this:
{"result":"success","testid":"1"} (with " ") .
If not, then you can add "responsetype => json" in your request params.
Then use json_decode($response,true) to convert it into an array.
Solution 11 - Php
You can convert json Object into Array & String.
$data='{"resultList":[{"id":"1839","displayName":"Analytics","subLine":""},{"id":"1015","displayName":"Automation","subLine":""},{"id":"1084","displayName":"Aviation","subLine":""},{"id":"554","displayName":"Apparel","subLine":""},{"id":"875","displayName":"Aerospace","subLine":""},{"id":"1990","displayName":"Account Reconciliation","subLine":""},{"id":"3657","displayName":"Android","subLine":""},{"id":"1262","displayName":"Apache","subLine":""},{"id":"1440","displayName":"Acting","subLine":""},{"id":"710","displayName":"Aircraft","subLine":""},{"id":"12187","displayName":"AAC","subLine":""}, {"id":"20365","displayName":"AAT","subLine":""}, {"id":"7849","displayName":"AAP","subLine":""}, {"id":"20511","displayName":"AACR2","subLine":""}, {"id":"28585","displayName":"AASHTO","subLine":""}, {"id":"45191","displayName":"AAMS","subLine":""}]}';
$b=json_decode($data);
$i=0;
while($b->{'resultList'}[$i])
{
print_r($b->{'resultList'}[$i]->{'displayName'});
echo "<br />";
$i++;
}
Solution 12 - Php
If you want to convert to an object then:
$data = json_decode($yourJson);
if you want to convert to an array then:
$data = json_decode($yourJson,TRUE);
Solution 13 - Php
If you ever need to convert JSON file or structures to PHP-style arrays, with all the nesting levels, you can use this function. First, you must json_decode($yourJSONdata) and then pass it to this function. It will output to your browser window (or console) the correct PHP styled arrays.
Solution 14 - Php
Use this convertor , It doesn't fail at all: Services_Json
// create a new instance of Services_JSON
$json = new Services_JSON();
// convert a complexe value to JSON notation, and send it to the browser
$value = array('foo', 'bar', array(1, 2, 'baz'), array(3, array(4)));
$output = $json->encode($value);
print($output);
// prints: ["foo","bar",[1,2,"baz"],[3,[4]]]
// accept incoming POST data, assumed to be in JSON notation
$input = file_get_contents('php://input', 1000000);
$value = $json->decode($input);
// if you want to convert json to php arrays:
$json = new Services_JSON(SERVICES_JSON_LOOSE_TYPE);
Solution 15 - Php
You can change a string to JSON as follows and you can also trim, strip on string if wanted,
$str = '[{"id":1, "value":"Comfort Stretch"}]';
//here is JSON object
$filters = json_decode($str);
foreach($filters as $obj){
$filter_id[] = $obj->id;
}
//here is your array from that JSON
$filter_id;
Solution 16 - Php
<?php
$str='{
"action" : "create",
"record": {
"type": "n$product",
"fields": {
"n$name": "Bread",
"n$price": 2.11
},
"namespaces": { "my.demo": "n" }
}
}';
$json = json_decode($str,true);
echo '<pre>';
print_r($json);
this should Work,just that the Keys should also be in double quotes if they are not numerals.
output:-
Array
(
[action] => create
[record] => Array
(
[type] => n$product
[fields] => Array
(
[n$name] => Bread
[n$price] => 2.11
)
[namespaces] => Array
(
[my.demo] => n
)
)
)
It will convert Json String To Array
Solution 17 - Php
$data = json_encode($result, true);
echo $data;