You want: 

    grep -A 5 &#39;19:55&#39; file

From `man grep`:

    Context Line Control
 
    -A NUM, --after-context=NUM
   
    Print NUM lines of trailing context after matching lines.  
    Places a line containing a gup separator (described under --group-separator) 
    between contiguous groups of matches.  With the -o or --only-matching
    option, this has no effect and a warning is given.
    
    -B NUM, --before-context=NUM
   
    Print NUM lines of leading context before matching lines.  
    Places a line containing a group separator (described under --group-separator) 
    between contiguous groups of matches.  With the -o or --only-matching
    option, this has no effect and a warning is given.
    
    -C NUM, -NUM, --context=NUM
    
    Print NUM lines of output context.  Places a line containing a group separator
    (described under --group-separator) between contiguous groups of matches.  
    With the -o or --only-matching option,  this  has  no effect and a warning
    is given.
    
    --group-separator=SEP
    
    Use SEP as a group separator. By default SEP is double hyphen (--).
    
    --no-group-separator

    Use empty string as a group separator.



Some `awk` version.

    awk &#39;/19:55/{c=5} c--&gt;0&#39;
    awk &#39;/19:55/{c=5} c &amp;&amp; c--&#39;

When pattern found, set `c=5`&lt;br&gt;
If `c` is true, print and decrease number of `c`

Here is a sed solution:

    sed &#39;/19:55/{
    N
    N
    N
    N
    N
    s/\n/ /g
    }&#39; file.txt



can any one give me a a simple example of nodeJs callbacks, I have already searched for the same on many websites but not able to understand it properly, Please give me a simple example.

    getDbFiles(store, function(files){
        getCdnFiles(store, function(files){
        })
    })

I want to do something like that...

nodeJs callbacks simple example

I have an app in Google Play Store. When an update version is available, the older version will become unusable – that is, if users do not update the app, they do not enter in the app. How can I force users to update the app when a new version becomes available?

Force update of an Android app when a new version is available

How do I `grep` a file for `19:55` and get the Line 1,2,3,4,5?

    2013/10/08 19:55:27.471
    Line 1
    Line 2
    Line 3
    Line 4
    Line 5

    2013/10/08 19:55:29.566
    Line 1
    Line 2
    Line 3
    Line 4
    Line 5



How do you grep a file and get the next 5 lines

How do I <code>grep</code> a file for <code>19:55</code> and get the Line 1,2,3,4,5?
<pre><code class="hljs language-yaml">2013/10/08 19:55:27.471
Line 1
Line 2
Line 3
Line 4
Line 5

2013/10/08 19:55:29.566
Line 1
Line 2
Line 3
Line 4
Line 5
</code></pre>

I have an ansible task which creates a new user on ubuntu 12.04;
  

    - name: Add deployment user
        action: user name=deployer password=mypassword

it completes as expected but when I login as that user and try to sudo with the password I set it always says it&#39;s incorrect. What am I doing wrong?

Creating a new user and password with Ansible

I am trying to get a specific line from a text file.

So far, online I have only seen stuff like sed, (I can only use the sh -not bash or sed or anything like that). I need to do this only using a basic shell script.

    cat file | while read line
    	do
    	   #do something
    	done

I know how to iterate through lines, as shown above, but what if I just need to get the contents of a particular line


Get specific line from text file using just shell script

I am trying to run this script in PowerShell. I have saved the below script as `ps.ps1` on my desktop.

    $query = &quot;SELECT * FROM Win32_DeviceChangeEvent WHERE EventType = 2&quot;
    Register-WMIEvent -Query $query -Action { invoke-item &quot;C:\Program Files\abc.exe&quot;}

I have made a batch script to run this PowerShell script

    @echo off
    Powershell.exe set-executionpolicy remotesigned -File  C:\Users\SE\Desktop\ps.ps1
    pause

But I am getting this error:

![Enter image description here][1]

  [1]: http://i.stack.imgur.com/i2473.png


How to run a PowerShell script from a batch file

I have a new Ubuntu 12.04 VPS. I am trying to write a setup script that completes an entire LAMP installation. Where I am having trouble is appending a line to the `/etc/hosts` file. My current hosts file looks like this:

    127.0.0.1       localhost Venus

    # The following lines are desirable for IPv6 capable hosts
    ::1     ip6-localhost ip6-loopback
    fe00::0 ip6-localnet
    ff00::0 ip6-mcastprefix
    ff02::1 ip6-allnodes
    ff02::2 ip6-allrouters

I would like it to look like this:

    127.0.0.1       localhost Venus
    192.241.xx.xx  venus.example.com venus

    # The following lines are desirable for IPv6 capable hosts
    ::1     ip6-localhost ip6-loopback
    fe00::0 ip6-localnet
    ff00::0 ip6-mcastprefix
    ff02::1 ip6-allnodes
    ff02::2 ip6-allrouters

I have tried a variety of `sed` commands using the append (`\a`) command. For some reason Ubuntu either just echoes the contents of the `hosts` file in terminal or does nothing at all. How would I properly inject the second line into the file with a bash script?

Append line to /etc/hosts file with shell script

Is there some sort of character limit imposed in bash (or other shells) for how long an input can be? If so, what is that character limit?

I.e. Is it possible to write a command in bash that is too long for the command line to execute?
If there is not a required limit, is there a suggested limit? 

Bash command line and input limit

How do you grep and only return the matching line? i.e. The path/filename is omitted from the results.

In this case I want to look in all .bar files in the current directory, searching for the term FOO

    find . -name &#39;*.bar&#39; -exec grep -Hn FOO {} \;

grep without showing path/file:line

Now I want to find whether there are lines containing &#39;\&#39; character. I tried `grep &quot;\\&quot; XXFile` but it hints &quot;Trailing Backslash&quot;. But when I tried `grep &#39;\\&#39; XXFile` it is OK. Could anyone explain why the first case cannot run? Thanks.

When grep &quot;\\&quot; XXFile I got &quot;Trailing Backslash&quot;

I want to delete all files which have names containing a specific word, e.g. &quot;car&quot;.
So far, I came up with this:

    find|grep car
How do I pass the output to rm?

Delete a list of files with find and grep

With a `find` command, I can display directories names with multiple levels. The following command display all directories under `/var` path with a depth of 2:

    find /var -maxdepth 2 -type d;

The result shows:

    /var
    /var/log
    /var/log/sssd
    /var/log/samba
    /var/log/audit
    /var/log/ConsoleKit
    /var/log/gdm
    /var/log/sa

With a `stat` command, I can find the modified date time:

    stat /var/log/samba | grep &#39;Modify:&#39;

The result is:

    Modify: 2014-01-02 11:21:27.762346214 -0800 

Is there a way to combine the two commands so that directories will be listed with modified date time?

How to display modified date time with &#39;find&#39; command?

I want to `grep -R` a directory but exclude symlinks how dow I do it?

Maybe something like `grep -R --no-symlinks` or something?

Thank you.

Content Type	Original Author	Original Content on Stackoverflow
Question	Leandro Toshio Takeda	View Question on Stackoverflow
Solution 1 - Shell	Chris Seymour	View Answer on Stackoverflow
Solution 2 - Shell	Jotne	View Answer on Stackoverflow
Solution 3 - Shell	Jason	View Answer on Stackoverflow

How do you grep a file and get the next 5 lines

Shell Problem Overview

Shell Solutions

Solution 1 - Shell

Solution 2 - Shell

Solution 3 - Shell

Force update of an Android app when a new version is available

nodeJs callbacks simple example

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