How does the new Docker --squash work

DockerDockerfileSquash

Docker Problem Overview


In Docker 1.13 the new --squash parameter was added.

I'm now hoping to reduce the size of my images as well as being able to "hide" secret files I have in my layers.

Below you can now see the difference from doing a build with and without the --squash parameter.

Without Squash

enter image description here

With Squash

enter image description here

Now to my question.

If I add a secret file in my first layer, then use the secret file in my second layer, and the finally remove my secret file in the third layer, and then build with the --squash flag.

Will there be any way now to get the secret file?

Docker Solutions


Solution 1 - Docker

> If I add a secret file in my first layer, then use the secret file in > my second layer, and the finally remove my secret file in the third > layer, and then build with the --squash flag. > > Will there be any way now to get the secret file?

Answer: Your image won't have the secret file.

How --squash works:

Once the build is complete, Docker creates a new image loading the diffs from each layer into a single new layer and references all the parent's layers.

In other words: when squashing, Docker will take all the filesystem layers produced by a build and collapse them into a single new layer.

This can simplify the process of creating minimal container images, but may result in slightly higher overhead when images are moved around (because squashed layers can no longer be shared between images). Docker still caches individual layers to make subsequent builds fast.

Please note this feature squashes all the newly built layers into a single layer, it is not squashing to scratch.

Side notes:

Docker 1.13 also has support for compressing the build context that is sent from CLI to daemon using the --compress flag. This will speed up builds done on remote daemons by reducing the amount of data sent.

Please note as of Docker 1.13 this feature is experimental.

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Solution 1 - DockerFarhad FarahiView Answer on Stackoverflow