How to compare two dates in php
PhpPhp Problem Overview
How to compare two dates in php if dates are in format '03_01_12' and '31_12_11' .
I am using this code:
$date1=date('d_m_y');
$date2='31_12_11';
if(strtotime($date1) < strtotime($date2))
echo '1 is small ='.strtotime($date1).','.$date1;
else
echo '2 is small ='.strtotime($date2).','.$date2;
But its not working..
Php Solutions
Solution 1 - Php
You will have to make sure that your dates are valid date objects.
Try this:
$date1=date('d/m/y');
$tempArr=explode('_', '31_12_11');
$date2 = date("d/m/y", mktime(0, 0, 0, $tempArr[1], $tempArr[0], $tempArr[2]));
You can then perform the strtotime() method to get the difference.
Solution 2 - Php
Using DateTime::createFromFormat:
$format = "d_m_y";
$date1 = \DateTime::createFromFormat($format, "03_01_12");
$date2 = \DateTime::createFromFormat($format, "31_12_11");
var_dump($date1 > $date2);
Solution 3 - Php
Not answering the OPs actual problem, but answering just the title. Since this is the top result for "comparing dates in php".
Pretty simple to use Datetime Objects (php >= 5.3.0) and Compare them directly
$date1 = new DateTime("2009-10-11");
$date2 = new DateTime("tomorrow"); // Can use date/string just like strtotime.
var_dump($date1 < $date2);
Solution 4 - Php
The date_diff() function returns the difference between two DateTime objects.
If the first date is before the second date a positive number of days will be returned; otherwise a negative number of days:
<?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
?>
output will be "+272 days" ;
changing $date1 = "2014-03-15"
<?php
$date1=date_create("2014-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
?>
Output will be "-93 days"
Solution 5 - Php
<?php
$expiry_date = "2017-12-31 00:00:00"
$today = date('d-m-Y',time());
$exp = date('d-m-Y',strtotime($expiry_date));
$expDate = date_create($exp);
$todayDate = date_create($today);
$diff = date_diff($todayDate, $expDate);
if($diff->format("%R%a")>0){
echo "active";
}else{
echo "inactive";
}
echo "Remaining Days ".$diff->format("%R%a days");
?>
Solution 6 - Php
Extending @nevermind's answer, one can use DateTime::createFromFormat: like,
// use - instead of _. replace _ by - if needed.
$format = "d-m-y";
$date1 = DateTime::createFromFormat($format, date('d-m-y'));
$date2 = DateTime::createFromFormat($format, str_replace("_", "-",$date2));
var_dump($date1 > $date2);
Solution 7 - Php
you can try something like:
$date1 = date_create('2014-1-23'); // format of yyyy-mm-dd
$date2 = date_create('2014-2-3'); // format of yyyy-mm-dd
$dateDiff = date_diff($date1, $date2);
var_dump($dateDiff);
You can then access the difference in days like this $dateDiff->d;
Solution 8 - Php
Don't know what your problem is but:
function date_compare($d1, $d2)
{
$d1 = explode('_', $d1);
$d2 = explode('_', $d2);
$d1 = array_reverse($d1);
$d2 = array_reverse($d2);
if (strtotime(implode('-', $d1)) > strtotime(implode('-', $d2)))
{
return $d2;
}
else
{
return $d1;
}
}
Solution 9 - Php
Try this
$data1 = strtotime(\date("d/m/Y"));
$data1 = date_create($data1);
$data2 = date_create("21/06/2017");
if($data1 < $data2){
return "The most current date is date1";
}
return "The most current date is date2";
Solution 10 - Php
compare the result of maketime() for each of the time
Solution 11 - Php
I know this is late, but for future reference, put the date format into a recognised format by using str_replace then your function will work. (replace the underscore with a dash)
//change the format to dashes instead of underscores, then get the timestamp
$date1 = strtotime(str_replace("_", "-",$date1));
$date2 = strtotime(str_replace("_", "-",$date2));
//compare the dates
if($date1 < $date2){
//convert the date back to underscore format if needed when printing it out.
echo '1 is small='.$date1.','.date('d_m_y',$date1);
}else{
echo '2 is small='.$date2.','.date('d_m_y',$date2);
}
Solution 12 - Php
You can to converte for integer number and compare.
Eg.:
$date_1 = date('Ymd');
$date_2 = '31_12_2011';
$date_2 = (int) implode(array_reverse(explode("_", $date_2)));
echo ($date_1 < $date_2) ? '$date_2 is bigger then $date_1' : '$date_2 is smaller than $date_1';
Solution 13 - Php
benchmark comparison date_create, strtotime, DateTime, and direct
direct is faster
$f1="2014-12-12";
$f2="2014-12-13";
$diff=false;
$this->bench('a');
for ($i=0; $i < 20000; $i++) {
$date1=date_create($f1);
$date2=date_create($f2);
$diff=date_diff($date1,$date2);
}
$this->bench('a','b');
for ($i=0; $i < 20000; $i++) {
$date1=strtotime($f1);
$date2=strtotime($f2);
if ($date1>$date2) {
$diff=true;
}
}
$this->bench('b','c');
for ($i=0; $i < 20000; $i++) {
$date1 = new DateTime($f1);
$date2 = new DateTime($f2);
if ($date1>$date2) {
$diff=true;
}
}
$diff=false;
$this->bench('c','d');
for ($i=0; $i < 20000; $i++) {
if ($f1>$f2) {
$diff=true;
}
}
$this->bench('d','e');
var_dump($diff);
$this->dumpr($this->benchs);
results:
[a] => 1610415241.4687
[b] => 1610415242.8759
[a-b] => 1.407194852829
[c] => 1610415243.5672
[b-c] => 0.69137716293335
[d] => 1610415244.7036
[c-d] => 1.1363649368286
[e] => 1610415244.7109
[d-e] => 0.0073208808898926
Solution 14 - Php
I think this one is very simple function
function terminateOrNotStringtoDate($currentDate, $terminationdate)
{
$crtDate = new DateTime($currentDate);
$termDate = new DateTime($terminationdate);
if($crtDate >= $termDate)
{
return true;
} else {
return false;
}
}
Solution 15 - Php
Guys Please don't make it so complex The simple answer bellow
$date1=date('d_m_y');
$date2='31_12_11';
$date1=str_replace('_', '-', $date1);
$date2=str_replace('_', '-', $date2)
if(strtotime($date1) < strtotime($date2))
echo '1 is small ='.strtotime($date1).','.$date1;
else
echo '2 is small ='.strtotime($date2).','.$date2;
I just have added two more lines with your code
Solution 16 - Php
If both dates are in the same format then use a comparison operator.
$date1 = "2018-05-05";
$date2 = "2019-08-19";
//comparison operator to
if ($date1 > $date2) {
echo "$date1 is latest than $date2";
}
else{
echo "$date1 is older than $date2";
}
Output: 2018-05-05 is older than 2019-08-19